a: =50-52=-2

b: =-35+149-114

=-149+149

=0

c: =-29x100=-2900

x=-36

x=11

x=100

x=14

x=-36

x=11

x=100

x=14

2: \(\Leftrightarrow\left(\dfrac{x+1}{12}-1\right)+\left(\dfrac{x+2}{13}-1\right)=\left(\dfrac{x+3}{14}-1\right)+\left(\dfrac{x+4}{15}-1\right)\)

=>x-11=0

=>x=11

3: \(\Leftrightarrow\left(\dfrac{x-85}{15}-1\right)+\left(\dfrac{x-74}{13}-2\right)+\left(\dfrac{x-67}{11}-3\right)+\left(\dfrac{x-64}{9}-4\right)=0\)

=>x-100=0

=>x=100

\(a)22.3-\left(110+7\right):326\)

\(=66-117:326\)

\(=66-\frac{117}{326}\)

\(=\frac{21399}{326}\)

\(b)1+2+3+.....+2019+2010\)

Ta tạm để số 2010 ra ngoài .

Số số hạng của tổng trên là :

( 2019 - 1 ) : 1 + 1 = 2019 ( sh )

Tổng trên là :

\(\left(2019+1\right)\times2019:2=2039190\)

\(\Rightarrow2039190+2010=2041200\)

\(c)64:4+2.52\)

\(=16+104\)

\(=120\)

\(d)2008.213+87.2008\)

\(=2008.\left(213+87\right)\)

\(=2008.300\)

\(=602400\)

\(e)12: \left\{390:\left[500-\left(125+35.7\right)\right]\right\}\)

\(=12:\left\{390:\left[500-370\right]\right\}\)

\(=12:\left\{390:130\right\}\)

\(=12:3=4\)

\(g)33.118-33.18\)

\(=3894-594\)

\(=3300\)

\(h)150-\left[102-\left(14-11\right).2\right]:9\)

\(=150-\left[102-6\right]:9\)

\(=150-96:9\)

\(=150-\frac{32}{33}\)

\(=\frac{4918}{33}\)

\(i)4.52-3\)

\(=208-3\)

\(=205\)

\(a,22.3-\left(110+7\right):326=66-117:326=21399:326\)

b, 1+2+3+...+2019+2020 

     Số số hạng: 2020

     tổng: (1+2020) x 2020 : 2 = 2041210

c,64:4 + 2.52 = 16+104 = 120

d,2008.213 + 87.2008 = 2008.(213 + 87) = 2008. 300 = 602400

e, 12 : {390:[500-(125 + 35.7)]} = 12 : { 390 : [500 - ( 125 + 245 )]} = 12 : [ 390 : (500 - 370)] = 12 : ( 390 : 130 ) = 12 : 3 = 4

g, 33.118 - 33.18 = 33.(118 - 18) = 33.100 = 3300

h, 150 - [ 102 - ( 14 -11 ).2 ] :9 = 150 - ( 102 - 3.2) : 9 = 105 - 96:9 = 1254 : 9

i, 4.52 - 3 = 208 - 3 = 205

A.115-(-85)+35-(46+35)

= 115 + 85 + 35 - 81

= 200 + 35 - 81

= 235 - 81

= 154

Vậy A = 154

B.7.(-3)^2 +9.(-4)^0 -(63-9)

= 7. 9 + 9. 1 - (63-9)

= 9. ( 7 + 1 ) - (63-9)

= 9 . 8 - 54

= 72 - 54

= 18

Vậy B= 18

C.(-164)+(-2)^10 : (-2)^8 +64

= (- 164) + (-2)^2 + 64

= (- 164) + 4 + 64

= (-168) + 64

= -104

Vậy C = - 104

-1/64 nha b

\(\frac{3}{2}+\frac{5}{4}+\frac{9}{8}+\frac{17}{16}+\frac{33}{32}+\)\(\frac{65}{64}-7\)

\(=\frac{96}{64}+\frac{80}{64}+\frac{72}{64}+\frac{66}{64}+\frac{65}{64}-7\)

\(=\frac{96+80+72+66+64}{64}-7\)

\(=\frac{378}{64}-\frac{7}{1}\)

\(=\frac{189}{32}-\frac{224}{32}\)

\(=\frac{-35}{32}\)

\(S=1+\frac{1}{2}+1+\frac{1}{4}+1+\frac{1}{8}+1+\frac{1}{16}+1+\frac{1}{32}+1+\frac{1}{64}-7\)

\(S=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}-1\)

Ta đặt:    \(P=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\)

=> \(2P=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\)

=> \(2P-P=\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\right)\)

=> \(P=1-\frac{1}{64}\)

Mà    \(S=P-1\)

=> \(S=1-\frac{1}{64}-1=-\frac{1}{64}\)

Vậy \(S=-\frac{1}{64}\)

\(\dfrac{4^9\cdot36+64^4}{100\cdot16^4}=\dfrac{2^{20}\cdot3^2+2^{24}}{2^{18}\cdot5^2}=\dfrac{2^{20}\left(3^2+2^4\right)}{2^{18}\cdot5^2}=4\)

 ko bt