\(\frac{9-\left(x+5\right)^2}{x^2+4x+4}\).Hay rut gon phan tu tren?
Những câu hỏi liên quan
Rut gon bt
\(\left(\frac{2+x}{2-x}-\frac{4x^2}{x^2-4}-\frac{2-x}{2+x}\right):\left(\frac{x^2-3x}{2x^2-x^3}\right)\)
Rut gon bt
\(A=\left(\frac{2+x}{2-x}-\frac{4x^2}{x^2-4}-\frac{2-x}{2+x}\right):\left(\frac{x^2-3x}{2x^2-x^3}\right)\)
Rut gon
\(\frac{1}{2}x^2.\left(6x-3\right)-x.\left(x^2+\frac{1}{2}\right)+\frac{1}{2}\left(x+4\right)\)
\(2x\left(3x^3-x\right)-4x^2\left(x-x^2+1\right)+\left(x-3x^2\right)x\)
\(\frac{1}{2}x^2\left(6x-3\right)-x\left(x^2+\frac{1}{2}\right)+\frac{1}{2}\left(x+4\right)\)
\(=\frac{1}{2}x^2.6x+\frac{1}{2}x^2.\left(-3\right)+\left(-x\right).x^2+\left(-x\right).\frac{1}{2}+\frac{1}{2}.x+\frac{1}{2}.4\)
\(=3x^3-\frac{3}{2}x^2-x^3-\frac{1}{2}x+\frac{1}{2}x+2\)
\(=\left(3x^3-x^3\right)-\frac{3}{2}x^2+\left(-\frac{1}{2}x+\frac{1}{2}x\right)+2\)
\(=2x^3-\frac{3}{2}x^2+2\)
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\(a,\)\(\frac{1}{2}x^2\left(6x-3\right)-x\left(x^2+\frac{1}{2}\right)+\frac{1}{2}\left(x+4\right)\)
\(=3x^3-\frac{3}{2}x^2-x^3-\frac{1}{2}x+\frac{1}{2}x+2\)
\(=2x^3-\frac{3}{2}x^2+2\)
\(b,\)\(2x\left(3x^3-x\right)-4x^2\left(x-x^2+1\right)+\left(x-3x^2\right)x\)
\(=6x^4-2x^2-4x^3+4x^4-4x^2+x^2-3x^3\)
\(=10x^4-7x^3-5x^2\)
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\(\frac{1}{2}x^2.\left(6x-3\right)-x\left(x^2+\frac{1}{2}\right)+\frac{1}{2}\left(x+4\right)\)
\(=3x^3-\frac{3}{2}x^2-x^3-\frac{1}{2}x+\frac{1}{2}x+2\)
\(=2x^3-\frac{3}{2}x^2+2\)
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rut gon phan thuc:
a, \(\frac{10x}{5x^2}\)
b,\(\frac{x\left(x^2-y^2\right)}{x^2\left(x+y\right)}\)
a/\(\frac{10x}{5x^2}=\frac{2}{x}\)
b/\(\frac{x\left(x^2-y^2\right)}{x^2\left(x+y\right)}=\frac{\left(x-y\right)\left(x+y\right)}{x\left(x+y\right)}=\frac{x-y}{x}\)
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Cho cac so nguyen duong a,b,c,x,y,z1, Biet 1/a 3/b + c 5/c + a. Hay rut gon phan so A a/2b - c2. Biet a/b 2b/cc 4c/a. Hay rut gon phan so B ab + bc + ca/a2 + b + c23. Biet x/a y/b z/c. Hay rut gon phan so C x*y*z*(b+c)*(c+a)*(a+b)/a*b*c(y+z)*(z+x)*(x+y)4. Biet ab/a + 2b 2/5; bc/b + 2c 3/4; ca/c +2a 3/5. Hay rut gon phan so D abc/ab+bc+ca5. Biet 3/a -4b 5c. Hay rut gon phan so E 3bc + ab - 4ac/6bc - 8ac -abGiup minh nhe! Ai lam duoc va dung cho tick.Thanks cac ban
Đọc tiếp
Cho cac so nguyen duong a,b,c,x,y,z
1, Biet 1/a = 3/b + c = 5/c + a. Hay rut gon phan so A = a/2b - c
2. Biet a/b = 2b/cc = 4c/a. Hay rut gon phan so B = ab + bc + ca/a2 + b + c2
3. Biet x/a = y/b =z/c. Hay rut gon phan so C = x*y*z*(b+c)*(c+a)*(a+b)/a*b*c(y+z)*(z+x)*(x+y)
4. Biet ab/a + 2b = 2/5; bc/b + 2c = 3/4; ca/c +2a = 3/5. Hay rut gon phan so D = abc/ab+bc+ca
5. Biet 3/a -4b = 5c. Hay rut gon phan so E = 3bc + ab - 4ac/6bc - 8ac -ab
Giup minh nhe! Ai lam duoc va dung cho tick.
