huhuhuhu help me cứi tui

Bài 1:

Ta có: \(4-2\left(x+1\right)=2\)

\(\Leftrightarrow2\left(x+1\right)=2\)

\(\Leftrightarrow x+1=1\)

hay x=0

Bài 2: 

Ta có: \(\left|2x-3\right|-1=2\)

\(\Leftrightarrow\left|2x-3\right|=3\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=6\\2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)

chưa biết

Mình nghĩ bạn chép sai đề rồi. Hãy kiểm tra và sửa lại đề nhé

\(4^{x+3}-3.4^{x+1}=13.4^{11}\)

\(\Rightarrow4^{x+1}.\left(4^2-3\right)=13.4^{11}\)

\(\Rightarrow4^{x+1}.\left(16-3\right)=13.4^{11}\)

\(\Rightarrow4^{x+1}.13=13.4^{11}\)

\(\Rightarrow x+1=11\)

\(\Rightarrow x=11-1\)

\(\Rightarrow x=10\)

\(\Rightarrow4^x\left(4^3-3.4\right)=13.4^{11}\)

\(\Rightarrow4^x.52=13.4^{11}\)

\(\Rightarrow4^x=4^{\left(-1\right)}.4^{11}\)

\(\Rightarrow4^x=4^{10}\)

=> x=10

\(4^{x+3}-3.4^{x+1}=13.4^{11}\)

\(\Leftrightarrow4^{x+1}.4^2-3.4^{x+1}=13.4^{11}\)

\(\Leftrightarrow4^{x+1}\left(4^2-3\right)=13.4^{11}\)

\(\Leftrightarrow4^{x+1}.13=13.4^{11}\)

\(\Leftrightarrow4^{x+1}=4^{11}\)

\(\Leftrightarrow x+1=11\)

\(\Leftrightarrow x=10\)

a.

\(\left(\frac{11}{12}+\frac{11}{12\times23}+\frac{11}{23\times34}+...+\frac{11}{89\times100}\right)+x=\frac{2}{3}\)

\(\left(\frac{11}{12}+\frac{1}{12}-\frac{1}{23}+\frac{1}{23}-\frac{1}{34}+...+\frac{1}{89}-\frac{1}{100}\right)+x=\frac{2}{3}\)

\(\left(\frac{11}{12}+\frac{1}{12}-\frac{1}{100}\right)+x=\frac{2}{3}\)

\(\left(\frac{12}{12}-\frac{1}{100}\right)+x=\frac{2}{3}\)

\(\left(1-\frac{1}{100}\right)+x=\frac{2}{3}\)

\(\left(\frac{100-1}{100}\right)+x=\frac{2}{3}\)

\(\frac{99}{100}+x=\frac{2}{3}\)

\(x=\frac{2}{3}-\frac{99}{100}\)

\(x=\frac{200-297}{300}\)

\(x=-\frac{97}{300}\)

b.

\(\left(\frac{2}{11\times13}+\frac{2}{13\times15}+...+\frac{2}{19\times21}\right)-x+\frac{221}{231}=\frac{4}{3}\)

\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)+\frac{221}{231}-x=\frac{4}{3}\)

\(\left(\frac{1}{11}-\frac{1}{21}\right)+\frac{221}{231}-x=\frac{4}{3}\)

\(\left(\frac{21-11}{231}\right)+\frac{221}{231}-x=\frac{4}{3}\)

\(\frac{10}{231}+\frac{221}{231}-x=\frac{4}{3}\)

\(\frac{231}{231}-x=\frac{4}{3}\)

\(1-x=\frac{4}{3}\)

\(x=1-\frac{4}{3}\)

\(x=\frac{3-4}{3}\)

\(x=-\frac{1}{3}\)

Chúc bạn học tốt

( 4,5 - 2.x ) . 11/7 = 11/14

4,5 - 2.x               = 11/14 : 11/7= 1/2

         2.x             =  4,5 - 1/2 =4

             x  = 4:2=2

\(\left(4,5-2x\right).1\frac{4}{7}=\frac{11}{14}\)

\(\Rightarrow\left(4,5-2x\right).\frac{11}{7}=\frac{11}{14}\)

\(\Rightarrow4,5-2x=\frac{11}{14}:\frac{11}{7}\)

\(\Rightarrow4,5-2x=\frac{11}{14}.\frac{7}{11}\)

\(\Rightarrow4,5-2x=\frac{1}{2}\)

\(\Rightarrow2x=4,5-\frac{1}{2}\)

\(\Rightarrow2x=4,5-0,5\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=4:2\)

\(\Rightarrow x=2\)

x\(\in\){11;-22}

\(|x-11|+x-11=0\)

\(|x-11|+x=11+0\)

\(|x-11|+x=11\)

\(x=11-11\)

\(x=0\)

Hk tốt,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

k nhé

-22 nữa bạn!

