1/2* x+2/3=9/2

1/2 * x = 9/2 - 2/3 

1/2 * x= 23/6

x= 23/6 : 1/2

x= 23/6 x 2= 23/3

___

1/2*x-1/3=2/3

1/2*x = 2/3 + 1/3

1/2 * x= 1

x= 1: 1/2 

x= 2

____

1/4+3/4:x=3

3/4 : x = 3 - 1/4

3/4 : x= 11/4

x= 11/4 : 3/4

x= 11/3

\(\dfrac{1}{2}\)\(\times\)\(x\) + \(\dfrac{2}{3}\) = \(\dfrac{9}{2}\)

\(\dfrac{1}{2}\)\(\times\)\(x\)        = \(\dfrac{9}{2}\) - \(\dfrac{2}{3}\)

\(\dfrac{1}{2}\)\(\times\)\(x\)       = \(\dfrac{23}{6}\)

      \(x\)       = \(\dfrac{23}{6}\):\(\dfrac{1}{2}\)

      \(x\)      = \(\dfrac{23}{3}\) 

\(\dfrac{1}{2}\)\(\times\)\(x\) - \(\dfrac{1}{3}\) = \(\dfrac{2}{3}\) 

\(\dfrac{1}{2}\)\(\times\)\(x\)       = \(\dfrac{2}{3}\) + \(\dfrac{1}{3}\)

\(\dfrac{1}{2}\times\)\(x\)      =  1

     \(x\)       = 1 : \(\dfrac{1}{2}\)

   \(x\)         = 2

\(\dfrac{1}{4}\) + \(\dfrac{3}{4}\): \(x\) = 3

          \(\dfrac{3}{4}\): \(x\) = 3 - \(\dfrac{1}{4}\) 

          \(\dfrac{3}{4}\):\(x\) = \(\dfrac{11}{4}\)

              \(x\) = \(\dfrac{3}{4}\): \(\dfrac{11}{4}\)

             \(x\) = \(\dfrac{3}{11}\)

` @ L I N H `

1/2* x+2/3=9/2

1/2 * x = 9/2 - 2/3 

1/2 * x= 23/6

x= 23/6 : 1/2

x= 23/6 x 2= 23/3

___

1/2*x-1/3=2/3

1/2*x = 2/3 + 1/3

1/2 * x= 1

x= 1: 1/2 

x= 2

____

1/4+3/4:x=3

3/4 : x = 3 - 1/4

3/4 : x= 11/4

x= 11/4 : 3/4

x= 11/3

=>2x^2+2x-3x-3+x^2+2x=3x^2+12x+12

=>12x+12=x-3

=>11x=-15

=>x=-15/11

`4/3 + ( x + 3) xx 2 - 1/2 = 27/2`

`=>  ( x + 3) xx 2 - 1/2 = 27/2-4/3`

`=>  ( x + 3) xx 2 - 1/2 =73/6`

`=>  ( x + 3) xx 2 =73/6 +1/2`

`=>  ( x + 3) xx 2 =38/3`

`=>x+3=38/3 xx 1/2`

`=>x+3=19/3`

`=>x=19/3-3`

`=>x= 10/3`

\(x\times\dfrac{2}{3}=\dfrac{4}{9}\times\dfrac{3}{8}=\dfrac{1}{6}\)

\(x=\dfrac{1}{6}:\dfrac{2}{3}=\dfrac{1}{4}\)

`x xx2/3=4/9xx3/8`

`x xx2/3=1/6`

`x=1/6:2/3`

`x=1/6xx3/2`

`x=1/4`

\(x\times\dfrac{2}{3}=\dfrac{4}{9}\times\dfrac{3}{8}\) 

\(x\times\dfrac{2}{3}=\dfrac{1}{6}\) 

       \(x=\dfrac{1}{6}:\dfrac{2}{3}\) 

       \(x=\dfrac{1}{4}\)

\(x^2\left(x-3\right)^2-\left(x-3\right)^2-x^2+1=\left(x-3\right)^2\left(x^2-1\right)-\left(x^2-1\right)=\left(x^2-1\right)\left(x-3\right)^2=\left(x-1\right)\left(x+1\right)\left(x-3\right)^2\)

\(\dfrac{1}{2}\) \(\times\) ( \(x\) - \(\dfrac{2}{3}\)) - \(\dfrac{1}{3}\) \(\times\) ( 2\(x\)  - 3) = \(x\)

\(\dfrac{1}{2}\)  \(\times\) \(\dfrac{3x-2}{3}\) -   \(\dfrac{2x-3}{3}\) = \(x\)

\(\dfrac{3x-2}{6}\) - \(\dfrac{4x-6}{6}\) = \(\dfrac{6x}{6}\)

3\(x-2-4x\) + 6 = 6\(x\) 

-\(x\) + 4 - 6\(x\) = 0

7\(x\)  = 4

    \(x\) =  \(\dfrac{4}{7}\) 

| x-2/3| = 1/3+2/5

             = 11/15

=> x-2/3=11/15          hoặc x-2/3=-11/15

            x= 7/5                      x       = -1/15

k cho mk nha

\(\left|x-\frac{2}{3}\right|-\frac{2}{5}=\frac{1}{3}\)

\(\Rightarrow\left|x-\frac{2}{3}\right|=\frac{1}{3}+\frac{2}{5}=\frac{11}{15}\)

\(\Rightarrow\orbr{\begin{cases}\Rightarrow x-\frac{2}{3}=\frac{11}{15}\\x-\frac{2}{3}=\frac{-11}{15}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}\Rightarrow x=\frac{7}{15}\\x=\frac{-1}{15}\end{cases}}\)

y x 2/3 + 1/3 = 8/9 : 2

Y x 2/3 +1/3 = 4/9

Y x 1/3 = 4/9 - 1/3

y x 1/3 = 1/9

Y = 1/9 : 1/3

y = 1/3

y x 2/3 + 1/3 = 8/9 : 2

y x 2/3 + 1/3 = 4/9

                y   = (4/9 - 1/3) : 2/3

                y   = 1/6

( dùng thứ lại biểu thức cộng trừ trước nhân chia sau)

y x 2/3 + 1/3 = 8/9 : 2

Y x 2/3 +1/3 = 4/9

Y x 1/3 = 4/9 - 1/3

y x 1/3 = 1/9

Y = 1/9 : 1/3

y = 1/3

\(\left(x+3\right)^2-\left(x+2\right)\left(x-2\right)=4x+17\\ \Leftrightarrow x^2+6x+9-x^2+4=4x+17\\ \Leftrightarrow2x=4\\ \Leftrightarrow x=2\)

\(\left(x+3\right)^2-\left(x+2\right)\left(x-2\right)=4x+17\\ \Leftrightarrow x^2+6x+9-x^2+4=4x+17\\ \Leftrightarrow x^2-x^2+6x-4x=17-4-9\\ \Leftrightarrow2x=4\\ \Leftrightarrow x=\dfrac{4}{2}=2\)

x = 2 bạn ạ