Tìm x:
x(x-1)(x+3)-x^2(x+3)=-4
Tìm X:x/2+x-1/3+x-2/4=1/4
Tìm x:
x x 2 + x x 3 + x x 4 + x = 2130
x * 2 + x * 3 + x * 4 + x = 2130
x * (2 + 3 + 4 + 1) = 2130
x * 10 = 2130
x = 2130 : 10 = 213
2x + 3x + 4x + x = 2130
10x = 2130
x = 2130 ÷ 10
x = 213
Tìm x:
x - 1/8 = 1/4 x 2/3
`x-1/8=1/4xx2/3`
`x-1/8=1/6`
`x=1/6+1/8`
`x=7/24`
x - 1/8 = 1/4 x 2/3
x - 1/8= 1/6
x = 1/6 + 1/8
x = 14/48
tìm x:
x :7/11 = 22
11/2 - 3/2 x X = 7/4
x = 22 x 7/11
x = 14
3/2 x X = 11/2 - 7/4
3/2 x X = 22/7
X = 22/7 : 3/2
X = 44/21
Tìm x:
X x 3/4 = 4/5
....................
....................
....................
5/9 : x = 8/3
...................
...................
...................
x = 4/5 : 3/4
x = 16/15
x = 5/9 : 8/3
x = 5/9 x 3/8
x = 5/24
\(x=\dfrac{4}{5}\times\dfrac{4}{3}\)
\(x=\dfrac{16}{15}\)
-----------------------
\(x=\dfrac{5}{9}\times\dfrac{3}{8}\)
\(x=\dfrac{5}{24}\)
\(x\times\dfrac{3}{4}=\dfrac{4}{5}\)
\(x=\dfrac{4}{5}:\dfrac{3}{4}\)
\(x=\dfrac{4}{5}\times\dfrac{4}{3}\)
\(x=\dfrac{16}{15}\)
\(\dfrac{5}{9}:x=\dfrac{8}{3}\)
\(x=\dfrac{5}{9}:\dfrac{8}{3}\)
\(x=\dfrac{5}{9}\times\dfrac{3}{8}\)
\(x=\dfrac{15}{72}\)
\(x=\dfrac{5}{24}\)
Tìm x :
6x(1-3x)+9x(2x-7)+171=0
tập hợp x:x+1/2015+x+2/2014=x+3/2013+x+4/2012
\(6x\left(1-3x\right)+9x\left(2x-7\right)+171=0\)
\(\Leftrightarrow6x-18x^2+18x^2-63x+171=0\)
\(\Leftrightarrow-57x=-171\)
\(\Leftrightarrow x=3\)
\(\frac{x+1}{2015}+\frac{x+2}{2014}=\frac{x+3}{2013}+\frac{x+4}{2012}\)
\(\Leftrightarrow\left(\frac{x+1}{2015}+1\right)+\left(\frac{x+2}{2014}+1\right)-\left(\frac{x+3}{2013}+1\right)-\left(\frac{x+4}{2012}+1\right)=0\)
\(\Leftrightarrow\)\(\frac{x+2016}{2015}+\frac{x+2016}{2014}-\frac{x+2016}{2013}+\frac{x+2016}{2012}=0\)
\(\Leftrightarrow\left(x+2016\right)\left(\frac{1}{2015}+\frac{1}{2014}-\frac{1}{2013}-\frac{1}{2012}\right)=0\)
\(\Leftrightarrow x+2016=0\) ( vì \(\frac{1}{2015}+\frac{1}{2014}-\frac{1}{2013}-\frac{1}{2012}\ne0\) )
\(\Leftrightarrow x=-2016\)
3.tìm x:x*0,25-72,5=22,2
tìm x:x*3+x*4+x=172
4.tổng 2 số là 68,2; thương 2 số là 4,5.tìm 2 số đó
5.hiệu 2 số là 0,6,thương 2 số cũng la 0,6.tìm 2 số đó
Tìm x:
x - {[ -x + ( x + 3)]} - [( x + 3) - ( x - 2)] = 0
GIÚP EM VỚI MN ƠI!!!!!
\(\Leftrightarrow x-\left[3-x+3+x-2\right]=0\)
=>x=4
Tìm x:
x^3 + 6x^2 + 12x + 8 = x^2 + 4x + 4
\(\Leftrightarrow\left(x+2\right)^2\cdot\left(x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=-1\end{matrix}\right.\)
\(\Leftrightarrow x^3+5x^2+8x+4=0\\ \Leftrightarrow\left(x+1\right)\left(x+2\right)^2=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-1\\x=-2\end{matrix}\right.\)