`a, = 5^3 xx 3^3 = 15^3`

`b, = 12^3 xx 4^3 = 48^3`

`c, = 625^3 xx 8^3 = 5000^3`

`d, = 625 ^3 xx 125^3 = 78125^3`

`e, = 5^20 : 5^14 = 5^6`

1,\(125\cdot27=5^3\cdot3^3=\left(5\cdot3\right)^3=15^3\)

2, \(12^3\cdot64=12^3\cdot4^3=\left(12\cdot4\right)^3=48^3\)

3, \(25^6\cdot8^3=\left(5^2\right)^6\cdot\left(2^3\right)^3=5^8\cdot2^9\)

4, \(25^6\cdot125^3=\left(5^2\right)^3\cdot\left(5^3\right)^3=5^6\cdot5^9=5^{15}\)

5,\(625^5:25^7=\left(5^4\right)^5:\left(5^2\right)^7=5^{20}:5^{14}=5^6\)

A)    (12 x 2 + 12 x 4 + 12 x 6) : ( 2 + 4 + 6 + ... + 12 + 14)
     = [12 x ( 2 + 4 - 6 )] : ( 2 + 4 + 6 + ... + 12 + 14)
     = [12 x 0 ] : ( 2 + 4 + 6 + ... + 12 + 14)
     = 0 : ( 2 + 4 + 6 + ... + 12 + 14)
     = 0 
B)    37 x 49 + 37 x 2 x 25 + 37 
     = 37 x (49 + 2 x 25 + 1)
     = 37 x 100 
     = 3700

Học dỏi nha :)))
~ Good luck ~

Sai cái dì mà mí người k sai nhiều quá v ?? :D ?? 

Sai cái dề :D ???????

=> vế trong ngoặc là 0 nhoa

rồi bạn thay vô tính thôi

a )   x :   − 7   –  6  =   − 15  x :   − 7   =   − 9 x  =   − 9 . − 7   x  =  63

b ) x :  12  –  12  =   − 37 x :  12  =   − 25 x  =   − 25 . 12 x  = 3 00

c ) x :   − 25   +  81  =  85 x :   − 25   =  4 x  =  4 . − 25 x  = − 1 00

x + 12 = -25 - (4⁴ : 4 + 6)

x + 12 = -25 - (256 : 4 + 6)

x + 12 = -25 - (64 + 6)

x + 12 = -25 - 70

x + 12 = -95

x = -95 - 12

x = -107

a: \(=\dfrac{48-45}{54}\cdot\dfrac{9}{4}=\dfrac{3}{54}\cdot\dfrac{9}{4}=\dfrac{27}{216}=\dfrac{1}{8}\)

b: \(=\dfrac{6}{5}+1=\dfrac{11}{5}\)

c: \(=\dfrac{7\cdot28\cdot15}{9\cdot25\cdot14}=\dfrac{1}{2}\cdot\dfrac{28}{25}\cdot\dfrac{5}{3}=\dfrac{140}{150}=\dfrac{14}{15}\)

a: \(x⋮25;25⋮x\)

=>\(\left\{{}\begin{matrix}x\inƯ\left(25\right)\\x\in B\left(25\right)\end{matrix}\right.\)

=>\(x\in\left\{25;-25\right\}\)

b: \(x\inƯ\left(21\right)\)

=>\(x\in\left\{1;-1;3;-3;7;-7;21;-21\right\}\)

mà \(x\in B\left(7\right)\)

nên \(x\in\left\{7;-7;21;-21\right\}\)