a,=3/13.17/29.29/34

=3/13.1/2

=3/26

b,=(4/21+25/42).19/33

=11/14.19/33

=19/42

`a, = 3/13 xx (17/29 xx 29/34)`

`= 3/13 xx 1/2`

`= 3/26`.

`b, = 19/33(4/21 + 25/42)`

`= 19/33 xx ( 33/42 )`

`= 19/42`

`a)(3/13xx17/29)xx29/34=3/13xx17/29xx29/34=[3xx17xx29]/[13xx19xx17xx2]=3/26`

`b)4/21xx19/33+25/42xx19/33=19/33xx(4/21+25/42)=19/33xx(8/42+25/42)=19/33xx33/42=19/42`

313×1729)×2934(313×1729)×2934

=313×1729×2934=313×1729×2934

=3×17×2913×29×34=3×17×2913×29×34

=3×17×2913×29×2×17=3×17×2913×29×2×17

=313×2=313×2

=326=326

421×1933+2542×1933421×1933+2542×1933

=1933×(421+2542)=1933×(421+2542)

=1933×(842+2542)=1933×(842+2542)

=1933×3342=1933×3342

=19×3333×42=19×3333×42

=1942

a, 6/7*8/15*7/6*15/16

=(6/7*7/6)*(8/15*15/16)

=1*1/2

=1/2

b, Đề bài hơi sai

câu b mình sửa lại là 19/20 x 13/21 + 19/20 x 8/21

b, 19/20*13/21+19/20*8/21

=19/20*(13/21+8/21)

=19/20*21/21

=19/20*1

=19/20

TK nha

 36-4x9 = 36 - 36 = 0 Vì số nào nhân với 0 thì cũng bằng 0 nên phép tính đó bằng 0

=9,8 * 43 + 19 * 9,8 - 61 * 9,8

= 9,8 * (43+19-61)
=9,8 * (62-61)
=9,8*1

=9,8

\(9,8\times43+2\times19\times4,9-6,1\times9,8\)

\(=9,8\times43+19\times\left(2\times4,9\right)-6,1\times9,8\)

\(=9,8\times43+19\times9,8-61\times9,8\)

\(=9,8\times\left(43+19-61\right)\)

\(=9,8\times\left(62-61\right)\)

\(=9,8\times1\)

\(=9,8\)

19.9+9.(37+43)+9

=19.9+9.80+9

=9.(19+80+1)

=9.100

=900

`#Ya`

`= 19 × 9 + 9 × 80 + 9 × 1`

`= 9 × ( 19 + 80 + 1 )`

`= 9 × 100= 900`

`19xx9+9xx(37+43)+9`

`=9xx(19+37+43+1)`

`=9xx100=900`

2008 x 76 +2008 x 43 - 2008 x 19

= 2008 x (76+43-19)

= 2008 x 100

= 200800

2008 x 76 +2008 x 43 - 2008 x 19

=2008x(76+43-19)

=2008x100

=200800

   2008 x 76 + 2008 x 43 - 2008 x 19

= 2008 x ( 76+43-19)

= 2008 x 100

= 200800

Nhớ k mk nha! Chúc bn hok tốt!

\(=21\cdot1131=23751\)

\(\left(a\right)\frac{3}{5}\cdot\frac{8}{21}\cdot\frac{5}{3}=\left(\frac{3}{5}\cdot\frac{5}{3}\right)\cdot\frac{8}{21}=1\cdot\frac{8}{21}=\frac{8}{21}\)

(b) sai đề

\(\left(c\right)x\cdot\frac{1}{2}=\frac{1}{3}\)

\(x=\frac{\frac{1}{3}}{\frac{1}{2}}=\frac{2}{3}\)

\(\left(d\right)\frac{x}{\frac{4}{5}}=\frac{5}{2}\)

\(x=\frac{5}{2}\cdot\frac{4}{5}=2\)

\(\left(e\right)\frac{\frac{2}{9}}{x}=\frac{2}{3}\)

\(x=\frac{\frac{2}{9}}{\frac{2}{3}}=\frac{1}{3}\)