(x . 3 ) : 4 =11
-4/3 - 5/7 + 4/3 3/13 x 6/11 + 3/13 x 9/11 - 3/13 x 4/11
\(\dfrac{-4}{3}-\dfrac{5}{7}+\dfrac{4}{3}=\left(\dfrac{4}{3}+\dfrac{-4}{3}\right)-\dfrac{5}{7}=0-\dfrac{5}{7}=-\dfrac{5}{7}\)
\(\dfrac{3}{13}\cdot\dfrac{6}{11}+\dfrac{3}{13}\cdot\dfrac{9}{11}-\dfrac{3}{13}\cdot\dfrac{4}{11}=\dfrac{3}{13}\cdot\left(\dfrac{6}{11}+\dfrac{9}{11}-\dfrac{4}{11}\right)=\dfrac{3}{13}\cdot1=\dfrac{3}{13}\)
a ) 4 . 3^x-1 + 2 . 3^x+2 = 4 . 3^6 + 2 . 3^9
b ) 5^x+4 - 3 . 5^x+3 = 2 . 5^11
c ) 11 . 6^x-1 = 11 . 6^11 + 2 . 6^13
\(4.3^{x-1}+2.3^{x+2}=4.3^6+2.3^9\)
\(3^{x-1}.\left(4+2.3^3\right)=3^6.\left(4+2.3^3\right)\)
\(\Leftrightarrow3^{x-1}=3^6\)
\(\Leftrightarrow x-1=6\)
\(\Leftrightarrow x=7\)
Vậy \(x=7\)
\(5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(\Leftrightarrow5^{x+3}.\left(5-3\right)=2.5^{11}\)
\(\Leftrightarrow5^{x+3}.2=2.5^{11}\)
\(\Leftrightarrow5^{x+3}=5^{11}\)
⇔\(x+3=11\)
\(\Leftrightarrow x=8\)
Vậy \(x=8\)
\(11.6^{x-1}=11.6^{11}+2.6^{13}\)
\(\Rightarrow11.6^{x-1}=6^{11}.\left(11+2.36\right)\)
\(\Rightarrow11.6^{x-1}=6^{11}.83\)
Timf `x`:
`(x - 2)/3 = (x + 1)/4`
`(x - 2) . 4 = (x + 1) . 3`
`<=> 4x - 8 = 3x + 3`
`<=> 4x - 3x = 3 + 8`
`<=> (4 - 3)x = 11`
`=> x = 11`
`(x - 2)/3 = (x + 1)/4`
`(x - 2) . 4 = (x + 1) . 3`
`<=> 4x - 8 = 3x + 3`
`<=> 4x - 3x = 3 + 8`
`<=> (4 - 3)x = 11`
`=> x = 11`
`=>` `x = 11`
Bài 1 Tìm x,biết
x.3/5=2/3
x.7/17=17/8
3/4 chia x=-7/12
3/8 - 1/6.x=1/4
1/3+1/2 chia x=-4
Bài 2 Tính
-6/11 chia [3/5 . 4/11]
7/12 + 5/12 chia 6 -11/36
[4/5 + 1/2] chia [3/13 - 8/13]
[2/3 - 1/4 + 5/11] chia [5/12 + 1 -7/11]
*Dấu . là dấu nhân nha mn*
Bài 1:
a: \(x=\dfrac{2}{3}:\dfrac{3}{5}=\dfrac{2}{3}\cdot\dfrac{5}{3}=\dfrac{10}{9}\)
b: \(x=\dfrac{17}{8}:\dfrac{7}{17}=\dfrac{17}{8}\cdot\dfrac{17}{7}=\dfrac{289}{56}\)
c: \(x=-\dfrac{3}{4}:\dfrac{7}{12}=\dfrac{-3}{4}\cdot\dfrac{12}{7}=\dfrac{-63}{28}=-\dfrac{9}{4}\)
d: \(\Leftrightarrow x\cdot\dfrac{1}{6}=\dfrac{3}{8}-\dfrac{1}{4}=\dfrac{1}{4}\)
hay \(x=\dfrac{1}{4}:\dfrac{1}{6}=\dfrac{3}{2}\)
e: \(\Leftrightarrow\dfrac{1}{2}:x=-4-\dfrac{1}{3}=-\dfrac{17}{3}\)
hay \(x=-\dfrac{1}{2}:\dfrac{17}{3}=\dfrac{-3}{34}\)
tính nhanh : -3/4 x 2/11 + -3/4 x 9/11+ -3/4
a, x.2 + x.5 = 14 b, x.9 + x = 20
c, x: \(\dfrac{3}{2}\) + x.\(\dfrac{1}{3}\) = 1999 d,11.(x+2) = 5.x + 40
e, 11.(x-6) = 4.x + 11 f, (3.x - 4) : x + 10 = 12
