51/35=x+25/48
Tìm số nguyên x biết
a. x-43=(35-x)-48 ; b. 305-x=14=48=(x-23)
c. -(x-6+85)=(x+51)-54 , d. -(35-x)-(37-x)=33-x
1) x - 43 = ( 35 - x ) - 48
2) 305 - x + 14 = 48 + ( x - 23 )
3) - ( x - 6 + 85 ) = ( x + 51 ) - 54
4) - ( 35 - x ) - ( 37 - x ) = 33 - x
5) 13 - | x | = | -4 |
1,x-43=(35-x)-48
=>x-43=35-x-48
=>x+x=35-48+43
=>2x=30
=>x=15
Vậy x=15
2,305-x+14=48+(x-23)
=>305-x+14=48+x-23
=>305+14+23-48=x+x
=>294=2x
=>x=294:2
=>x=147
3,-(x-6+85)=(x+51)-54
=>-x+6-85=x+51-54
=>6-85-51+54=x+x
=>-76=2x
=>x=(-76):2
=>x=-38
4,-(35-x)-(37-x)=33-x
=>-35+x-37+x=33-x
=>-35+(-37)+(-33)=-x-x-x
=>-105=-3x
=>x=(-105):(-3)
=>x=35
5,13-\(|x|=|-4|\)
=>13-\(|x|\)=4
=>13-4=\(|x|\)
=>9=\(|x|\)
=>x=9 hoặc x=-9
5) 13 - |x| = |-4|
=> 13 - |x| = 4
|x| = 13-4 = 9
Vậy x=9 hoặc x=-9
4) - (35-x) - (37-x) = 33-x
<=>-35 + x - 37 + x = 33-x
<=> -35 - 37 + x + x = 33-x
-72 + 2x = 33 - x
Theo quy tắc chuyển vế, ta có
-72 - 33 = - 2x + x
-105 = - (2x+x)
-105 = -3x
=> x = (-105) : (-3) = 35
Vậy x=35
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Tìm số nguyên x:
1.x-43=(35-x)-48
2.305-x+14=48+(x-23)
3.-(x-6+85)=(x+51)-54
4.-(35-x)-(37-x)=33-x
5.13-|x|=|-4|
6.|x|-3+6=16
7.35-|2x-1|=14
8.|3x-2|+5=9-x
9.x-(-25+7)>12-(15-14)
10.|17+(x-15)|<5
1.\(x-43=\left(35-x\right)-48\)
\(\Rightarrow x-43=35-x-48\)
\(\Rightarrow2x=35+43-48\)
\(\Rightarrow2x=30\)
\(\Rightarrow x=15\)
2.\(305-x+14=48+\left(x-23\right)\)
\(\Rightarrow305-x+14=48+x-23\)
\(\Rightarrow305+14=48+x+x-23\)
\(\Rightarrow2x+25=319\)
\(\Rightarrow2x=294\)
\(\Rightarrow x=147\)
3.\(-\left(x-6+85\right)=\left(x+51\right)-54\)
\(\Rightarrow-x+6-85=x+51-54\)
\(\Rightarrow6-85=x+x+51-54\)
\(\Rightarrow2x-3=-79\)
\(\Rightarrow2x=-76\)
\(\Rightarrow x=-38\)
4.\(-\left(35-x\right)-\left(37-x\right)=33-x\)
\(\Rightarrow-35+x-37+x=33-x\)
\(\Rightarrow2x-72=33-x\)
\(\Rightarrow3x=105\)
\(\Rightarrow x=35\)
5.\(13-\left|x\right|=\left|-4\right|\)
\(\Rightarrow13-\left|x\right|=4\)
\(\Leftrightarrow\left[{}\begin{matrix}13-x=4\\13+x=4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=9\\x=-9\end{matrix}\right.\)
tính nhanh
37 x 46 + 37 x 51 + 111
172 x 47 + 86 x8 - 34 x4
35 x 215 - 35 x 210 -175
48 x 56 + 28 x104
\(37\times46+37\times51+111\)
\(=37\times46+37\times51+37\times3\)
\(=37\times\left(46+51+3\right)\)
\(=37\times100\)
\(=3700\)
------------
\(172\times47+86\times8-34\times4\)
\(=172\times47+172\times4-34\times4\)
\(=172\times\left(47+4\right)-34\times4\)
\(=172\times51-34\times4\)
\(=172\times3\times17-17\times2\times4\)
\(=17\times\left(172\times3-2\times4\right)\)
\(=17\times\left(516-8\right)\)
\(=17\times508\)
\(=8636\)
------------
\(35\times215-35\times200-175\)
\(=35\times215-35\times200-35\times5\)
\(=35\times\left(215-200-5\right)\)
\(=35\times10\)
\(=350\)
------------
\(48\times56+28\times104\)
\(=48\times2\times28+28\times104\)
\(=28\times\left(48\times2+104\right)\)
\(=28\times200\)
\(=5600\)
3) tìm x thuộc z, biết
a) x-43=(35-x)-48
b) 305-x+14=48+(x-23)
c) -(-x -6+85)=(x+51)-54
d)-(35-x)-(37-x)= 33-x
a: \(x-43=\left(35-x\right)-48\)
=>\(x-43=35-x-48\)
=>\(x-43=-x-13\)
=>\(x+x=-13+43\)
=>2x=30
=>x=30/2=15
b: \(305-x+14=48+\left(x-23\right)\)
=>\(319-x=48+x-23=25+x\)
=>\(x+25=319-x\)
