ai nhanh giup minh di roi minh cho nick "lien quan mobile" rank vang

B=1/16+ 6/16.26+ 6/26.36+ ..................+ 6/2006.2016

B=1/16+ 6. (1/16.26+ 1/26.36 +.................+ 1/2006.2016)

10B=1/16+6.(1/16- 1/2016)

10B=7.1/16 - 1/336

10B=7/16 - 1/336

10B=73/168

B=73/1680

làm hơi tắt bạn cố hiểu nhé

tớ là "nam tử hán đại trượng phu" nên tớ hứa là tớ làm .Kết bạn với tớ đi,tớ nhắn tin cho

nhân với 1/6

nhân với 1/6 cả 2 vế rồi nhân cả 2 vế với 10

\(B=\frac{1}{16}+\frac{6}{16.26}+\frac{6}{26.36}+....+\frac{6}{2006.2016}\)

\(=\frac{6}{6.16}+\frac{6}{16.26}+\frac{6}{26.36}+....+\frac{6}{2006.2016}\)

\(=\frac{6}{10}\left(\frac{1}{6}-\frac{1}{16}+\frac{1}{16}-\frac{1}{26}+...+\frac{1}{2006}-\frac{1}{2016}\right)\)

\(=\frac{3}{5}\left(\frac{1}{6}-\frac{1}{2016}\right)\)

\(=\frac{67}{672}\)

\(B=\frac{1}{16}+\frac{6}{16\cdot26}+\frac{6}{26\cdot36}+...+\frac{6}{2006\cdot2016}\)

\(B=\frac{1}{16}+6\left(\frac{1}{16\cdot26}+\frac{1}{26\cdot36}+...+\frac{1}{2006\cdot2016}\right)\)

\(B=\frac{1}{16}+6\left[\frac{1}{10}\left(\frac{10}{16\cdot26}+\frac{10}{26\cdot36}+...+\frac{10}{2006\cdot1016}\right)\right]\)

\(B=\frac{1}{16}+6\left[\frac{1}{10}\left(\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}+...+\frac{1}{2006}-\frac{1}{2016}\right)\right]\)

\(B=\frac{1}{16}+6\left[\frac{1}{10}\left(\frac{1}{16}-\frac{1}{2016}\right)\right]\)

\(B=\frac{1}{16}+6\cdot\left[\frac{1}{10}\cdot\frac{125}{2016}\right]\)

\(B=\frac{1}{16}+6\cdot\frac{26}{4032}\)

\(B=\frac{1}{16}+\frac{25}{672}\)

\(B=\frac{57}{672}\)

\(B=\frac{1}{16}+\frac{6}{16.26}+\frac{6}{26.36}+...+\frac{6}{2006.2016}\)

\(B=\frac{1}{16}+6\left(\frac{1}{16.26}+\frac{6}{26.36}+...+\frac{6}{2006.2016}\right)\)

\(B=\frac{1}{16}+\frac{6}{10}\left(\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}+...+\frac{1}{2006}-\frac{1}{2016}\right)\)

\(B=\frac{1}{16}+\frac{6}{10}\left(\frac{1}{16}-\frac{1}{2016}\right)\)

\(B=\frac{1}{16}+\frac{6}{10}.\frac{125}{2016}\)

\(B=\frac{1}{16}+\frac{25}{672}\)

\(B=\frac{67}{672}\)

nhanh lên ngày mai mk hk rùi

x-y-z=0=>x=y+z

=>z=x-y;=>y=x-z

\(=>B=\left(1-\frac{z}{x}\right)\left(1-\frac{x}{y}\right)\left(1-\frac{y}{z}\right)=\left(1-\frac{x-y}{x}\right)\cdot\left(1-\frac{y+z}{y}\right)\cdot\left(1+\frac{x-z}{z}\right)\)

Câu a cậu ghi sai đầu bài rồi hay sao í! phải là \(\frac{6}{36.46}\) chứ

Ta có x-y-z=0 suy ra x=z+y;y=x-z;-z=y-x

B=(1-z/x)(1-x/y)(1+y/z)

B=((x-z)/x)((y-x)/y)((z+y)/z)

B=(y/x)(-z/y)(x/z)

B=(-z.y.x)/(z.y.x)

B=-1

\(=\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{26}+...+\dfrac{1}{2006}-\dfrac{1}{2016}\)

=1/8-1/2016

=251/2016

\(\frac{15.\left(\frac{1}{616}.\frac{1}{6.16}.\frac{1}{6.16}\right)}{33.\left(\frac{1}{6.16}.\frac{1}{6.16}.\frac{1}{6.16}\right)}=\frac{15}{35}\)

\(A=\frac{\frac{3}{2}\left(\frac{1}{6}-\frac{1}{16}+\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}\right)}{\frac{33}{10}\left(\frac{1}{6}-\frac{1}{16}+\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}\right)}=\frac{\frac{3}{2}}{\frac{33}{10}}=\frac{3}{2}:\frac{33}{10}=\frac{5}{11}\)