cho S= 3/1.4 cong 3/4.7 cong 3/7.10 cong . . . cong 3/40.43 cong 3/ 43.46 .Hay chung to rang Slon hon 1
Cho S=3/1.4+3/4.7+3/7.10+...+3/40.43+3/32+46 .Hay chung to rang S<1
chung to rang B = 1/2mu 2 cong 1/3 mu 2 cong 1/4 mu 2 cong 1/5 mu 2 cong 1/6 mu 2cong 1/7 mu 2 cong 1/8 mu2 nho hon 1
S=3/1.4+3/4.7+3/7.10+...+3/40.43+43.46 CHứng minh S<1
\(S=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{40.43}+\frac{3}{43.46}\)
\(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{40}-\frac{1}{43}+\frac{1}{43}-\frac{1}{46}\)
\(=1-\frac{1}{46}
Cho S=3/1.4+3/4.7+3/7.10+...+3/40.43+3/43.46 . Chứng tỏ rằng S<1
\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{40.43}+\frac{3}{43.46}\)
\(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{10}-\frac{1}{43}+\frac{1}{43}-\frac{1}{46}\)
\(=1-\frac{1}{46}\)
Vì \(1-\frac{1}{46}\) < 1
=> \(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{40.43}+\frac{3}{43.46}\) < 1
cho S= \(\dfrac{3}{1.4}+\dfrac{3}{4.7}+\dfrac{3}{7.10}+...+\dfrac{3}{40.43}+\dfrac{3}{43.46}\)
Hãy chứng tỏ rằng S<1
\(S=\dfrac{3}{1.4}+\dfrac{3}{4.7}+\dfrac{3}{7.10}+...+\dfrac{3}{40.43}+\dfrac{3}{43.46}\\ S=1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+...+\dfrac{1}{40}-\dfrac{1}{43}+\dfrac{1}{43}-\dfrac{1}{46}\\ S=1-\dfrac{1}{46}< 1\)
Vậy S < 1 (đpcm)
CHO S : 3/1.4 + 3/4.7 + 3/7.10 ... + 3/40.43 + 3/43.46
HÃY CHỨNG TỎ RẰNG S <1
\(S=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+.....+\frac{1}{43}-\frac{1}{46}..\)
\(S=1-\frac{1}{46}< 1\)
VẬY S<1
\(S=\frac{3}{1.4} +\frac{3}{4.7}+\frac{3}{7.10}+....+\frac{3}{40.43}+\frac{3}{43.46}\)
\(S=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{40}-\frac{1}{43}+\frac{1}{43}-\frac{1}{46}\)
\(S=1-\frac{1}{46}\)
=> S<1 (ĐCCM)
Bạn có cần giải thích tại sao tách được các phân số như thế không?
Cho 3 so nguyen p ; p cong 2014.k;p cong 2015.k la cac so nguyen to lon hon 3 va p chia cho 3 du 1.Chung minh rang k chia het cho 6
S=3/1.4 +3/4.7 +3/7.10 +...+3/40.43 +3/43.46
S=1-1/4+1/4-1/7+1/7-1/10+...+1/40-1/43+1/43-1/46
S=1-1/46 S=45/46<1
vậy S <1
!!!
S=1-1/4+1/4-1/7+......+1/43 - 1/46
= 1-1/46
= 45/46
S=1-1/4+1/4-1/7+......+1/43 - 1/46
= 1-1/46
= 45/46
Cho S= 3/1.4+3/4.7+3/7.10+.......3/40.43+3/43.46.
Hãy chứng tỏ rằng S<1
\(S=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{40.43}+\frac{3}{43.46}\)
\(=\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{40}-\frac{1}{43}+\frac{1}{43}-\frac{1}{46}\)
\(=1-\frac{1}{46}< 1\)
Vậy S<1
xin lỗi minh triều bạn làm kiểu này mình ko hiểu