Từ FeSO4 ---> Fe(OH)3???
Fe(OH)2=>Fe(OH)3 ; Fe2(SO4)3=>FeSO4 ; FeSO4=>Fe(OH)2
\(4Fe(OH)_2 + O_2 + 2H_2O \to 4Fe(OH)_3\\ Fe_2(SO_4)_3 + Cu \to CuSO_4 + 2FeSO_4\\ FeSO_4 + 2KOH \to Fe(OH)_2 + K_2SO_4\)
\(4Fe\left(OH\right)_2+2H_2O+O_2\rightarrow4Fe\left(OH\right)_3\)
\(Fe_2\left(SO_4\right)_3+Fe\rightarrow3FeSO_4\)
\(FeSO_4+2KOH\rightarrow K_2SO_4+Fe\left(OH\right)_2\downarrow\)
từ Fe,S,H2O,Na ,viết PTHH điều chế FeSo4,Fe2(so40)3,Fe(oh)3
\(S+O_2\xrightarrow[]{t^o}SO_2\)
\(SO_2+H_2O+\dfrac{1}{2}O_2\rightarrow H_2SO_4\)
\(Fe+H_2SO_4\rightarrow H_2+FeSO_4\) (*)
\(4Fe+3O_{2\left(dư\right)}\xrightarrow[]{t^ocao}2Fe_2O_3\)
\(Fe_2O_3+3H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+3H_2O\) (*)
\(Na+H_2O\rightarrow NaOH+\dfrac{1}{2}H_2\uparrow\)
\(Fe_2\left(SO_4\right)_3+6NaOH\rightarrow3Na_2SO_4+2Fe\left(OH\right)_3\downarrow\) (*)
Bài 3: Hoàn thành chuỗi phản ứng sau:
a. Al → Al2O3→Al2(SO4)3→Al(OH)3 →Al2O3→Al →NaAlO2
b.Al→AlCl3→Al(NO3)3→Al(OH)3→Al2(SO4)3→AlCl3→Al
c. Fe→FeCl2→Fe(OH)2→FeSO4→Fe(NO3)2→Fe→Fe3O4→Fe
d.Fe→FeCl3→Fe→Fe3O4→FeSO4.
Bài 3: Hoàn thành chuỗi phản ứng sau:
a. Al → Al2O3→Al2(SO4)3→Al(OH)3 →Al2O3→Al →NaAlO2
b.Al→AlCl3→Al(NO3)3→Al(OH)3→Al2(SO4)3→AlCl3→Al
c. Fe→FeCl2→Fe(OH)2→FeSO4→Fe(NO3)2→Fe→Fe3O4→Fe
d.Fe→FeCl3→Fe→Fe3O4→FeSO4.
Fe-->Fecl2--->Fe(OH)2--->FeSO4---->Fe Fe-->FeCl3--->Fe(OH)3--->Fe203--->Fe Al-->AlCl3-->Al(OH)3-->Al2O3--->Al
Dãy 1 :
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
\(FeCl_2+2NaOH\rightarrow Fe\left(OH\right)_2+2NaCl\)
\(Fe\left(OH\right)_2+H_2SO_4\rightarrow FeSO_4+2H_2O\)
\(FeSO_4+Zn\rightarrow ZnSO_4+Fe\)
Dãy 2 :
\(2Fe+3Cl_2\xrightarrow[]{t^o}2FeCl_3\)
\(FeCl_3+3KOH\rightarrow Fe\left(OH\right)_3+3KCl\)
\(2Fe\left(OH\right)_3\xrightarrow[]{t^o}Fe_2O_3+3H_2O\)
\(Fe_2O_3+3CO\xrightarrow[]{t^o}Fe+3CO_2\)
Dãy 3 :
\(2Al+3Cl_2\xrightarrow[]{t^o}2AlCl_3\)
\(AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\)
\(2Al\left(OH\right)_3\xrightarrow[]{t^o}Al_2O_3+3H_2O\)
\(2Al_2O_3\xrightarrow[criolit]{đpnc}4Al+3O_2\)
