rút gọn:
\(\frac{2^{19}.27^3-15.\left(-4\right)^9.9^4}{6^9.2^{10}+\left(-12\right)^{10}}\)
\(\frac{2^{19}.27^3-15.\left(-4\right)^9.9^4}{6^9.2^{10}+\left(-12\right)^{10}}\)
a) \(\frac{2^{19}.2^{27}+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)
b) \(\frac{\left(-\frac{1}{2}\right)^3-\left(\frac{3}{4}\right)^3-\left(-2\right)^2}{2.\left(-1\right)^5+\left(\frac{3}{4}\right)^2-\frac{3}{8}}\)
Rút gọn
Tính
\(C=\frac{2^{19}.27^3-15.\left(-4\right)^9.9^4}{6^9.2^{10}+\left(-12\right)^{10}}\)
Mik đã k Magicpencil
=\(\frac{1}{2}\)
\(\dfrac{2^{19}.27^3-15.\left(-4\right)^9.9^4}{6^9.2^{10}+\left(-12\right)^{10}}\)
kết quả cuối cùng =1/2
/ phần nha bạn
nếu đúng thì tick cho mk nha
Thực hiện phép tính :
\(H=\frac{2^{19}.27^3.5-15.\left(-4\right)^9.9^4}{6^9.2^{10}-\left(-12\right)^{10}}\)
Tử số: 2^19 x (3^3)^3 x 5+15 x 4^9 x(3^2)^4
=2^19 x3^9x5 + 15 x(2^2)^9 x 3^8
= 2^19 x 3^9 x 5 +3 x 5 x 2^18 x 3^8
= 2^19 x 3^9 x 5+ 3^9 x 5 x 2^18
= 5 x 3^9 x 2^18 (2+1)
=5 x 3^10 x 2^18
Mẫu số
= (2 x 3)^9 x 2^10 -12^10
= 2^9 x 3^9 x 2^10 - (2^2x3)^10
= 2^9 x 3^9 x 2^10 -2^20 x 3^10
= 2^19 x 3^9 - 2^20 x 3^10
= 2^19 x 3^9 (1-2 x 3)
= 2^19 x 3^9 x(-5)
Chia cả tử và mẫu ta có
(5 x 3^10 x 2^18) / (2^19 x 3^9 x (-5)) = -3/2
\(H=\frac{2^{19}.27^3.5-15.\left(-4\right)^9.9^4}{6^9.2^{10}-\left(-12\right)^{10}}\)
\(\Rightarrow\)\(H=\frac{2^{19}.3^9.5-3.5-1.2^{18}.3^8}{2^9.3^9.2^{10}-6^{10}.2^{10}}=\frac{2^{19}.3^9.5-3^9.5-2^{18}}{2^{19}.3^9-3^{10}.2^{10}.2^{10}}=\frac{2^{19}.3^9.5-3^9.5-2^{18}}{2^{19}.3^9-3^{10}.2^{20}}\)
\(\Rightarrow H=\frac{2^{18}.3^9.5\left(2-1\right)}{2^{19}.3^9.\left(1-3.2\right)}=\frac{5}{2.\left(-5\right)}=\frac{-1}{2}\)
Vậy \(H=\frac{-1}{2}\)
\(\dfrac{2^{19}.27^3-15.\left(-4\right)^9.9^4}{6^9.2^{10}+\left(-12\right)^{10}}\)
Help me!
=\(\dfrac{2^{19}.27^3-15.\left(-4\right)^9.9^4}{6^9.2^{10}+\left(-12\right)^{10}}\)
=\(\dfrac{2^{19}.3^9-2^{18}.3^9.5}{6^9.2^{10}+6^{10}.2^{10}}\)
=\(\dfrac{2^{18}.3^9\left(2-2.5\right)}{6^9.2^{10}\left(1+6\right)}\)
=\(\dfrac{2^{18}.3^9.\left(-8\right)}{3^9.2^{19}.7}\)
=\(\dfrac{-8}{14}=\dfrac{-4}{7}\)
Tính giá trị biểu thức :
\(H=\frac{2^{19}.27^3.5-15.\left(-4\right)^9.9^4}{6^9.2^{10}-\left(-12\right)^{10}}\)
thưc hiện phép tính:
H = \(\dfrac{2^{19}.27^3.5-15.\left(-4\right)^9.9^4}{6^9.2^{10}-\left(-12\right)^{10}}\)
\(H=\dfrac{2^{19}\cdot3^9\cdot5+3\cdot5\cdot2^{18}\cdot3^8}{2^9\cdot2^{10}\cdot3^9-2^{20}\cdot3^{10}}\)
\(=\dfrac{2^{19}\cdot3^9\cdot5+2^{18}\cdot3^9\cdot5}{2^{19}\cdot3^9-2^{20}\cdot3^{10}}\)
\(=\dfrac{2^{18}\cdot3^9\cdot5\cdot\left(2+1\right)}{2^{19}\cdot3^9\cdot\left(1-6\right)}\)
\(=\dfrac{1}{2}\cdot\dfrac{5\cdot3}{-5}=-\dfrac{1}{2}\cdot3=-\dfrac{3}{2}\)
Rút gọn: a)\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}.12^{10}}\)
b)\(\frac{\left(-\frac{1}{2}\right)^3-\left(\frac{3}{4}\right)^3.\left(-2\right)^2}{2.\left(-1\right)^5+\left(\frac{3}{4}\right)^2-\frac{3}{8}}\)
Tìm x
a)\(3^{x+1}=9^x\)
b)\(2^{3x+2}=4^{x+5}\)
c)\(3^{2x-1}=243\)