( -1,5x - 15 ) x \(\frac{2}{3}\)=\(-\frac{2}{5}\)
Những câu hỏi liên quan
\(\left(\frac{2x}{3}-3\right):\left(-10\right)=\frac{2}{5}\)
\(1,5x-2\frac{1}{3}x=1,5-\frac{2}{3}\)
Giup minh voi
a) \(\left(\frac{2x}{3}-3\right):\left(-10\right)=\frac{2}{5}\)
<=> \(\frac{2x}{3}-3=\frac{2}{5}.\left(-10\right)\)
<=> \(\frac{2x}{3}-3=-4\)
<=> \(\frac{2x}{3}=-4+3=-1\)
<=> \(2x=-1.3=-3\)
<=> \(x=\frac{-3}{2}\)
Vậy \(x=\frac{-3}{2}\)
b) \(1,5x-2\frac{1}{3}x=1,5-\frac{2}{3}\)
\(x.\left(1,5-2\frac{1}{3}\right)=\frac{5}{6}\)
\(x.\left(\frac{-5}{6}\right)=\frac{5}{6}\)
\(x=\frac{5}{6}:\left(\frac{-5}{6}\right)=\frac{5}{6}.\left(\frac{-6}{5}\right)=-1\)
Vậy \(x=-1\)
Nếu đúng thì cho mình nhé, chúc bạn học tốt !
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Tìm x biêt:
a)5x(x-1\3)=0
b)(x+1\4)(x-2\3)=0
c)1+3x=-5
d)1,5x-\(2\frac{1}{3}\)=1,5-2\3
e)2\3+1\3:x=3\5
y)\(\left(\frac{2x}{3}-3\right):\left(-10\right)=\frac{2}{5}\)
Tìm x:
A. 0,5x - \(\frac{1}{3}\) x =\(\frac{1}{3}\)
B. x: \(3\frac{1}{2}\) = -1,5
C. 1,5x = \(\frac{11}{5}\)
a. \(0,5x-\frac{1}{3}x=\frac{1}{3}\)
\(\left(0,5-\frac{1}{3}\right)x=\frac{1}{3}\)
\(\frac{1}{6}x=\frac{1}{3}\)
\(x=\frac{1}{3}:\frac{1}{6}\)
\(x=2\)
b. \(x:3\frac{1}{2}=-1,5\)
\(x=-1,5\times3\frac{1}{2}\)
\(x=-5,25\)
c. \(1,5x=\frac{11}{5}\)
\(x=\frac{22}{15}\)
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A. 0,5x - 1/3x = 1/3
(0,5 - 1/3)x = 1/3
1/6x = 1/3
x = 2
B. x : 3 1/2 = -1,5
x = -1,5 x 3 1/2
x = -5,25
C. 1,5x = 11/5
x = 22/15
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5 tháng 6 2019 lúc 20:32
Giải bất phương trình
\(2x+3>5\)
\(\frac{3}{5}x+\frac{12}{15}< 0\)
\(24x-5\le14,5\)
\(1,5x+4\le7\)
\(a,\)\(2x+3>5\)
\(\Rightarrow2x>5-3\)
\(\Rightarrow2x>2\)
\(\Rightarrow x>1\)
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\(\frac{3}{5}x+\frac{12}{15}< 0\)
\(\Rightarrow\frac{3}{5}x+\frac{4}{5}< 0\)
\(\Rightarrow3x+4< 0\)
\(\Rightarrow3x< -4\)
\(\Rightarrow x>\frac{-4}{3}\)
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1) \(2x+3>5\Leftrightarrow2x>2\Leftrightarrow x>1.\)
2)\(\frac{3}{5}x+\frac{12}{15}< 0\)
\(\Leftrightarrow\frac{3}{5}x< -\frac{4}{5}\)
\(\Leftrightarrow x< -\frac{4}{5}:\frac{3}{5}\)
\(\Leftrightarrow x< -\frac{4}{3}\)
3) \(24x-5\le14,5\)
\(\Leftrightarrow24x\le14,5+5\)
\(\Leftrightarrow24x\le19,5\)
\(\Leftrightarrow x\le\frac{13}{16}\)
4) \(1,5x+4\le7\)
\(\Leftrightarrow1,5x\le3\)
\(\Leftrightarrow x\le2\)
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Xem thêm câu trả lời
Câu 3: Giải các phương trình sau bằng cách đưa về dạng ax+b0
1. a, frac{5x-2}{3}frac{5-3x}{2}; b, frac{10x+3}{12}1+frac{6+8x}{9}
c, 2left(x+frac{3}{5}right)5-left(frac{13}{5}+xright); d, frac{7}{8}x-5left(x-9right)frac{20x+1,5}{6}
e, frac{7x-1}{6}+2xfrac{16-x}{5}; f, 4 (0,5-1,5x)frac{5x-6}{3}
g, frac{3x+2}{2}-frac{3x+1}{6}frac{5}{3}+2x; h, frac{x+4}{5}.x+4frac{x}{3}-frac{x-2}{2}
i, frac{4x+3}{5}-frac{6x-2}{7}fr...