=>\(x+x=319-25\)
=>\(2x=294\)
=>\(x=\dfrac{294}{2}=147\)
c: \(-\left(-x-6+85\right)=\left(x+51\right)-54\)
=>\(-\left(-x+79\right)=x+51-54\)
=>x-79=x-3
=>-79=-3(vô lý)
=>\(x\in\varnothing\)
d: \(-\left(35-x\right)-\left(37-x\right)=33-x\)
=>\(-35+x-37+x=33-x\)
=>2x-72=-x+33
=>\(2x+x=33+72\)
=>3x=105
=>\(x=\dfrac{105}{3}=35\)
tính
25 . 48 + 25 . 51 + 300 + 25
\(25\cdot48+25\cdot51+300+25\\ =25\cdot48+25\cdot51+25\cdot12+25\cdot1\\ =25\cdot\left(48+51+12+1\right)\\ =25\cdot112=2800\)
Tìm số nguyên x biết :
1)x-43=(35-x)-48
2)-(x-6+85)=(x+51)-54
3)|-7-(x+3)|=3
\(x-43=35-x-48\)
\(x+x=43+35-48=30\)
2.x=30=> x=15
2) -x+6-85=x+51-54
-x-79=x-3
2x=76=> x=38
3)\(\orbr{\begin{cases}-7-x-3=-3\Rightarrow x=-7\\-7-x-3=3\Rightarrow x=-13\end{cases}}\)
Tính nhanh
A) 37 x 46 + 37 x 51 + 111
B) 35 x 215 - 35 x 210 - 175
E) 76 x 102 - 76 x 2
C) 85 x 94 + 85 x 2 + 170 x 2
48 x 56 + 28 x 104
G) 206 x 12 - 206 - 206
`@` `\text {Ans}`
`\downarrow`
`A)`
`37 \times 46+37 \times 51+111`
`= 37 \times (46+51)+111`
`= 37 \times 97+111`
`= 3589 +111`
`= 3700`
`B)`
`35 \times 215-35 \times 210-175`
`= 35 \times (215-210)-175`
`= 35 \times 5-175`
`= 175-175=0`
`E)`
`76 \times 102-76 \times 2`
`= 76 \times (102-2)`
`= 76 \times 100`
`= 7600`
`C)`
`85 \times 94+85 \times 2 +170 \times 2`
`= 85 \times (94+2) + 170 \times 2`
`= 85 \times 96+170 \times 2`
`= 8160+340`
`= 8500`
`48 \times 56+28 \times 104`
`= 48 \times 28 \times 2+28 \times 104`
`= 28 \times (48 \times 2+104)`
`= 28 \times (96+104)`
`= 28 \times 200`
`= 5600`
`G)`
`206 \times 12-206-206`
`= 206 \times (12-1-1)`
`= 206 \times 10`
`= 2060`
a) 37 x 46 + 37 x 51 + 111
= 37 x ( 46 + 51 ) + 111
= 37 x 97 + 111
= 3589 + 111
= 3700
b) 35 x 215 - 35 x 210 - 175
= 35 x ( 215 - 210 ) - 175
= 35 x 5 - 175
= 175 - 175
= 0
e) 76 x 102 - 76 x 2
= 76 x ( 102 - 2 )
= 76 x 100
= 7600
c) 85 x 94 + 95 x 2 + 170 x 2
= 7990 + 2 x ( 95 + 170 )
= 7990 + 2 x 265
= 7990 + 530
= 8520
48 x 56 + 28 x 104
= 2688 + 2912
= 5600
g) 206 x 12 - 206 - 206
= 2472 - 206 - 206
= 2266 - 206
= 2060
giải phương trình sau
\(\dfrac{x-50}{50}+\dfrac{x-51}{49}+\dfrac{x-52}{48}+\dfrac{x-53}{47}+\dfrac{x-200}{25}=0\)
Ta có : \(\dfrac{x-50}{50}+\dfrac{x-51}{49}+\dfrac{x-52}{49}+\dfrac{x-53}{47}+\dfrac{x-200}{25}=0\)
\(\Leftrightarrow\dfrac{x-50}{50}-1+\dfrac{x-51}{49}-1+\dfrac{x-52}{49}-1+\dfrac{x-53}{47}-1+\dfrac{x-200}{25}+4=0\)
\(\Leftrightarrow\dfrac{x-100}{50}+\dfrac{x-100}{49}+\dfrac{x-100}{49}+\dfrac{x-100}{47}+\dfrac{x-100}{25}=0\)
\(\Leftrightarrow\left(x-100\right)\left(\dfrac{1}{50}+\dfrac{1}{49}+\dfrac{1}{48}+\dfrac{1}{47}+\dfrac{1}{25}\right)=0\)
<=> x - 100 = 0
<=> x = 100
Vậy ..
Ta có: \(\dfrac{x-50}{50}+\dfrac{x-51}{49}+\dfrac{x-52}{48}+\dfrac{x-53}{47}+\dfrac{x-200}{25}=0\)
\(\Leftrightarrow\dfrac{x-50}{50}-1+\dfrac{x-51}{49}-1+\dfrac{x-52}{48}-1+\dfrac{x-53}{47}-1+\dfrac{x-200}{25}+4=0\)
\(\Leftrightarrow\dfrac{x-100}{50}+\dfrac{x-100}{49}+\dfrac{x-100}{48}+\dfrac{x-100}{47}+\dfrac{x-100}{25}=0\)
\(\Leftrightarrow\left(x-100\right)\left(\dfrac{1}{50}+\dfrac{1}{49}+\dfrac{1}{48}+\dfrac{1}{47}+\dfrac{1}{25}\right)=0\)
mà \(\dfrac{1}{50}+\dfrac{1}{49}+\dfrac{1}{48}+\dfrac{1}{47}+\dfrac{1}{25}>0\)
nên x-100=0
hay x=100
Vậy: S={100}