259,201 + 102,208 = 361,409

145,897 - 52,52 = 93,377

15,7 x 55 = 863,5

175 : 5 = 35

a: \(2004^2-16=2000\cdot2008=4016000\)

b: \(892^2+892\cdot216+108^2=1000^2=1000000\)

c: \(36^2-52\cdot36+26^2=10^2=100\)

\(\dfrac{59-x}{41}+\dfrac{57-x}{43}+\dfrac{55-x}{45}+\dfrac{53-x}{47}+\dfrac{51-x}{49}=-5\)

\(\Leftrightarrow\dfrac{59-x}{41}+1+\dfrac{57-x}{43}+1+\dfrac{55-x}{45}+1+\dfrac{53-x}{47}+1+\dfrac{51-x}{49}+1=0\)

=>100-x=0

hay x=100

14x + 54 = 82

14x = 28

x = 2

175 + (30 - x) = 2001

30 - x = 1826

x = 30 - 1826

x = - 1796

1551 - 10 ( x + 1 ) = 55

10(x + 1) = 1496

x + 1 = 149,6

x = 148,6

5 . (x + 12) + 22 = 92

5 . (x + 12) = 70

x + 12 = 14

x = 2

6 . (x + 23) + 40 = 100

6 . (x + 23) = 60

x + 23 = 10

x = - 13

\(14x+54=82\)

\(\Leftrightarrow14x=82-54\)

\(\Leftrightarrow14x=28\)

\(\Leftrightarrow x=2\)

Vậy \(x=2\)

\(175+\left(30-x\right)=2001\)

\(\Leftrightarrow30-x=2001-175\)

\(\Leftrightarrow30-x=1826\)

\(\Leftrightarrow x=-1796\)

Vậy \(x=-1796\)

\(1551-10\left(x+1\right)=55\)

\(\Leftrightarrow10.\left(x+1\right)=1551-55\)

\(\Leftrightarrow10.\left(x+1\right)=1496\)

\(\Leftrightarrow x+1=\frac{1496}{10}\)

\(\Leftrightarrow x=\frac{1486}{10}\)

Vậy \(x=\frac{1486}{10}\)

\(5.\left(x+12\right)+22=92\)

\(\Leftrightarrow5.\left(x+12\right)=70\)

\(\Leftrightarrow x+12=14\).

\(\Leftrightarrow x=2\)

Vậy \(x=2\)

\(6.\left(x+23\right)+40=100\)

\(\Leftrightarrow6.\left(x+23\right)=60\)

\(\Leftrightarrow x+23=10\)

\(\Leftrightarrow x=-13\)

Vậy \(x=-13\)

ta có: (59-x)/41  +(57-x)/43  +(55-x)/45  +(53-x)/47  +(51-x)/49 =-5

       <=>[(59-x)/41  +1 ]  +[(57-x)/43  +1]  +[(55-x)/45  +1]  +[(53-x)/47  +1]   +[(51-x)/49  +1] =0

      <=>(59-x-41)/41      + (57-x-43)/43     +(55-x-45)/45     +(53-x-47)/47      +(51-x-49)/49    =0

      <=>(100-x)/41   +   (100-x)/43       +    (100-x)/45     +(100-x)/47      +   (100-x)/49   =0

     <=>(100-x).( 1/41   +  1/43  +  1/45   +   1/47   +  1/49  )  =0

mà   (1/41  +  1/43  +  1/45  +  1/47  +  1/49) khác 0  nên 100-x =0 <=>x=100

vậy nghiệm của pt là x=100

1: Tính

a: 27+ 55+ (-17) + (-55)

= (27-17) + (55-55)

= 10 + 0

= 10

b: (-92)+ (-251)+ (-8)+ 25

= -(92+8) - (251 - 25)

= -100 - 226

= -326

c: (235- 47) + (175- 53)

= 235 - 47 + 175 - 53

= (235+175) - (47+53)

= 410 - 100

= 310

d: (756- 217)- (183- 44)

= 756 - 217 - 183 + 44

= (756+44) - (217+183)

= 800 - 400

= 400

2: Tìm x, biết

\(\text{x. (x+ 3)= 0}\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x+3=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x=-3\end{cases}}\)

vậy______

\(\text{(x-2). (5- x) = 0}\)

\(\Rightarrow\orbr{\begin{cases}x-2=0\\5-x=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=2\\x=5\end{cases}}\)

vậy________

(x- 3). (2x +1) = 7

=> x-3 và 2x + 1 thuộc Ư(7)

ta có bảng sau :

vậy x thuộc {4;3;2;-3;10;0;-4;-1}

a: 27+ 55+ (-17) + (-55)

=27 + 55 -17 - 55

=10

b: (-92)+ (-251)+ (-8)+ 25

= -92 - 251 - 8 + 25

=-326

c: (235- 47) + (175- 53)

=188 + 122

=310

d: (756- 217)- (183- 44)

=539 - 139

=400

Bài 1:

a) 27 + 55 + (-17) + (-55)

= (27 - 17) + (55 - 55)

= 10 + 0

= 10

b) (-92) + (-251) + (-8) + 25

= (-92 - 8) - (251 - 25)

= (-100) - 226

= -326

c) (235 - 47) + (175 - 53)

= 235 - 47 + 175 - 53

= (235 + 175) - (47 + 53)

= 410 - 100

= 310

d) (756 - 217) - (183 - 44)

= 756 - 217 - 183 + 44

= (756 + 44) - (217 + 183)

= 800 - 400

= 400