a: Ta có: \(-3x^4+20x^3-35x^2-10x+48\)

\(=-\left(3x^4-20x^3+35x^2+10x-48\right)\)

\(=-\left(3x^4-9x^3-11x^3+33x^2+2x^2-6x+16x-48\right)\)

\(=-\left(x-3\right)\left(3x^3-11x^2+2x+16\right)\)

\(=-\left(x-3\right)\left(3x^3-6x^2-5x^2+10x-8x+16\right)\)

\(=-\left(x-3\right)\left(x-2\right)\left(3x^2-5x-8\right)\)

\(=-\left(x-3\right)\left(x-2\right)\left(3x-8\right)\left(x+1\right)\)

b: Ta có: \(-\left(2x^4+7x^3+x^2-7x-3\right)\)

\(=-\left(2x^4-2x^3+9x^3-9x^2+10x^2-10x+3x-3\right)\)

\(=-\left(x-1\right)\left(2x^3+9x^2+10x+3\right)\)

\(=-\left(x-1\right)\left(2x^3+2x^2+7x^2+7x+3x+3\right)\)

\(=-\left(x-1\right)\left(x+1\right)\left(2x^2+7x+3\right)\)

\(=-\left(x-1\right)\left(x+1\right)\cdot\left(x+3\right)\left(2x+1\right)\)

\(b,x^3-3x^2-4x+12\)

\(\Leftrightarrow x^2\left(x-3\right)-4\left(x-3\right)\)

\(\Leftrightarrow\left(x-3\right)\left(x^2-4\right)\)

\(\Leftrightarrow\left(x-3\right)\left(x-2\right)\left(x+2\right)\)

\(c,3x^3-7x^2+17x-5\)

\(\Leftrightarrow3x^3-x^2-6x^2+2x+15x-5\)

\(\Leftrightarrow x^2\left(3x-1\right)-2x\left(3x-1\right)+5\left(3x-1\right)\)

\(\Leftrightarrow\left(3x-1\right)\left(x^2-2x+5\right)\)

\(\text{d) 2x}^4- 7x^3 - 2x^2 + 13x + 6\)
\(\text{= (2x^4 + 2x^3) - (9x^3 + 9x^2) + (7x^2 + 7x) + (6x + 6)}\)
\(\text{= 2x^3(x + 1) - 9x^2(x + 1) + 7x(x + 1) + 6(x + 1)}\)
\(\text{= (x + 1)(2x^3 - 9x^2 + 7x + 6)}\)
\(\text{= (x + 1)(2x + 1)(x - 3)(x - 2)}\)

phần b,c thay ''<=>'' là ''='' nhé ! Mình nhầm!

\(4x^2-5x-6=4x^2-8x+3x-6\)

\(=4x\left(x-2\right)+3\left(x-2\right)\)

\(=\left(x-2\right)\left(4x+3\right)\)

e ko bt phân tích đa thức thành nhân tử nên a tham khảo linh này nha

https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=&cad=rja&uact=8&ved=2ahUKEwim29i-oIzyAhVSNKYKHZBdCJ4QFjAAegQIBRAD&url=https%3A%2F%2Fh7.net%2Fhoi-dap%2Ftoan-8%2Fphan-h-da-thuc-5x-2-2x-2-2x-5x-2-6-thanh-nhan-tu-faq341450.html&usg=AOvVaw2Kkix8idzI43uM1i2Mitp4

TL:

(5x^2 - 2x)^2+2x-5x^2-6 

=(\(5x^2\)-2x+3)(\(5x^2\)-2x+2)

các bạn làm giúp mik , mik cần gấp . Làm đc mik chọn cho .

3x³-7x²+17x-5

=3x³-x²-6x²+2x+15x-5

= x².(3x-1)-2x.(3x-1)+5.(3x-1)

= (3x-1)(x²-2x+5)

Ta có : \(3x^3-7x^2+17x-5\)

    \(=\left(3x^3-x^2\right)-\left(6x^2-2x\right)+\left(15x-5\right)\)

    \(=x^2\left(3x-1\right)-2x\left(3x-1\right)+5\left(3x-1\right)\)

    \(=\left(3x-1\right)\left(x^2-2x+5\right)\)

Lời giải:

$2x^2-5x-6=2(x^2-\frac{5}{2}x+\frac{5^2}{4^2})-\frac{73}{8}$

$=2(x-\frac{5}{4})^2-\frac{73}{8}$

$=2(x-\frac{5}{4}-\frac{\sqrt{73}}{4})(x-\frac{5}{4}+\frac{\sqrt{73}}{4})$

a) \(-10x^2-17x+6\)

\(=-10x^2-20x+3x+6\)

\(=-10x\left(x+2\right)+3\left(x+2\right)\)

\(=\left(x+2\right)\left(3-10x\right)\)

b)\(x^2-10x+9\)

\(=x^2-x-9x+9\)

\(=x\left(x-1\right)-9\left(x-1\right)\)

\(=\left(x-1\right)\left(x-9\right)\)

c) \(x^2-10x+24\)

\(=x^2-4x-6x+24\)

\(=x\left(x-4\right)-6\left(x-4\right)\)

\(=\left(x-4\right)\left(x-6\right)\)

5x²-5x-6=(x+1)(5x-6)

ok k hộ mình cái