\(\dfrac{x-2023}{6}+\dfrac{x-2023}{10}+\dfrac{x-2023}{15}+\dfrac{x-2023}{21}=\dfrac{8}{21}\)

\(\left(x-2023\right)\left(\dfrac{1}{6}+\dfrac{1}{10}+\dfrac{1}{15}+\dfrac{1}{21}\right)=\dfrac{8}{21}\)

\(\left(x-2023\right).\dfrac{8}{21}=\dfrac{8}{21}\)

\(x-2023=1\)

\(x=2024\)

Vậy..............

\(...\Rightarrow\left(x-2023\right)\left(\dfrac{1}{6}+\dfrac{1}{10}+\dfrac{1}{15}+\dfrac{1}{21}\right)=\dfrac{8}{21}\)

\(\Rightarrow\left(x-2023\right)\left(\dfrac{35+21+14+1}{210}\right)=\dfrac{8}{21}\)

\(\Rightarrow\left(x-2023\right).\dfrac{71}{210}=\dfrac{8}{21}\)

\(\Rightarrow\left(x-2023\right).\dfrac{71}{210}=\dfrac{8}{21}.\dfrac{210}{71}=\dfrac{80}{71}\)

\(\Rightarrow x-2023=\dfrac{80}{71}\Rightarrow x=\dfrac{80}{71}+2023=\dfrac{143713}{71}\)

\(\dfrac{x-2023}{6}+\dfrac{x-2023}{10}+\dfrac{x-2023}{15}+\dfrac{x-2023}{21}=\dfrac{8}{21}\)

\(\Leftrightarrow\left(x-2023\right).\left(\dfrac{1}{6}+\dfrac{1}{10}+\dfrac{1}{15}+\dfrac{1}{21}\right)=\dfrac{8}{21}\)

\(\Leftrightarrow\left(x-2023\right).\left(\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}\right)=\dfrac{4}{21}\)

\(\Leftrightarrow\left(x-2023\right).\left(\dfrac{1}{3.4}+\dfrac{1}{4.5}+\dfrac{1}{5.6}+\dfrac{1}{6.7}\right)=\dfrac{4}{21}\)

\(\Leftrightarrow\left(x-2023\right).\left(\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}\right)=\dfrac{4}{21}\)

\(\Leftrightarrow\left(x-2023\right).\left(\dfrac{1}{3}-\dfrac{1}{7}\right)=\dfrac{4}{21}\)

\(\Leftrightarrow x-2023=1\Leftrightarrow x=2024\)

=>6/5>x>21/37

hay x=1

x=1

1

a)  x - 105 : 21 = 15

x - 5 = 15

=> x = 20

b)  ( x - 105 ) : 21 = 15

x - 105 = 315

=> x = 420

c)  315 + ( 125 - x ) = 435

125 - x = 120

=> x = 5

a)x - 105 : 21 = 15

    x - 5        =15

    x             =20

b) (x - 105) :21=15

     x -105         =315

     x                 =420

c) 315+ (125 - x ) =435

              125 - x   =-120            

                       x   =5

a) \(315+\left(125-x\right)=435\)

\(\Leftrightarrow125-x=435-315\)

\(\Leftrightarrow125-x=120\)

\(\Leftrightarrow x=125-120\)

\(\Leftrightarrow x=5\)

b) \(x:41=32\)

\(\Leftrightarrow x=32\cdot41\)

\(\Leftrightarrow x=1312\)

c) \(\left(x-105\right):21=15\)

\(\Leftrightarrow x-105=15\cdot21\)

\(\Leftrightarrow x-105=315\)

\(\Leftrightarrow x=315+105\)

\(\Leftrightarrow x=420\)

d) \(x-105:21=15\)

\(\Leftrightarrow x-5=15\)

\(\Leftrightarrow x=15+5\)

\(\Leftrightarrow x=20\)

a, 315 + ( 125 - x ) = 435 

              ( 125 - x) = 435 - 315 

               ( 125 - x ) = 320

                          x   = 320 - 125 

                          x = 195

bạn văn quang long tính sai rồi 435-315=120 chứ

1)\(x-105:21=15\)

\(x-5=15\)

\(x=15+5\)

\(x=20\)

Vậy \(x=20.\)

2)\(\left(x-105\right):21=15\)

\(\left(x-105\right)=15.21\)

\(x-105=315\)

\(x=315+105\)

\(x=420\)

Vậy \(x=412.\)

4)\(1818:\left(6x-37\right)=18\)

\(6x-37=1818:18\)

\(6x-37=101\)

\(6x=101+37\)

\(6x=138\)

\(x=138:6\)

\(x=23\)

Vậy \(x=23.\)

mk quên,còn phần 3) nữa:

3)\(\left(32+x\right):17=x\)

\(32+x=x.17\)

\(\Leftrightarrow x=2\)

Vậy \(x=2.\)

x - 105 : 21 = 15

x - 105        = 315

x                =420

tk mk nhé

x-105:21=15

<=>x-5=15

<=>x=20

vậy x=20

x - 105 ÷ 21 = 15

x - 5 = 15

x      = 15 + 5

x      = 20

[ -3x +21 ] [ 5 .| x | - 15 ] =0

<=> (-3x+21)=0 hoặc (5|x|-15)=0

<=> x=7 hoặc |x|=3

<=> x={7;-3;3}

d) (x – 105) : 21 = 15

(x – 105) = 15. 21

(x – 105) = 315

x = 315+ 105

x = 420

Vậy x = 420

b) x – 105 : 21 = 15

x – 5 = 15

x = 15+5

x = 20

Vậy x = 20