`#3107.101107`

\(48\div24-x=1\\ \Rightarrow2-x=1\\ \Rightarrow x=2-1\\ \Rightarrow x=1\)

Vậy, `x = 1`

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\(124-2\times\left(x+3\right)=24\\ \Rightarrow2\left(x+3\right)=124-24\\ \Rightarrow2\left(x+3\right)=100\\ \Rightarrow x+3=100\div2\\ \Rightarrow x+3=50\\ \Rightarrow x=50-3\\ \Rightarrow x=47\)

Vậy, `x = 47.`

1) 48 : 24 - x = 1                               2) 123 - 2 x (x+3) = 24

    2-x=1                                                 2 x (x+3) = 123 - 24   

       x= 2-1                                             2 x (x+3) = 99

       x= 1                                                       x+3 = 99 : 2

                                                                     x+3 = \(\dfrac{99}{2}\)

                                                                     x     = \(\dfrac{99}{2}\) -3

                                                                     x     = \(\dfrac{93}{2}\)

Bài 2: Tìm x:

\(a)x=\dfrac{1}{4}+\dfrac{5}{13}=\dfrac{33}{52}.\\ b)\dfrac{x}{3}=\dfrac{2}{3}+\dfrac{-1}{7}.\\ \Leftrightarrow\dfrac{x}{3}=\dfrac{11}{21}.\\ \Leftrightarrow\dfrac{7x}{21}=\dfrac{11}{21}.\\ \Rightarrow7x=11.\\ \Leftrightarrow x=\dfrac{11}{7}.\\ c)\dfrac{x}{3}=\dfrac{16}{24}+\dfrac{24}{36}=\dfrac{2}{3}+\dfrac{2}{3}=\dfrac{4}{3}.\\ \Rightarrow x=4.\\ d)\dfrac{x}{15}=\dfrac{1}{5}+\dfrac{2}{3}=\dfrac{13}{15}.\\ \Rightarrow x=13.\)

a ) (x+1)+(x+2)+(x+3)=24

=>x+1+x+2+x+3=24

=>(x+x+x)+(1+2+3)=24

=>3x+6=24

=>3x = 24-6

=> 3x = 18

=> x = 18 : 3

=> x = 3

b )x+x+8 =24

=>2x = 24-8

=> 2x = 16

=> x = 16 : 2

=> x =8

k cho mh nha

. 

a. ( x+1 )+(x+2)+(x+3)=24

x+1+x+2+x+3=24

x+x+x+1+2+3=24

3*x+(1+2+3)=24

3*x+6=24

3*x=24-6

3*x=18

x=18:3

x=6

b.x+x+8=24

2*x+8=24

2*x=24-8

2*x=16

x=16:2

x=8

Lần sau mấy bài dễ thế này em nên tư duy một tí nha!

de sai roi ban oi

Không sai bạn nhé, đề cô giáo mình cho như vậy

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a: x=-5/11+2/11=-3/11

b: =>x=-3/24+20/24+1/24=18/24=3/4

c: =>5/8-x=1/9+5/4=4/36+45/36=49/36

=>x=5/8-49/36=-53/72

d: =>2/3-x=1/3

=>x=1/3

e: =>1/5:x=12/35

=>x=7/12

\(5x\left(x-2\right)-3\left(x-1\right)=20x^2-15x\left(2x+1\right)-24\)

\(\Rightarrow5x^2-10x-3x+3=20x^2-30x^2-15x-24\)

\(\Rightarrow5x^2-13x+3=-10x^2-15x-24\)

\(\Rightarrow5x^2+10x^2-13x+15x+3+24=0\)

\(\Rightarrow15x^2+2x+27=0\)

Ta có: 

\(\Delta=2^2-4\cdot15\cdot27==-1616< 0\)

Nên pt vô nghiệm

\(5x\left(x-2\right)-3\left(x-1\right)=20x^2-15x\left(2x+1\right)-24\\ \Leftrightarrow5x^2-10x-3x+3=20x^2-30x^2-15x-24\\ \Leftrightarrow5x^2-20x^2+30x^2-10x-3x+15x+3+24=0\\ \Leftrightarrow15x^2+2x+27=0\\ \Leftrightarrow15x^2-2.x.\sqrt{15}+\dfrac{2}{15}+\dfrac{403}{15}=0\\ \Leftrightarrow\left(\sqrt{15}x+\dfrac{\sqrt{30}}{15}\right)^2+\dfrac{403}{15}=0\left(Vô.lí\right)\\ Vậy:Không.có.x.thoả\)

\(B=\frac{1+x^2+x^4+...+x^{26}}{1+x^4+x^8+...+x^{24}}\)

\(=\frac{\frac{\left(x^2-1\right)\left(1+x^2+x^4+...+x^{26}\right)}{x^2-1}}{\frac{\left(x^4-1\right)\left(1+x^4+x^8+...+x^{24}\right)}{x^4-1}}\)

\(=\frac{\frac{x^{28}-1}{x^2-1}}{\frac{x^{28}-1}{x^4-1}}=\frac{x^4-1}{x^2-1}=x^2+1\)

a: =>6/x=x/24

=>x^2=144

=>x=12 hoặc x=-12

b: =>x(1-7/12+3/8)=5/24

=>x*19/24=5/24

=>x=5/24:19/24=5/19

c: =>(x-1/3)^2=1+3/4+1/2=9/4

=>x-1/3=3/2 hoặc x-1/3=-3/2

=>x=11/6 hoặc x=-7/6

d: =>(x-3)^2=16

=>x-3=4 hoặc x-3=-4

=>x=-1 hoặc x=7

e: =>9/x=-1/3

=>x=-27

f: =>x-1/2=0 hoặc -x/2-3=0

=>x=1/2 hoặc x=-6