Ta có: 2⁵⁰⁰=2^5.100=(2⁵)¹⁰⁰=32¹⁰⁰

5²⁰⁰=5^2.100=(5²)¹⁰⁰=25¹⁰⁰

Vì: 32¹⁰⁰>25¹⁰⁰ (32>25) => 2⁵⁰⁰>25¹⁰⁰

2⁵⁰⁰ và 5²⁰⁰

Ta có : 2^{500 =} (2⁵)¹⁰⁰ = 32¹⁰⁰

            5^{200 =} (5²)^{100 =} 25¹⁰⁰

Vì 32¹⁰⁰ > 25¹⁰⁰

=) 2⁵⁰⁰ > 5²⁰⁰

3⁷⁵=(3³)²⁵=27²⁵>25²⁵=(5²)²⁵=5⁵⁰

vậy 3⁷⁵>5⁵⁰

Ta có:

\(\left(-5\right)^{30}=\left(-5^3\right)^{10}=\left(-125\right)^{10}=125^{10}\)

\(\left(-3\right)^{50}=\left(-3^5\right)^{10}=\left(-81\right)^{10}=81^{10}\)

Vì \(125^{10}>81^{10}\)

⇒\(\left(-5\right)^{30}>\left(-3\right)^{50}\)

\(\left(-5\right)^{30}\) và \(\left(-3\right)^{50}\)

Ta có: \(\left(-5\right)^{30}=\left[\left(-5\right)^3\right]^{10}=\left(-125\right)^{10}\)

\(\left(-3\right)^{50}=\left[\left(-3\right)^5\right]^{10}=\left(-243\right)^{10}\)

Vì \(\left(-125\right)^{10}< \left(-243\right)^{10}\) nên \(\left(-5\right)^{30}< \left(-3\right)^{50}\)

\(5\sqrt{2}+\sqrt{75}=5\sqrt{2}+5\sqrt{3}\)

\(5\sqrt{3}+\sqrt{50}=5\sqrt{3}+5\sqrt{2}\)

\(\Rightarrow5\sqrt{2}+\sqrt{75}=5\sqrt{3}+\sqrt{50}\)

Ta có 3^75 = (3^3)^25= 9^25

5^50 = (5^2)^25 =-10^25

=) 9<10 =) 3^75 < 5^50

3⁷⁵  > 3⁵⁰

\(\text{Ta có}:\)

\(3^{75}=\left(3^3\right)^{25}\)

\(5^{50}=\left(5^2\right)^{25}\)

\(\Rightarrow\left(3^3\right)^{25}=27^{25}\)

\(\Rightarrow\left(5^2\right)^{25}=25^{25}\)

\(\text{Vậy }27^{25}>25^{25}\)

\(\Rightarrow3^{75}>5^{50}\)

1) \(5^{199}< 5^{200}=25^{100}\)

\(3^{300}=27^{100}>25^{100}\)

\(\Rightarrow3^{300}>5^{199}\)

\(\Rightarrow\dfrac{1}{3^{300}}< \dfrac{1}{5^{199}}\)

2)  a) \(107^{50}=\left(107^2\right)^{25}=11449^{25}\)

\(73^{75}=\left(73^3\right)^{25}=389017^{25}>11449^{25}\)

\(\Rightarrow107^{50}< 73^{75}\)

b) \(54^4< 5^{12}< 21^{12}\Rightarrow54^4< 21^{12}\)

Giúp mình với

chắc là >

\(\left(-5\right)^{30}=5^{30}=5^{3.10}=\left(5^3\right)^{10}=125^{10}\)

\(\left(-3\right)^{50}=3^{50}=3^{5.10}=\left(3^5\right)^{10}=243^{10}\)

do   \(125^{10}< 243^{10}\)

nên   \(\left(-5\right)^{30}< \left(-3\right)^{50}\)

\(\left(-5\right)^{30}=\left[\left(-5\right)^3\right]^{10}=125^{10}\)

\(\left(-3\right)^{50}=\left[\left(-3\right)^5\right]^{10}=243^{10}\)

mà \(125^{10}< 243^{10}=>\left(-5\right)^{30}< \left(-3\right)^{50}\)

\(a=2^{100}=\left(2^4\right)^{25}=16^{25}\)

\(b=3^{75}=\left(3^3\right)^{25}=27^{25}\)

\(c=5^{50}=\left(5^2\right)^{25}=25^{25}\)

Vì \(16^{25}< 25^{25}< 27^{25}\)

\(\Rightarrow a< c< b\)

\(a=2^{100},b=3^{75},c=5^{50}\\ \Rightarrow a=30^{85},b=30^{65},c=30^{44}\\ \Rightarrow a>b>c\)

Ta có:

\(a=2^{100}=2^{4\cdot25}=\left(2^4\right)^{25}=16^{25}\)

\(b=3^{75}=3^{3\cdot25}=\left(3^3\right)^{25}=27^{25}\)

\(c=5^{50}=5^{2\cdot25}=\left(5^2\right)^{25}=25^{50}\)

Ta thấy: 

\(16< 25< 27\)

\(\Rightarrow16^{25}< 25^{25}< 27^{25}\)

\(\Rightarrow2^{100}< 5^{50}< 3^{75}\)

\(\Rightarrow a< c< b\)