a)\(\left(-3\right)^{x+3}=-\frac{1}{27}\)

\(\left(-3\right)^{x+3}=\left(-\frac{1}{3}\right)^3\)

\(\left(-3\right)^{x+3}=\left(-\frac{3^0}{3^1}\right)^3\)

\(\left(-3\right)^{x+3}=\left(-3^{-1}\right)^3\)

\(\left(-3\right)^{x+3}=\left(-3\right)^{-3}\)

\(\Rightarrow x+3=-3\)

\(\Rightarrow x=-6\)

b)\(\left(-6\right)^{2x+2}=\frac{1}{36}\)

\(\left(-6\right)^{2x+2}=\left(-\frac{1}{6}\right)^2\)

\(\left(-6\right)^{2x+2}=\left(-\frac{6^0}{6^1}\right)^2\)

\(\left(-6\right)^{2x+2}=\left(-6^{-1}\right)^2\)

\(\left(-6\right)^{2x+2}=\left(-6\right)^{-2}\)

\(\Rightarrow2x+2=-2\)

\(\Rightarrow2x=-4\)

\(\Rightarrow x=-2\)

c)\(\left(-3\right)^{x+5}=\frac{1}{81}\)

\(\left(-3\right)^{x+5}=\left(-\frac{1}{3}\right)^4\)

\(\left(-3\right)^{x+5}=\left(-\frac{3^0}{3^1}\right)^4\)

\(\left(-3\right)^{x+5}=\left(-3^{-1}\right)^4\)

\(\left(-3\right)^{x+5}=\left(-3\right)^{-4}\)

\(\Rightarrow x+5=-4\)

\(\Rightarrow x=-9\)

d)\(\left(\frac{1}{9}\right)^x=\left(\frac{1}{27}\right)^6\)

\(\left[\left(\frac{1}{3}\right)^2\right]^x=\left[\left(\frac{1}{3}\right)^3\right]^6\)

\(\left(\frac{1}{3}\right)^{2x}=\left(\frac{1}{3}\right)^{18}\)

\(\Rightarrow2x=18\)

\(\Rightarrow x=9\)

e)\(\left(\frac{4}{9}\right)^x=\left(\frac{8}{27}\right)^6\)

\(\left[\left(\frac{2}{3}\right)^2\right]^x=\left[\left(\frac{2}{3}\right)^3\right]^6\)

\(\left(\frac{2}{3}\right)^{2x}=\left(\frac{2}{3}\right)^{18}\)

\(\Rightarrow2x=18\)

\(\Rightarrow x=9\)

f)\(5^{x+4}-3\cdot5^{x+3}=2\cdot5^{11}\)

\(5^{x+3}\cdot5-3\cdot5^{x+3}=2\cdot5^{11}\)

\(5^{x+3}\left(5-3\right)=2\cdot5^{11}\)

\(5^{x+3}\cdot2=2\cdot5^{11}\)

\(\Rightarrow5^{x+3}=5^{11}\)

\(\Rightarrow x+3=11\)

\(\Rightarrow x=8\)

r)\(4\cdot3^{x-1}+2\cdot3^{x+2}=4\cdot3^6+2\cdot3^9\)

\(4\cdot3^x:3+2\cdot3^x\cdot9=4.3^7:3+2\cdot3^7\cdot9\)

\(3^x\left(4:3+2\cdot9\right)=3^7\left(4:3+2\cdot9\right)\)

\(\Rightarrow3^x=3^7\)

\(\Rightarrow x=7\)

a, => 2^x = (2^3)^4/(2^4)^3 = 2^12/2^12 = 1 = 2^0

=> x = 0

c, => 4^x = 4^10.(4-3) = 4^10

=> x=10

d, => 2^2.3^x-1 + 2.3^x.9 = 2^2.3^6+2.3^9

=> 2.3^x-1 . (2+3.9) = 2.3^6.(2+3^3)

=> 2.3^x-1 . 27 = 2.3^6 . 27

=> 3^x-1 = 3^6

=> x-1 = 6

=> x = 7

e, => 2^x.(1/3+1/6+2) = 2^11.(2+1/2)

=> 2^x. 5/2 = 2^11. 5/2

=> 2^x = 2^11

=> x = 11

Tk mk nha

câu b) chưa có ai làm thì mình làm nốt vậy 

\(\left(-2\right)^2=-4^6-8^5\)

\(\left(-2\right)^x=-4096-32768\)

\(\left(-2\right)^x=-36864\)

\(\Rightarrow x\) sẽ 1 số thập phân nào đó 

\(5^{x+4}-3.5^{x+3}=2.5^{11}\)

\(5^{x+3}\left(5-3\right)=2.5^{11}\)

\(5^{x+3}.2=2.5^{11}\)

\(5^{x+3}=5^{11}\)

\(x+3=11\)

\(x=8\)

\(4^{x+3}-3.4^{x+1}=13.4^{11}\)

\(4^{x+1}\left(4^2-3\right)=13.4^{11}\)

\(4^{x+1}.13=13.4^{11}\)

\(4^{x+1}=4^{11}\)

\(x+1=11\)

\(x=10\)

ai nhanh nhất mà trả lời dúng mik tặng 3 k

Bài 2 

| x - \(\frac{1}{3}\)| + \(\frac{4}{5}\)= | ( -3,2) + \(\frac{2}{5}\)|

=> | x - \(\frac{1}{3}\)| + \(\frac{4}{5}\)= | -2,8|

=> | x - \(\frac{1}{3}\)| + \(\frac{4}{5}\)= -2,8

=> | x - \(\frac{1}{3}\)| = -2,8 - \(\frac{4}{5}\)

=> | x - \(\frac{1}{3}\)| = - 3,6

=> x - \(\frac{1}{3}\)= -3,6

=> x = -3,6 + \(\frac{1}{3}\)

=> x = \(\frac{-49}{15}\)

Bài 3 :

Áp dụng tính chất dãy tỉ số bằng nhau ta có :

\(\frac{a_1-1}{9}=\frac{a_2-2}{8}=...=\frac{a_9-9}{1}=\frac{a_1-1+a_2-2+...+a_9-9}{9+8+...+1}\)

\(=\frac{\left[a_1+a_2+...+a_9\right]-\left[1+2+...+9\right]}{9+8+...+1}=\frac{90-45}{45}=1\)

Ta có : \(\frac{a_1-1}{9}=1\Rightarrow a_1=10\)

Tương tự : \(a_1=a_2=....=a_9=10\)

1, Đặt \(A=\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)

\(A=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)\(A=\frac{2^{28}\left(5.2^2.3^{18}-2.3^{20}\right)}{2^{28}\left(5.3^{19}-7.2.3^{18}\right)}\)

\(A=\frac{5.2^2.3^{18}-2.3^{20}}{5.3^{19}-7.2.3^{18}}\)\(A=\frac{3^{18}\left(5.2^2-2.3^2\right)}{3^{18}\left(5.3-7.2\right)}\)

\(A=\frac{5.2^2-2.3^2}{5.3-7.2}\)\(A=2\)

Đây là lớp 8 nha các b giúp mk với

Do mk viết nhầm