(2003*14+1988+2001*2002)/(2002+2002*503+504*2002) = 2 

khó hiểu quá.

Cái j  vậy

nghe

Please

a) 59 753 498

b) 2 018 016

a) 63 759 500

b) 2 018 016

P=\(\frac{\left(2002+1\right)\times14+1988+2001\times2002}{2002\times\left(1+503+504\right)}\)

\(=\frac{2002\times14+2002+2001\times2002}{2002\times1008}\)

\(=\frac{2002\times\left(14+1+2001\right)}{2002\times1008}=\frac{2016}{1008}=2\)

kết quả là bao nhiêu

bấm máy nha bạn

Kết quả là 2

Ta có:

\(\frac{2003\times14+1988+2001\times2002}{2002+2002\times503+504\times2002}\)

ở phép tính này mình sẽ phân tích các số ra: ví dụ: 504 = 14 x36

Ta lại có:\(\frac{2003\times14+1988+2001\times2002}{2002+2002\times503+14\times36\times2002}\)

tiếp đó lượt bỏ các số giống nhau đi:

Ta được: \(\frac{2003+1988+2001}{2002+2002\times503\times36}\)

= \(\frac{5992}{2002+\left(2002\times503\right)\times36}\)

Tới đây bạn tự tính nha!

Ps: Mình không chắc nữa

thanks bạn nhiều nha

AAĂn loz

 2003 x 14 + 1988 + 2001 x 2002

=28042 + 1988 + 4006002

=4036032

 2002 + 2002 x 503 +504 x 2002

=2002 x 1 + 2002 x 503 + 504 x 2002

=2002 x (1 + 503 + 504)

=2002 x 908

=1817816

(2002+1)x14+1998+2001x2002/2002x1+2002x503+504x(2002+1)

=2002x14+14+1998+2001x2002/2002x1+2002x503+504x2002+504

=2002x(2001+14)+14+1998/2002x(1+503+504)+504

=2015+14+1998/1008+504

=4027/1512

 2003 x 14 + 1988 + 2001 x 2002

=28042 + 1988 + 4006002

=4036032

 2002 + 2002 x 503 +504 x 2002

=2002 x 1 + 2002 x 503 + 504 x 2002

=2002 x (1 + 503 + 504)

=2002 x 908

=1817816

a ) \(\frac{2003\times14+1988+2001+2002}{2002+2002\times503+504\times2002}\)

= \(\frac{\left(2002+1\right)\times14+1988+2001\times2002}{2002\times\left(1+503+504\right)}\)

= \(\frac{2002\times14+14+1998+2001\times2002}{2002\times1008}\)

= \(\frac{2002\times14+2002+2001\times2002}{2002\times1008}\)

= \(\frac{2002\times\left(14+1+2001\right)}{2002\times1008}\)

= \(\frac{2016}{1008}\)

= 2

b ) Đặt A = 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128

=> 2A = 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64

=> 2A - A = ( 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 ) - ( 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 )

=> A = 1/2 - 1/128

A = 63/128

\(b,\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+..+\frac{1}{128}\)

\(=\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^7}=A\)

\(\Rightarrow2A=\frac{1}{2}+\frac{1}{2^2}+..+\frac{1}{2^6}\)

\(\Rightarrow2A-A=\left(\frac{1}{2}+\frac{1}{2^2}+..+\frac{1}{2^6}\right)-\left(\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^7}\right)\)

\(\Rightarrow A=\frac{1}{2}-\frac{1}{2^7}\)