`a, = 5^3 xx 3^3 = 15^3`

`b, = 12^3 xx 4^3 = 48^3`

`c, = 625^3 xx 8^3 = 5000^3`

`d, = 625 ^3 xx 125^3 = 78125^3`

`e, = 5^20 : 5^14 = 5^6`

1,\(125\cdot27=5^3\cdot3^3=\left(5\cdot3\right)^3=15^3\)

2, \(12^3\cdot64=12^3\cdot4^3=\left(12\cdot4\right)^3=48^3\)

3, \(25^6\cdot8^3=\left(5^2\right)^6\cdot\left(2^3\right)^3=5^8\cdot2^9\)

4, \(25^6\cdot125^3=\left(5^2\right)^3\cdot\left(5^3\right)^3=5^6\cdot5^9=5^{15}\)

5,\(625^5:25^7=\left(5^4\right)^5:\left(5^2\right)^7=5^{20}:5^{14}=5^6\)

a) \(x^5\cdot x^3\cdot x^2=x^{5+3+2}=x^{10}\)

b) \(\left(0,2\right)^8:0,04=\left(0,2\right)^8:\left(0,2\right)^2=\left(0,2\right)^{8-2}=\left(0,2\right)^6\)

CHÚC BẠN HỌC TỐT!!!!!!!!!!!

a)x^5.x^3.x^2=x^5+3+2=x^10

b)0,2^8:0,04=0,2^8:0,2^2=0,2^8-2=0,2^6

a: \(=\dfrac{2^6\cdot3^3}{3^{-4}\cdot2^6}=\dfrac{3^3}{3^{-4}}=3^7\)

c: \(=5^4\cdot5^3\cdot\left(\dfrac{5}{2}\right)^{-5}\cdot\dfrac{4}{100}\)

\(=5^7\cdot\left(\dfrac{2}{5}\right)^5\cdot\left(\dfrac{1}{5}\right)^2\)

\(=5^2\cdot\left(\dfrac{1}{5}\right)^2\cdot5^5\cdot\left(\dfrac{2}{5}\right)^5=2^5\)

3 mũ mấy bạn eiiii

6:=(3/2)*(3/2)^2*(3/2)^4=(3/2)^7

7: =(1/2)^7*2^3*2^5*2^8=2^9

8: =(-1/7)^4*5^4=(-5/7)^4

9: =2^2*2^5:(2^3/2^4)

=2^7/2=2^6

10: =(1/7)^3*7^2=1/7

\(27\cdot5^3\cdot3^3\cdot32^{-1}:125=3^3\cdot5^3\cdot3^3\cdot\dfrac{1}{32}:5^3=\dfrac{3^6}{32}=\dfrac{3^6}{2^5}\)

b: \(3^4\cdot3^5:\dfrac{1}{27}==3^9\cdot3^3=3^{12}\)