từ nước , không khí, FeS2, , muối ăn, hãy điều chế FeSO4,Fe(OH)3,NaHSO4
Tinh chế H2SO4:
4FeS2+11O2(t*)=>2Fe2O3+8SO2
2SO2+O2(V2O5,450*C)=>2SO3
SO3+H2O=>H2SO4
+FeSO4:
4FeS2+11O2(t*)=>2Fe2O3+8SO2
2NaCl+2H2O(đpmn)=>2NaOH+H2+Cl2
Fe2O3+3H2=>2Fe+3H2O
Fe+H2SO4=>FeSO4+H2
+Fe2(SO4)3:
4FeS2+11O2(t*)=>2Fe2O3+8SO2
Fe2O3+3H2SO4=>Fe2(SO4)3+3H2O
+Fe(OH)3:
2NaCl+2H2O(đpmn)=>2NaOH+H2+Cl2
H2+Cl2(t*)=>2HCl
4FeS2+11O2(t*)=>2Fe2O3+8SO2
Fe2O3+6HCl=>2FeCl3+3H2O
FeCl3+3NaOH=>Fe(OH)3+3NaCl
+Na2SO4:
2NaCl+2H2O(đpmn)=>2NaOH+H2+Cl2
2NaOH+H2SO4=>Na2SO4+2H2O
+NaHSO4:
2NaCl+2H2O(đpmn)=>2NaOH+H2+Cl2
NaOH+H2SO4=>NaHSO4+H2O
+Na2SO3:
4FeS2+11O2(t*)=>2Fe2O3+8SO2
2NaCl+2H2O(đpmn)=>2NaOH+H2+Cl2
SO2+2NaOH=>Na2SO3+H2O
Hoàn thành các PTHH sau
1.Fe+.................➜ FeSO4
2.FeSO4+.................➜ Fe(OH)2
3.Fe(SO4)3+...................➜ Fe(OH)3
4.Fe(OH)2+.................➜ FeO
5.Fe(OH)3+.................➜ Fe2O3
6.FeO+...................➜ FeCl2
7.Fe2O3+.................➜FeCl3
8.Fe+.................➜FeCl2
9.Fe+.................➜FeCl3
10.FeCl3+...............➜FeCl2
1.Fe+H2SO4.➜ FeSO4+H2
2.FeSO4+ NaOH➜ Fe(OH)2 + Na2SO4
3.Fe2(SO4)3+ 6NaOH➜ 2Fe(OH)3 +3Na2SO4
4.Fe(OH)2➜ FeO +H2O
5.2Fe(OH)3➜ Fe2O3 +3H2O
6.FeO+ 2HCl ➜ FeCl2 +H2O
7.Fe2O3+ 6HCl ➜2FeCl3 +3H2O
8.Fe+Cl2➜FeCl2
9.2Fe+6HCl ➜2FeCl3 +3H2
10.2FeCl3.➜2FeCl2 +Cl2
Chúc bạn học tốt
Nhớ tích cho mình nhé
Mình làm bạn tự cân bằng nhé:
1.Fe+......H2SO4...........➜ FeSO4 + H2
2.FeSO4+.........NaOH........➜ Fe(OH)2 + Na2SO4
3.Fe2(SO4)3+........NaOH...........➜ Fe(OH)3 + Na2SO4
4.Fe(OH)2 \(\underrightarrow{t^o}\) FeO + H2O
5.Fe(OH)3 \(\underrightarrow{t^o}\) Fe2O3 + H2O
6.FeO+........HCl...........➜ FeCl2 + H2O
7.Fe2O3+........HCl.........➜FeCl3 +H2O
8.Fe+......HCl...........➜FeCl2 +H2
9.Fe+........Cl2.........➜FeCl3
10.FeCl3+........Fe.......➜FeCl2
a) Al AbO3→ AlCl3 → Al(OH)3 → Al2O3 → Al→ Al2(SO4)3 → Al And ins b) Fe→FeCl3 → Fe(OH)3→ Fe2O3→ Fe → FeCl2→ Fe → FeSO4
a, \(2Al+3O_2\underrightarrow{t^o}2Al_2O_3\)
\(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)
\(AlCl_3+3NaOH\rightarrow3NaCl+Al\left(OH\right)_3\)