Đọc tiếp
Câu 3: Giải các phương trình sau bằng cách đưa về dạng ax+b=0
1. a, \(\frac{5x-2}{3}=\frac{5-3x}{2}\); b, \(\frac{10x+3}{12}=1+\frac{6+8x}{9}\)
c, \(2\left(x+\frac{3}{5}\right)=5-\left(\frac{13}{5}+x\right)\); d, \(\frac{7}{8}x-5\left(x-9\right)=\frac{20x+1,5}{6}\)
e, \(\frac{7x-1}{6}+2x=\frac{16-x}{5}\); f, 4 (0,5-1,5x)=\(\frac{5x-6}{3}\)
g, \(\frac{3x+2}{2}-\frac{3x+1}{6}=\frac{5}{3}+2x\); h, \(\frac{x+4}{5}.x+4=\frac{x}{3}-\frac{x-2}{2}\)
i, \(\frac{4x+3}{5}-\frac{6x-2}{7}=\frac{5x+4}{3}+3\); k, \(\frac{5x+2}{6}-\frac{8x-1}{3}=\frac{4x+2}{5}-5\)
m, \(\frac{2x-1}{5}-\frac{x-2}{3}=\frac{x+7}{15}\); n, \(\frac{1}{4}\left(x+3\right)=3-\frac{1}{2}\left(x+1\right).\frac{1}{3}\left(x+2\right)\)
p, \(\frac{x}{3}-\frac{2x+1}{6}=\frac{x}{6}-x\); q, \(\frac{2+x}{5}-0,5x=\frac{1-2x}{4}+0,25\)
r, \(\frac{3x-11}{11}-\frac{x}{3}=\frac{3x-5}{7}-\frac{5x-3}{9}\); s, \(\frac{9x-0,7}{4}-\frac{5x-1,5}{7}=\frac{7x-1,1}{6}-\frac{5\left(0,4-2x\right)}{6}\)
t, \(\frac{2x-8}{6}.\frac{3x+1}{4}=\frac{9x-2}{8}+\frac{3x-1}{12}\); u, \(\frac{x+5}{4}-\frac{2x-3}{3}=\frac{6x-1}{3}+\frac{2x-1}{12}\)
v, \(\frac{5x-1}{10}+\frac{2x+3}{6}=\frac{x-8}{15}-\frac{x}{30}\); w, \(\frac{2x-\frac{4-3x}{5}}{15}=\frac{7x\frac{x-3}{2}}{5}-x+1\)
Đây là những bài cơ bản mà bạn!
\(\frac{5x-2}{3}=\frac{5-3x}{2}\)
\(< =>\frac{\left(5x-2\right).2}{6}=\frac{\left(5-3x\right).3}{6}\)
\(< =>\left(5x-2\right).2=\left(5-3x\right).3\)
\(< =>10x-4=15-9x\)
\(< =>10x+9x=15+4\)
\(< =>19x=19< =>x=1\)
\(\frac{10x+3}{12}=1+\frac{6+8x}{9}\)
\(< =>\frac{\left(10x+3\right).3}{36}=\frac{36}{36}+\frac{\left(6+8x\right).4}{36}\)
\(< =>\left(10x+3\right).3=36+\left(6+8x\right).4\)
\(< =>30x+9=36+24+32x\)
\(< =>32x-30x=9-36-24\)
\(< =>2x=9-60=-51< =>x=-\frac{51}{2}\)
Xem thêm câu trả lời
Bài 3 : Giải các phương trình sau bằng cách đưa về dạng ax+b0 :
a) frac{7}{8}x-5left(x-9right)frac{20x+1,5}{6}
b) 4left(0,5-1,5xright)-frac{5x-6}{3}
c) frac{x+4}{5}-x+4frac{x}{3}-frac{x-2}{2}
d) frac{4x+3}{5}-frac{6x-2}{7}frac{5x+4}{3}+3
e) frac{1}{4}left(x+3right)3-frac{1}{2}left(x+1right)-frac{1}{3}left(x+2right)
Đọc tiếp
Bài 3 : Giải các phương trình sau bằng cách đưa về dạng ax+b=0 :
a) \(\frac{7}{8}x-5\left(x-9\right)=\frac{20x+1,5}{6}\)
b) \(4\left(0,5-1,5x\right)=-\frac{5x-6}{3}\)
c) \(\frac{x+4}{5}-x+4=\frac{x}{3}-\frac{x-2}{2}\)
d) \(\frac{4x+3}{5}-\frac{6x-2}{7}=\frac{5x+4}{3}+3\)
e) \(\frac{1}{4}\left(x+3\right)=3-\frac{1}{2}\left(x+1\right)-\frac{1}{3}\left(x+2\right)\)
a) Ta có: \(\frac{7}{8}x-5\left(x-9\right)=\frac{20x+1,5}{6}\)
\(\Leftrightarrow\frac{7x}{8}-5x+45-\frac{20x+1,5}{6}=0\)
\(\Leftrightarrow\frac{21x}{24}-\frac{120x}{24}+\frac{1080}{24}-\frac{4\left(20x+1,5\right)}{24}=0\)
