=???????????

tinh nhanh 2 bai nay giup mk di ma cac ban oi

tìm x 275% : x - 3/4 : x + 1,2  : x = 1,6                                                       giúp mik với, ai làm đg mik tick ng đó!!!

\(\frac{2,4\times1994\times2+1,6\times3996\times3+1,2\times4010\times4}{3+7+11+...+95+99-275}\)

\(=\frac{0,2\times6\times2\times2\times997\times2+0,2\times8\times6\times666\times3+0,2\times6\times2\times2005\times4}{\left(99+3\right)\times49:2-275}\)

\(=\frac{0,2\times6\times8\times997+0,2\times8\times6\times666\times3+0,2\times6\times8\times2005}{2499-275}\)

\(=\frac{0,2\times6\times8\times\left(997+666\times3+2005\right)}{2224}\)

\(=\frac{0,2\times2\times3\times8\times\left(997+1998+2005\right)}{8\times2\times0,2\times695}\)

\(=\frac{3\times\left(2995+2005\right)}{695}\)

\(=\frac{3\times5000}{695}=\frac{3\times1000\times5}{5\times139}\)

\(=\frac{3\times1000}{139}=\frac{3000}{139}\)

\(2,4\times1994\times2+1,6\times3996\times3+4,8\times4010\)
\(=4,8\times1994+4,8\times3996+4,8\times4010\)
\(=4,8\times\left(1994+3996+4010\right)\)
\(=4,8\times10000=48000\)

b)  3+7+11+15+...+95+99-27

= (3+99)x49-27

=4998-27

=4971

360125

6177

ban ơi ghi cách tính nhah hộ mk nha

1. 2,4 x 1994 x 2 + 1,6 x 3996 x 3 + 1,2 x 4010 x 4

= ( 2,4 x 1994 x 2 ) + ( 1,6 x 3996 x 3 ) + ( 1,2 x 4010 x 4 )

= ( 2,4 x 2 x 1994 ) + ( 1,6 x 3 x 3996 ) + ( 1,2 x 4 x 4010 )

=       4,8 x 1994     +        4,8 x 3996   +       4,8 x 4010

=      4,8 x ( 1994 + 3996 + 4010 )

=      4,8 x           10 000

=               48000

2. 3 + 7 + 11 + 15 +........+ 95 + 99 - 275

= [ ( 99 - 3 ) : 4 + 1 ] - 275

=    25             - 275

= [ ( 99 + 3 ) x 25 : 2 ] - 275

=       1275                 - 275

=                  1000

kick mình nhé bạn

1/48000

2/chịu

mik cũng có câu hỏi như thế này ,các bn giải thik giúp mik đc ko

 BÚ

Đề bạn có mấy chỗ thiếu mk bổ sung nha

\(a,2^3+4^2+6x=8+16+6x=6x+24=x\left(x+4\right)\\ b,x^2-4=\left(x-2\right)\left(x+2\right)\\ c,x^2-10x+25=\left(x-5\right)^2\\ d,x^3-4x=x\left(x^2-4\right)=x\left(x-2\right)\left(x+2\right)\\ e,x^2+xy-3x-3y=x\left(x+y\right)-3\left(x+y\right)=\left(x-3\right)\left(x+y\right)\\ g,x^2-y^2-4x+4=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x+y-2\right)\)

Tick plzz

a: Ta có: \(2x^3+4x^2+6x\)

\(=2x\left(x^2+2x+3\right)\)

b: \(x^2-4=\left(x-2\right)\left(x+2\right)\)

c: \(x^2-10x+25=\left(x-5\right)^2\)

d: \(x^3-4x=x\left(x-2\right)\left(x+2\right)\)

e: \(x^2+xy-3x-3y\)

\(=x\left(x+y\right)-3\left(x+y\right)\)

\(=\left(x+y\right)\left(x-3\right)\)

g: \(x^2-4x+4-y^2\)

\(=\left(x-2\right)^2-y^2\)

\(=\left(x-y-2\right)\left(x+y-2\right)\)