a) (7x – 15).8 – 21 = 27
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a) (7x – 15).8 – 21 = 27
(7x - 15).8 - 21 = 27
(7x - 15).8 = 27 + 21
(7x - 15).8 = 48
7x - 15 = 48:8
7x - 15 = 6
7x = 6 + 15
7x = 21
x = 21 : 7
x = 3
Vậy x = 3
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(7x - 15).8 - 21 = 27
(7x - 15).8 = 27 + 21
(7x - 15).8 = 48
7x - 15 = 48:8
7x - 15 = 6
7x = 6 + 15
7x = 21
x = 21 : 7
x = 3
Vậy x = 3
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a) (7x – 15).8 – 21 = 27
thank
(7x - 15) = 27+21
(7x - 15)= 48
7x= 48+15
7x= 63
x= 63:7
x= 9
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56x -120 -21 =27
56x = 27+210 +21
56x = 168
x = 3
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\(\left(7x-15\right).8-21=27.\Leftrightarrow\left(7x-15\right).8=48.\Leftrightarrow7x-15=6.\Leftrightarrow x=3.\)
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Xem thêm câu trả lời
8/7x-10/3=-5/21
x:27=-2:3,6
Bài 1:
\(\frac{8}{7}x-\frac{10}{3}=-\frac{5}{21}\)
\(\Rightarrow\frac{8}{7}x=\frac{5}{6}\)
\(\Rightarrow x=\frac{35}{48}\)
Bài 2:
\(\frac{x}{27}=-\frac{2}{3,6}\)
\(\Rightarrow x=\frac{\left(-2\right)\cdot27}{3,6}=-15\)
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Tính hợp lý
a, - ( - 15 ) - ( +27 ) + ( + 27 ) + ( -15 ) + ( -29)
b, 12 - ( a + 105 - 13 ) + ( 4 + 105 - 13 )
c, ( 5 + 7 - 8 ) - ( 7 + 5 - 8 )
d, - 15 - ( -17 + 21 - 35 ) + ( -17 + 21 - 35)
e, 32 - ( -7 - 28 + 15 ) - ( 7 + | -28 | + 32 )
f, -1379 - ( -1379 - 27 )
Làm giùm, cần gấp.
1/8 + 2/5 - 4/32
-1/15 + 23/27 + -14/15 + 31/27
3/7 . 22/21 + 3/7 . 5/21 + 15/21 . 3/7
-8/9 : 2/3 +1/9 : -2/3
a: =1/8-1/8+2/5=2/5
b: =(-1/15-14/15)+(23/27+31/27)=2-1=1
c: \(=\dfrac{3}{7}\left(\dfrac{22}{21}+\dfrac{5}{21}+\dfrac{15}{21}\right)=\dfrac{3}{7}\cdot2=\dfrac{6}{7}\)
d: \(=\dfrac{-8}{9}\cdot\dfrac{3}{2}+\dfrac{1}{9}\cdot\dfrac{-3}{2}=-\dfrac{3}{2}\)
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So sánh :
A=21^15 và B=27^5x49^8
1)tim x bit a)(1/2-1/3).6^x+6^x+2=6^15+6^18
b)3^x+3^x+2=2430
c)(2x-15)^5=(2x-15)^3
2) so saanh
a)2^11 va 5^35
b)2^31 va 3^21
c)2^15 va 27^5.49^8 d)21^15 va 27^5.49^8
1)tim x bit a)(1/2-1/3).6^x+6^x+2=6^15+6^18
b)3^x+3^x+2=2430
c)(2x-15)^5=(2x-15)^3
2) so saanh a)2^11 va 5^35
b)2^31 va 3^21
c)2^15 va 27^5.49^8 d)21^15 va 27^5.49^8
1.
b) \(3^x+3^{x+2}=2430\)
\(\Rightarrow3^x.1+3^x.3^2=2430\)
\(\Rightarrow3^x.\left(1+3^2\right)=2430\)
\(\Rightarrow3^x.10=2430\)
\(\Rightarrow3^x=2430:10\)
\(\Rightarrow3^x=243\)
\(\Rightarrow3^x=3^5\)
\(\Rightarrow x=5\)
Vậy \(x=5.\)
c) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\Rightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)
\(\Rightarrow\left(2x-15\right)^3.\left[\left(2x-15\right)^2-1\right]=0\)
\(\Rightarrow\left[{}\begin{matrix}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15\right)^2=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=15\\2x-15=\pm1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=15:2\\2x-15=1\\2x-15=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{15}{2}\\2x=16\\2x=14\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{15}{2}\\x=8\\x=7\end{matrix}\right.\)
Vậy \(x\in\left\{\frac{15}{2};8;7\right\}.\)
Chúc bạn học tốt!
So sanh:
a)21^15 va 27^5×49^8
b)3^99 va 11^21