\(\Leftrightarrow-99x+1080-4\left(20x+1,5\right)=0\)
\(\Leftrightarrow-99x+1080-80x-6=0\)
\(\Leftrightarrow1074-179x=0\)
\(\Leftrightarrow179x=1074\)
hay x=6
Vậy: x=6
b) Ta có: \(4\left(0,5-1,5x\right)=-\frac{5x-6}{3}\)
\(\Leftrightarrow2-6x=\frac{6-5x}{3}\)
\(\Leftrightarrow\frac{3\left(2-6x\right)}{3}-\frac{6-5x}{3}=0\)
\(\Leftrightarrow6-18x-6+5x=0\)
\(\Leftrightarrow-13x=0\)
mà -13≠0
nên x=0
Vậy: x=0
c) Ta có: \(\frac{x+4}{5}-x+4=\frac{x}{3}-\frac{x-2}{2}\)
\(\Leftrightarrow\frac{6\left(x+4\right)}{30}+\frac{30\left(-x+4\right)}{30}-\frac{10x}{30}+\frac{15\left(x-2\right)}{30}=0\)
\(\Leftrightarrow6\left(x+4\right)+30\left(4-x\right)-10x+15\left(x-2\right)=0\)
\(\Leftrightarrow6x+24+120-30x-10x+15x-30=0\)
\(\Leftrightarrow-19x+114=0\)
\(\Leftrightarrow-19x=-114\)
hay x=6
Vậy: x=6
d) Ta có: \(\frac{4x+3}{5}-\frac{6x-2}{7}=\frac{5x+4}{3}+3\)
\(\Leftrightarrow\frac{21\left(4x+3\right)}{105}-\frac{15\left(6x-2\right)}{105}-\frac{35\left(5x+4\right)}{105}-\frac{315}{105}=0\)
\(\Leftrightarrow84x+63-90x+30-175x-140-315=0\)
\(\Leftrightarrow-181x-362=0\)
\(\Leftrightarrow-181x=362\)
hay x=-2
Vậy: x=-2
e) Ta có: \(\frac{1}{4}\left(x+3\right)=3-\frac{1}{2}\left(x+1\right)-\frac{1}{3}\left(x+2\right)\)
\(\Leftrightarrow\frac{x+3}{4}=3-\frac{x+1}{2}-\frac{x+2}{3}\)
\(\Leftrightarrow\frac{3\left(x+3\right)}{12}-\frac{36}{12}+\frac{6\left(x+1\right)}{12}+\frac{4\left(x+2\right)}{12}=0\)
\(\Leftrightarrow3x+9-36+6x+6+4x+8=0\)
\(\Leftrightarrow13x-13=0\)
\(\Leftrightarrow13x=13\)
hay x=1
Vậy: x=1
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Bài 1 : Tìm x, biết:
a) \(\left(\frac{1}{5}-\frac{3}{4}\right)x-1,52=-0,48\)
b,I x - 2 I - 1,5x = \(\frac{3}{4}+\frac{5}{4}x\)
c, \(\frac{5x}{0,75}=x:8\)
d, \(\frac{-6}{3x-2}=\frac{4}{x-1}\)
Giúp mik vs mai mik thi rùi!!!
Giúp mình với ạ:
1) (0,4x-2) - (1,5x+1)- (-4x-0,8)=3,6
2) \(\left(\frac{3}{4}x+3\right)-\left(\frac{2}{3}x-4\right)-\left(\frac{1}{6}x+1\right)=\left(\frac{1}{3}x+4\right)-\left(\frac{1}{3}x-3\right)\)
3) x+2x+3x+4x+...+100x=-21
1 . left(3x-2right)left(x^2-1right)left(9x^2-4right)left(x+1right)2 . frac{7}{8}x-5left(x-9right)frac{20x+1,5}{6}3 . 4left(0,5-1,5xright)frac{5x-6}{3}4 . left(3x-1right)left(x^2+2right)left(3x-1right)left(7x-10right)5 . frac{8x^2}{3left(1-4x^2right)}+frac{1}{2x+7}frac{6}{x^2-9}
Đọc tiếp
1 . \(\left(3x-2\right)\left(x^2-1\right)=\left(9x^2-4\right)\left(x+1\right)\)
2 . \(\frac{7}{8}x-5\left(x-9\right)=\frac{20x+1,5}{6}\)
3 . \(4\left(0,5-1,5x\right)=\frac{5x-6}{3}\)
4 . \(\left(3x-1\right)\left(x^2+2\right)=\left(3x-1\right)\left(7x-10\right)\)
5 . \(\frac{8x^2}{3\left(1-4x^2\right)}+\frac{1}{2x+7}=\frac{6}{x^2-9}\)
Mấy câu như vậy bạn tải photomath về dùng nhé :)