g, (5.x + 7) : x + 20 = 26 h, x.1999 - x = 1999.1997 + 1999
***dấu chấm(.) = dấu nhân(x)***
a) \(...\Rightarrow x.\left(2+5\right)=14\Rightarrow x.7=14\Rightarrow x=14:7=2\)
b) \(...\Rightarrow x.\left(9+1\right)=20\Rightarrow x.10=20\Rightarrow x=20:10=2\)
c) \(...\Rightarrow x.\left(\dfrac{2}{3}+\dfrac{1}{3}\right)=1999\Rightarrow x.\dfrac{3}{3}=1999\Rightarrow x=1999\)
d) \(...\Rightarrow11.x+22=5.x+40\Rightarrow11.x-5.x=40-22\Rightarrow6.x=18\Rightarrow x=18:6=3\)
e) \(...\Rightarrow11.x-66=4.x+11\Rightarrow11.x-4.x=11+66\Rightarrow7.x=77\Rightarrow x=77:7=11\)
f) \(...\Rightarrow\left(3.x-12\right):x=12-10\)
\(\Rightarrow3.x-12=2.x\)
\(\Rightarrow3.x-2.x=12\)
\(\Rightarrow x=12\)
g) \(...\Rightarrow\left(5.x+7\right):x=26-20\)
\(\Rightarrow5.x+7=6.x\)
\(\Rightarrow6.x-5.x=7\)
\(\Rightarrow x=7\)
h) \(...\Rightarrow x.\left(1999-1\right)=1999.\left(1997+1\right)\)
\(\Rightarrow x.1998=1999.1998\)
\(\Rightarrow x=1999.1998:1998\)
\(\Rightarrow x=1999\)
a, \(x\times\) 2 + \(x\times\) 5 = 14
\(x\) \(\times\) ( 2 + 5) = 14
\(x\) \(\times\) 7 = 14
\(x\) = 14: 7
\(x\) = 2
b, \(x\times9\) + \(x\)= 20
\(x\) \(\times\)( 9 + 1) = 20
\(x\) \(\times\) 10 = 20
\(x\) = 2
c, \(x\) : \(\dfrac{3}{2}\) + \(x\times\dfrac{1}{3}\) = 1999
\(x\times\) \(\dfrac{2}{3}\) + \(x\) \(\times\dfrac{1}{3}\) = 1999
\(x\times\) ( \(\dfrac{2}{3}\) + \(\dfrac{1}{3}\)) = 1999
\(x\) = 1999
d, 11\(\times\)(\(x+2\)) = 5 \(\times\) \(x\) + 40
11 \(\times\) \(x\) + 22 = 5 \(\times\) \(x\) + 40
11 \(\times\) \(x\) = 5 \(\times\) \(x\) + 40 - 22
11 \(\times\) \(x\) = 5 \(\times\) \(x\) + 18
11 \(\times\) \(x\) - 5 \(\times\) \(x\) = 18
\(x\) \(\times\) ( 11 - 5) = 18
\(x\) \(\times\) 6 = 18
\(x\) = 3
e, 11 \(\times\)( \(x-6\)) = 4 \(\times\) \(x\) + 11
11 \(\times\)\(x\) - 66 = 4 \(\times\) \(x\) + 11
11 \(\times\) \(x\) = 4 \(\times\) \(x\) + 11 + 66
11 \(\times\) \(x\) = 4 \(\times\) \(x\) + 77
11 \(\times\) \(x\) - 4 \(\times\) \(x\) = 77
\(x\) \(\times\) ( 11 - 4) = 77
\(x\) \(\times\) 7 = 77
\(x\) = 77 : 7
\(x\) = 11
g, (5 \(\times\) \(x\) + 7) : \(x\) + 20 = 26
(5 \(\times\) \(x\) + 7) : \(x\) = 26 - 20
(5 \(\times\) \(x\) + 7) : \(x\) = 6
5 \(\times\) \(x\) + 7 = 6 \(\times\) \(x\)
6 \(\times\) \(x\) - 5 \(\times\)\(x\) = 7
\(x\times\)( 6- 5) = 7
\(x\) = 7