Thanks cac ban
xin lỗi tớ ấn nhầm chỗ M=7 tớ làm lại rồi đó
ban tra loi het cac cau hoi phia tren kia ho minh dc ko?
Cho cac so nguyen duong a,b,c,x,y,z1, Biet 1/a 3/b + c 5/c + a. Hay rut gon phan so A a/2b - c2. Biet a/b 2b/cc 4c/a. Hay rut gon phan so B ab + bc + ca/a2 + b + c23. Biet x/a y/b z/c. Hay rut gon phan so C x*y*z*(b+c)*(c+a)*(a+b)/a*b*c(y+z)*(z+x)*(x+y)4. Biet ab/a + 2b 2/5; bc/b + 2c 3/4; ca/c +2a 3/5. Hay rut gon phan so D abc/ab+bc+ca5. Biet 3/a -4b 5c. Hay rut gon phan so E 3bc + ab - 4ac/6bc - 8ac -abGiup minh nhe! Ai lam duoc va dung cho tick.Thanks cac ban
Đọc tiếp
Cho cac so nguyen duong a,b,c,x,y,z
1, Biet 1/a = 3/b + c = 5/c + a. Hay rut gon phan so A = a/2b - c
2. Biet a/b = 2b/cc = 4c/a. Hay rut gon phan so B = ab + bc + ca/a2 + b + c2
3. Biet x/a = y/b =z/c. Hay rut gon phan so C = x*y*z*(b+c)*(c+a)*(a+b)/a*b*c(y+z)*(z+x)*(x+y)
4. Biet ab/a + 2b = 2/5; bc/b + 2c = 3/4; ca/c +2a = 3/5. Hay rut gon phan so D = abc/ab+bc+ca
5. Biet 3/a -4b = 5c. Hay rut gon phan so E = 3bc + ab - 4ac/6bc - 8ac -ab
Giup minh nhe! Ai lam duoc va dung cho tick.
Thanks cac ban
\(\dfrac{\left(x+2\right)^2}{x}\times\left(1-\dfrac{x^2}{x+2}\right)-\dfrac{x^2+6x+4}{x}\)
rut gon bieu thuc tren
\(=\dfrac{\left(x+2\right)^2}{x}\cdot\dfrac{x+2-x^2}{x+2}-\dfrac{x^2+6x+4}{x}\)
\(=\dfrac{\left(x+2\right)\left(-x^2+x+2\right)-x^2-6x-4}{x}\)
\(=\dfrac{-x^3+x^2+2x-2x^2+2x+4-x^2-6x-4}{x}\)
\(=\dfrac{-x^3-2x^2-2x}{x}=-x^2-2x-2\)
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rut gon phan thuc:
1 \(\dfrac{x^2-18x-19}{x^2-1}\)
2 \(\dfrac{x\left(4x^2-8x+4\right)}{2x^3-2x^2}\)
1) \(\dfrac{x^2-18x-19}{x^2-1}=\dfrac{x^2-19x+x-19}{\left(x-1\right)\left(x+1\right)}=\dfrac{x\left(x-19\right)+x-19}{\left(x-1\right)\left(x+1\right)}=\dfrac{\left(x-19\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}=\dfrac{x-19}{x-1}\)
2) \(\dfrac{x\left(4x^2-8x+4\right)}{2x^3-2x^2}=\dfrac{4x\left(x^2-2x+1\right)}{2x^2\left(x-1\right)}=\dfrac{4x\left(x-1\right)^2}{2x^2\left(x-1\right)}=\dfrac{2\left(x-1\right)}{x}\)
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1.=\(\dfrac{(x^2+x)-(19x+19)}{(x+1)(x-1)}\)
=\(\dfrac{x(x+1)-19(x+1)}{(x+1)(x-1)}\)
=\(\dfrac{(x+1)(x-19)}{(x+1)(x-1)}\)
=\(\dfrac{x-19}{x-1}\)
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rut gon phan thuc
\(\dfrac{\left(-x\right)^5.a^2}{x^2.\left(-a\right)^3}\)
rút gọn phân thức:
\(\dfrac{\left(-x\right)^5.a^2}{x^2.\left(-a\right)^3}=\dfrac{x^2.\left(-x\right)^3.a^2}{x^2.\left(-a\right).a^2}=\dfrac{-x^3}{-a}=\dfrac{x^3}{a}\)
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\(\dfrac{\left(-x\right)^5.a^2}{x^2.\left(-a\right)^3}\\ =\dfrac{\left(-x\right)^3x^2.a^2}{x^2.\left(-a\right).a^2}\\ =\dfrac{\left(-x\right)^3}{a}\)
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\(\dfrac{\left(-x\right)^5.a^2}{x^2.\left(-a\right)^3}\\ =\dfrac{\left(-x\right)^3x^2.a^2}{x^2.\left(-a\right).a^2}\)
\(=\dfrac{\left(-x\right)^3}{a}\)
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