\(4^{x+3}-3.4^{x+1}=13.4^{11}\)

\(16.4^{x+1}-3.4^{x+1}=13.4^{11}\)

\(\left(16-3\right).4^{x+1}=13.4^{11}\)

\(13.4^{x+1}=13.4^{11}\)

\(\Rightarrow x+1=11\)

\(x=10\)

\(4^{x+3}-3.4^{x+1}=13.4^{11}\)

=> \(4^{x+1}.\left(4^2-3\right)=13.4^{11}\)

=> \(4^{x+1}.\left(16-3\right)=13.4^{11}\)

=> \(4^{x+1}.13=13.4^{11}\)

=> \(x+1=11\)

=> \(x=11-1=10\)

\(4^{x+3}-3.4^{x+1}=13.4^{11}\Rightarrow4^{x+1}.4^2-3.4^{x+1}=13.4^{11}\Rightarrow4^{x+1}\left(4^2-3\right)=13.4^{11}\)

\(\Rightarrow4^{x+1}\left(16-3\right)=13.4^{11}\Rightarrow4^{x+1}.13=13.4^{11}\Rightarrow x+1=11\Rightarrow x=10\)

a, 11/12 - ( 2/5 + x ) = 2/3

<=> \(\frac{2}{5}+x=\frac{11}{12}-\frac{2}{3}=\frac{1}{4}\)

=> x=\(\frac{1}{4}-\frac{11}{12}=-\frac{2}{3}\)

b, 2x . ( x - 1/7 ) = 0

<=>\(\left[\begin{array}{nghiempt}x=0\\x-\frac{1}{7}=0\end{array}\right.\)<=> \(\left[\begin{array}{nghiempt}x=0\\x=\frac{1}{7}\end{array}\right.\)

vậy x={\(0;\frac{1}{7}\)}

c, 3/4 + 1/4 : x = 2/5

<=>\(\frac{1}{4}:x=\frac{2}{5}-\frac{3}{4}=-\frac{7}{20}\)

<=> \(x=\frac{1}{4}:\left(-\frac{7}{20}\right)=-\frac{5}{7}\)

vậy x=-5/7

a) \(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)

\(\Leftrightarrow\frac{11}{12}-\frac{2}{5}-x=\frac{2}{3}\)

\(\Leftrightarrow-x=\frac{2}{3}-\frac{11}{12}+\frac{2}{5}=\frac{3}{20}\)

\(\Leftrightarrow x=-\frac{3}{20}\)

b) \(2x\left(x-\frac{1}{7}\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x-\frac{1}{7}=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x=\frac{1}{7}\end{array}\right.\)

c) \(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)

\(\Leftrightarrow\frac{1}{4x}=\frac{2}{5}-\frac{3}{4}=-\frac{7}{20}\)

\(\Leftrightarrow4x=\frac{-20}{7}\)

\(\Leftrightarrow x=-\frac{5}{7}\)

a) \(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)

\(\frac{2}{5}+x=\frac{11}{12}-\frac{2}{3}\)

\(\frac{2}{5}+x=\frac{1}{4}\)

\(x=\frac{1}{4}-\frac{2}{5}\)

\(x=-\frac{3}{20}\)

Vậy \(x=-\frac{3}{20}\)

b) \(2x\left(x-\frac{1}{7}\right)=0\)

\(\Rightarrow\begin{cases}2x=0\\x-\frac{1}{7}=0\end{cases}\Rightarrow\begin{cases}x=0\\x=\frac{1}{7}\end{cases}\)

Vậy x = 0 hoặc \(x=\frac{1}{7}\)

c) \(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)

\(\frac{1}{4}:x=\frac{2}{5}-\frac{3}{4}\)

\(\frac{1}{4}:x=-\frac{7}{20}\)

\(x=\frac{1}{4}:\left(-\frac{7}{20}\right)\)

\(x=-\frac{5}{7}\)

Vậy \(x=-\frac{5}{7}\)