\(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)
\(Al_2O_3\underrightarrow{đpnc}2Al+\dfrac{3}{2}O_2\)
\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)
\(Al_2\left(SO_4\right)_3+3Mg\rightarrow3MgSO_4+2Al\)
b, \(2Fe+3Cl_2\underrightarrow{t^o}2FeCl_3\)
\(FeCl_3+3NaOH\rightarrow3NaCl+Fe\left(OH\right)_3\)
\(2Fe\left(OH\right)_3\underrightarrow{t^o}Fe_2O_3+3H_2O\)
\(Fe_2O_3+3H_2\underrightarrow{t^o}2Fe+3H_2O\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
\(Mg+FeCl_2\rightarrow MgCl_2+Fe\)
\(Fe+H_2SO_4\rightarrow FeSO_4+H_2\)
Hoàn thành các pt phản ứng sau
(34) MgSO4+. _______> Mgcl2
(35) MgCL2+ _____> Mg(OH)2
(36) Mg(OH)2 +. _______> MgCL2
(37) Mg(OH)2+. _______> MgSO4
(38) MgSO4 +. ______> Na2SO4
(39) MgSO4 +. _____> BaSO4
(40) CuSO4 +. ______> BaSO4
(41) CuSO4+. ______> FeSO4
(42) Fe2(SO4)3 +. ______> CuSO4
(43) FeSO4 +. _____> Fe2(SO4)3
(44) Fe2(SO4)3 +. ______> FeSO4
(45) FeSO4+. ______> Al2(SO4)3
(46) FeSO4+ _____> Na2SO4
(47) Na2CO3 +. _____> Al(OH)3
(48) Al(OH)3. +. _____> NaAlo2
(49) NaAlo2 +. ______> Al(OH)3
(50) Co2+. ______> Al(OH)3
(51) Fe(OH)2 +. ____> Fe(OH)3
(52) Fe(OH)3 +. ____> Fe2(SO4)3
(53) Fe(OH)2+. ____> Fe2(SO4)3
(34): MgSO4 + BaCl2 → MgCl2 + BaSO4↓
(35) MgCl2 + 2NaOH → Mg(OH)2↓ + 2NaCl
(36) Mg(OH)2 + 2HCl → MgCl2 + 2H2O
(37) Mg(OH)2 + H2SO4 → MgSO4 + 2H2O
(38) MgSO4 + 2NaOH → Na2SO4 + Mg(OH)2↓
(39) MgSO4 + BaCl2 → BaSO4↓ + MgCl2
(40) CuSO4 + Ba(OH)2 → BaSO4↓ + Cu(OH)2↓
(41) CuSO4 + Fe(OH)2 → FeSO4 + Cu(OH)2↓
(42) Fe2(SO4)3 + 3Cu(OH)2 → 3CuSO4 + 2Fe(OH)3↓
(43) 2FeSO4 + 2H2SO4 → Fe2(SO4)3 + 2H2O + SO2↑
(44) Fe2(SO4)3 + Fe → 3FeSO4
(45) 3FeSO4 + 2Al(OH)3 → Al2(SO4)3 + 3Fe(OH)2↓
(46) FeSO4 + 2NaOH → Na2SO4 + Fe(OH)2↓
(48) Al(OH)3 + NaOH → NaAlO2 + 2H2O
(49) 2NaAlO2 + 3H2O + CO2 → 2Al(OH)3↓ + Na2CO3
(50) CO2 + 3H2O + 2NaAlO2 → 2Al(OH)3↓ + Na2CO3
(51) 4Fe(OH)2 + O2 + 2H2O \(\underrightarrow{to}\) 4Fe(OH)3
(52) 2Fe(OH)3 + 3H2SO4 → Fe2(SO4)3 + 6H2O
34. MgSO4 + BaCl2 -> BaSO4 + MgCl2
35. MgCl2 + 2NaOH -> 2NaCl + Mg(OH)2