3335 nhà ko có mt ak?

tất cả = 3335

 với lại đây là toán lớp 2 nha bn hiểu nhầm r

=3335

Sửa đề: 4^10

\(\dfrac{4^{10}\cdot9^3-6^9\cdot120}{8^4\cdot3^{12}+6^{11}}\)

\(=\dfrac{2^{20}\cdot3^6-2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}+2^{11}\cdot3^{11}}\)

\(=\dfrac{2^{12}\cdot3^6\left(2^8-3^4\cdot5\right)}{2^{11}\cdot3^{11}\left(2\cdot3+1\right)}=\dfrac{2}{3^5}\cdot\dfrac{-149}{7}=\dfrac{-298}{3^5\cdot7}\)

=46x ( 37+93)+54 x (61+69)

= 46 x 130 + 54 x 130

= 130 x ( 46+54)

=130 x 100

=13000

46 x 37 + 93 x 46 + 54 x 61 + 69 x 54

= 46 x ( 37 + 93 ) + 54 x ( 61 + 69 )

= 46 x 120 + 54 x 120

= 120 x ( 46 + 54 )

= 120 x 100

= 12000

\(46.35+93.46+54.61+69.54\)

\(=\left(37+93\right)46+\left(61+69\right)54\)

\(=130.46+130.54\)

\(=130\left(46+54\right)\)

\(=130.100=13000\)

1/3 của 69 kg là : 69 : 3 = 23 (kg)

1/3 của 36 m là : 36 : 3 = 12 (m)

1/3 của 93 l là : 93 : 3 = 31 (l)

`#3107.101107`

\(45\times37+93\times45+55\times61+69\times55\)

\(=45\times\left(37+93\right)+55\times\left(61+69\right)\)

\(=45\times130+55\times130\)

\(=130\times\left(45+55\right)\)

\(=130\times100\)

\(=13000\)

\(#GNamK\)

45x37+93x45+55x61+69x55
=45x(37+93)+55x(61+69)

=45x130+55x130
=130x(45+55)

=130x100=13000

\(x:2+250.4=55.61+69.55-45.37-93.45\)

\(\Leftrightarrow x:2+1000=55\left(61+69\right)-45\left(37+93\right)\)

\(\Leftrightarrow x:2+1000=55.130-45.130\)

\(\Leftrightarrow x:2+1000=130\left(55-45\right)\)

\(\Leftrightarrow x:2+1000=130.10\)

\(\Leftrightarrow x:2+1000=1300\)

\(\Leftrightarrow x:2=1300-1000=300\)

\(\Leftrightarrow x=300.2=600\)

Vậy \(x=600\)

X:2+250*4=55*61+69*55-45*37-93*45

X:2+250*4=(55*61+69*55)-(45*37+93*45)

X:2+1000=55*(61+69)-45*(37+93)

X:2+1000=55*130-45*130

X:2+1000=(55-45)*130

X:2+1000=10*130

X:2+1000=1300

X:2=1300-1000

X:2=300

X=300*2

X=600

Vậy X = 600

=43.37+93.43+57.61+69.57

=43.(37+93)+57.(61+69)

=43.130+77.130

=130.(43+57)

=13000

=9412

nho h cho minh nhe

minh ghi lon cho 57 ma minh ghi 77

\(\dfrac{51}{53}+\dfrac{55}{57}+\dfrac{61}{63}+\dfrac{69}{71}+\dfrac{79}{81}+\dfrac{91}{93}\) 

\(=\left(\dfrac{52}{53}-\dfrac{1}{53}\right)+\left(\dfrac{56}{57}-\dfrac{1}{57}\right)+\left(\dfrac{62}{63}-\dfrac{1}{63}\right)+\left(\dfrac{70}{71}-\dfrac{1}{71}\right)+\left(\dfrac{80}{81}-\dfrac{1}{81}\right)+\left(\dfrac{92}{93}-\dfrac{1}{93}\right)\)

\(=\left(1-\dfrac{1}{53}-\dfrac{1}{53}\right)+\left(1-\dfrac{1}{57}-\dfrac{1}{57}\right)+\left(1-\dfrac{1}{63}-\dfrac{1}{63}\right)+\left(1-\dfrac{1}{71}-\dfrac{1}{71}\right)+\left(1-\dfrac{1}{81}-\dfrac{1}{81}\right)+\left(1-\dfrac{1}{93}-\dfrac{1}{93}\right)\)

\(=\left(1-0\right)+\left(1-0\right)+\left(1-0\right)+\left(1-0\right)+\left(1-0\right)+\left(1-0\right)\) 

\(=1+1+1+1+1+1\) 

\(=6\)