M=9/40-11/60+13/84-15/112=1/16

nhớ k cho mình nha

Đây là toán lớp 1 à?

\(\frac{9}{40}\) - \(\frac{11}{60}\) + \(\frac{13}{84}\) - \(\frac{15}{112}\)

= \(\frac{1}{24}\) + \(\frac{13}{84}\) - \(\frac{15}{112}\)

= \(\frac{11}{56}\) - \(\frac{15}{112}\)

= \(\frac{1}{16}\)

cam on ban nhung tai sao co 1/24

Ta có: \(M=\dfrac{9}{40}-\dfrac{11}{60}+\dfrac{13}{84}-\dfrac{15}{112}\)

\(=\dfrac{378}{1680}-\dfrac{308}{1680}+\dfrac{260}{1680}-\dfrac{225}{1680}\)

\(=\dfrac{105}{1680}=\dfrac{1}{16}\)

M=9/40-11/60+13/84-15/112

M=27/120-22/120+52/336-45/336

M=1/24+1/48

M=2/48+1/48=3/48=1/16

\(M=\dfrac{9}{40}-\dfrac{11}{60}+\dfrac{13}{84}-\dfrac{15}{112}\)

\(M=\left(\dfrac{90}{40}-\dfrac{11}{60}\right)+\left(\dfrac{13}{84}-\dfrac{15}{112}\right)\)

\(M=\dfrac{27}{120}-\dfrac{22}{120}+\dfrac{52}{336}-\dfrac{45}{336}\)

\(M=\dfrac{5}{120}+\dfrac{7}{336}\)

\(M=\dfrac{1}{24}+\dfrac{1}{48}\)

\(M=\dfrac{3}{48}=\dfrac{1}{16}\)

M=\(\dfrac{9}{40}-\dfrac{11}{60}+\dfrac{13}{84}-\dfrac{15}{112}\)

M=\(\dfrac{1}{24}+\dfrac{13}{84}-\dfrac{15}{112}\)

M=\(\dfrac{11}{56}-\dfrac{15}{112}\)

M=\(\dfrac{1}{16}\)