f, (3 \(\times\) \(x\) - 4): \(x\) + 10 = 12
(3 \(\times\) \(x\) - 4) : \(x\) = 12 - 10
( 3 \(\times\) \(x\) - 4): \(x\) = 2
3 \(\times\) \(x\) - 4 = 2 \(\times\) \(x\)
3 \(\times\) \(x\) - 2 \(\times\) \(x\) = 4
\(x\) \(\times\) ( 3 - 2) = 4
\(x\) = 4
h, \(x\times\) 1999 - \(x\) = 1999 \(\times\)1997 + 1999
\(x\) \(\times\)( 1999 - 1) = 1999 \(\times\) ( 1997 + 1)
\(x\) \(\times\) 1998 = 1999 \(\times\) 1998
\(x\) = 1999 \(\times\) 1998 : 1998
\(x\) = 1999
a)3/2 x 4/7 8/21 : 2/3 8/21 : 4/7 4/7 x 2/3
b)3/11 x 2 6/11 : 3/11 6/11 : 2 2 x 3/11
c)4 x 2/7 8/7 : 2/7 8/7 : 4 2/7 x 4
a) 3/2 x 4/7 = 6/7
8/21 : 2/3= 4/7
8/21 : 4/7 = 2/3
4/7 x 2/3 = 8/21
b) 3/11 x 2 = 6/11
6/11: 3/11 = 2
a,7/4+-3/5
b,2021-(1/3)^2 x 3^2
c,7,5 x(-3/5)
d,(-1/4)^2 x 4/11+7/11 x(-1/4)^2
e, A= 1/4 +1/4^2+1/4^3+...+1/4^2020<1/3
a: \(\dfrac{7}{4}+\dfrac{-3}{5}=\dfrac{35-12}{20}=\dfrac{23}{20}\)
d: \(\left(-\dfrac{1}{4}\right)^2\cdot\dfrac{4}{11}+\dfrac{7}{11}\cdot\left(-\dfrac{1}{4}\right)^2=\dfrac{1}{16}\)
\(\dfrac{7}{4}+\dfrac{-3}{5}=\dfrac{35}{20}+\dfrac{-12}{20}=\dfrac{23}{20}\)
3/13 x 6/11 + 3/13 x 9/11 - 3/13 x 4/11 = ?
Nhanh giúp mình ạ
Tìm x\(\in\)Z, biết:
a)3-5+(-x+3)=6
b)(-4-x)+(4-15)=-15
c)(11+x)-(-11-9)=32
`a) 3-5+(-x+3)=6`
`=>5+(-x+3)=3-6`
`=>5+(-x+3)=-3`
`=>-x+3=-3-5`
`=>-x+3=-8`
`=>-x=-8-3`
`=>-x=-11`
`=>x=11`
__
`b)(-4-x)+(4-15)=-15`
`=>(-4-x)+-11=-15`
`=>-4-x=-15-(-11)`
`=>-4-x=-15+11`
`=>-4-x=-4`
`=>x=-4-(-4)`
`=>x=-4+4`
`=>x=0`
`c)(11+x)-(-11-9)=32`
`=>(11+x)-(-20)=32`
`=>(11+x)+20=32`
`=>11+x=32-20`
`=>11+x=12`
`=>x=12-11`
`=>x=1`
`a)3-5+(-x+3)=6`
`5+(-x+3)=3-6`
`5+(-x+3)=-3`
`-x+3=-3-5`
`-x+3=-8`
`-x=-8-3`
`-x=-11`
`x=11`
`b,(-4-x)+(4-15)=-15`
`(-4-x)+(-11)=-15`
`-4-x=-15-(-11)`
`-4-x=-15+11`
`-4-x=-4`
`x=-4-(-4)`
`x=-4+4`
`x=0`
`c)(11+x)-(-11-9)=32`
`(11+x)-(-20)=32`
`(11+x)+20=32`
`11+x=32-20`
`11+x=12`
`x=12-11`
`x=1`
a ) 3 − 5 + ( − x + 3 ) = 6 ⇒ 5 + ( − x + 3 ) = 3 − 6 ⇒ 5 + ( − x + 3 ) = − 3 ⇒ − x + 3 = − 3 − 5 ⇒ − x + 3 = − 8 ⇒ − x = − 8 − 3 ⇒ − x = − 11 ⇒ x = 11 __ b ) ( − 4 − x ) + ( 4 − 15 ) = − 15 ⇒ ( − 4 − x ) ± 11 = − 15 ⇒ − 4 − x = − 15 − ( − 11 ) ⇒ − 4 − x = − 15 + 11 ⇒ − 4 − x = − 4 ⇒ x = − 4 − ( − 4 ) ⇒ x = − 4 + 4 ⇒ x = 0 c ) ( 11 + x ) − ( − 11 − 9 ) = 32 ⇒ ( 11 + x ) − ( − 20 ) = 32 ⇒ ( 11 + x ) + 20 = 32 ⇒ 11 + x = 32 − 20 ⇒ 11 + x = 12 ⇒ x = 12 − 11 ⇒ x = 1