a,=3/13.17/29.29/34
=3/13.1/2
=3/26
b,=(4/21+25/42).19/33
=11/14.19/33
=19/42
`a, = 3/13 xx (17/29 xx 29/34)`
`= 3/13 xx 1/2`
`= 3/26`.
`b, = 19/33(4/21 + 25/42)`
`= 19/33 xx ( 33/42 )`
`= 19/42`
`a)(3/13xx17/29)xx29/34=3/13xx17/29xx29/34=[3xx17xx29]/[13xx19xx17xx2]=3/26`
`b)4/21xx19/33+25/42xx19/33=19/33xx(4/21+25/42)=19/33xx(8/42+25/42)=19/33xx33/42=19/42`
a)\(=\dfrac{3}{13}\cdot\left(\dfrac{17}{29}\cdot\dfrac{29}{34}\right)=\dfrac{3}{13}\cdot\dfrac{17}{34}=\dfrac{3}{13}\cdot\dfrac{1}{2}=\dfrac{3}{26}\)
b)\(=\dfrac{19}{33}.\left(\dfrac{8}{42}+\dfrac{25}{42}\right)=\dfrac{19}{33}\cdot\dfrac{33}{42}=\dfrac{19}{42}\)
a) \(\left(\dfrac{3}{13}\times\dfrac{17}{29}\right)\times\dfrac{29}{34}=\dfrac{3\times17\times29}{13\times29\times34}=\dfrac{3\times17\times29}{13\times29\times17\times2}=\dfrac{3}{13\times2}=\dfrac{3}{26}\)
b) \(\dfrac{4}{21}\times\dfrac{19}{33}+\dfrac{25}{42}\times\dfrac{19}{33}=\left(\dfrac{4}{21}+\dfrac{25}{42}\right)\times\dfrac{19}{33}=\dfrac{11}{14}\times\dfrac{19}{33}=\dfrac{19}{42}\)
