a) 5 : 3/4 - 4 4/5 : 3/4

= 5 . 4/3 - 24/5 . 4/3

= (5 - 24/5) . 4/3

= 1/5 × 4/3

= 4/15

b) -3/5 . 2/7 + (-3/7) . 3/5 + (-3/7)

= (-3/7) . (2/5 + 3/5 + 1)

= (-3/7) . 2

= -6/7

c) [(-4 2/7) . 7/11 + 7/11 . (5 1/3)] . 5 - 5 2/3

= (-30/7 . 7/11 + 7/11 . 16/3) . 5 - 17/3

= (-30/11 + 112/33) . 5 - 17/3

= 2/3 . 5 - 17/3

= 10/3 - 17/3

= -7/3

d) 5/39 . [(7 4/5) . (1 2/3) + (8 1/3) . (7 4/5)]

= 5/39 . (39/5 . 5/3 + 25/3 . 39/5)

= 5/39 . 39/5 . (5/3 + 25/3)

= 1 . 10

= 10

= 

51/30

24/65

chưa xong 

Viết phân số thích hợp vào chỗ chấm:

A) 3/4 nhân ( 5/6+6/5 )= 3/4 nhân 5/6+3/4 nhân 6/5       

B) 7/5 nhân ( 4/7-2/5 )= 7/5 nhân 4/7- 7/5 nhân 2/5

Viết phân số thích hợp vào chỗ chấm:

A)3/4.(5/6+6/5)=3/4.61/30=61/40   

B)7/5.(4/7-2/5)=7/5.6/35=6/25

a=1234567890-123456790=1223

Gợi ý: Nó trong VBT Toán Nâng Cao

bó tay !

a) \(\dfrac{3}{7}\)

b)\(\dfrac{9}{4}\)

c)\(\dfrac{1}{3}\)

d)\(\dfrac{41}{32}\) 

e)\(\dfrac{73}{60}\)

a,3/7

b,9/4

c,1/3

d,41/32

e,73/60

\(\dfrac{2}{5}\times\dfrac{1}{7}+\dfrac{2}{7}\times\dfrac{2}{5}\)

\(=\dfrac{2}{5}\times\left(\dfrac{1}{7}+\dfrac{2}{7}\right)\)

\(=\dfrac{2}{5}\times\dfrac{3}{7}\)

\(=\dfrac{6}{35}\)

\(x+\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{3}{4}\)

\(x+\dfrac{1}{6}=\dfrac{3}{4}\)

\(x=\dfrac{9}{12}-\dfrac{2}{12}\)

\(x=\dfrac{7}{12}\)

\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times...\times\left(1-\dfrac{1}{2020}\right)+x=\dfrac{1}{2}\)

\(\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{2019}{2020}+x=\dfrac{1}{2}\)

\(\dfrac{1}{2020}+x=\dfrac{1}{2}\)

\(x=\dfrac{1}{2}-\dfrac{1}{2020}\)

\(x=\dfrac{1010}{2020}-\dfrac{1}{2020}\)

\(x=\dfrac{1009}{2020}\)

\(\dfrac{2}{5}\times\dfrac{1}{7}+\dfrac{2}{7}\times\dfrac{2}{5}\)

\(=\dfrac{2}{5}\times\left(\dfrac{1}{7}+\dfrac{2}{7}\right)\)

\(=\dfrac{2}{5}\times\dfrac{3}{7}\)

\(=\dfrac{6}{35}\)

\(x+\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{3}{4}\)

\(\Rightarrow\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{3}{4}-x\)

\(\Rightarrow\dfrac{3}{4}-x=\dfrac{1}{6}\)

\(\Rightarrow x=\dfrac{3}{4}-\dfrac{1}{6}=\dfrac{7}{12}\)

\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times...\times\left(1-\dfrac{1}{2020}\right)+x=\dfrac{1}{2}\)

\(\Rightarrow\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{2019}{2020}+x=\dfrac{1}{2}\)

\(\Rightarrow\dfrac{1\times2\times3\times4\times...\times2019}{2\times3\times4\times5\times...\times2020}+x=\dfrac{1}{2}\)

\(\Rightarrow\dfrac{1}{2020}+x=\dfrac{1}{2}\)

\(\Rightarrow x=\dfrac{1}{2}-\dfrac{1}{2020}=\dfrac{1009}{2020}\)

Em nên gõ công thức trực quan để đề bài rõ ràng nhé

12+(5+x)=20

5+x=8

    x=8/5

vãy=8/5

12 + ( 5 + x ) = 20              5.2² + ( x + 3 ) = 5²                         2³ + ( x + 3 ) = 5²                                 4³ - ( x - 2 ) = 5²

17 + x = 20                        5.4 + x + 3 = 25                               8 + x + 3 = 25                                  64 - x + 2 = 25

x = 20 - 17                         20 + 3 + x = 25                                11 + x = 25                                       66 - x = 25

x = 3                                  23 + x = 25                                       x = 25 - 11                                        x = 66 - 25

                                          x = 25 - 23                                        x = 14                                               x = 41

                                          x = 2

Đăng nhìu v bn :) Đáng quan ngại đây :)

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