=>9x=36

hay x=4

\(A^2=\left(\sqrt{2x+\sqrt{4x+1}}+\sqrt{2x-\sqrt{4x-1}}\right)\) 

     \(=2x+\sqrt{4x+1}+2x-\sqrt{4x-1}-2\sqrt{\left(2x+\sqrt{4x+1}\right)\cdot\left(2x-\sqrt{4x-1}\right)}\)

     \(=4x-2\sqrt{4x^2-4x+1}=4x-2\sqrt{\left(2x-1\right)^2}=4x-2\left|2x-1\right|\)

\(Do-\dfrac{1}{4}\le x\le\dfrac{1}{2}\)\(\Rightarrow A^2=4x-2\left(1-2x\right)=8x-2\)

\(\Rightarrow A=\sqrt{8x-2}\)

đề là j ạ

\(\frac{3x-5}{2x+7}=\frac{4x+8}{5x-4}\)

\(\left(3x-5\right)\left(5x-4\right)=\left(4x+8\right)\left(2x+7\right)\)

\(15x^2-12x-10x+20=8x^2+28x+16x+56\)

\(15x^2-8x^2-12x-10x-28x-16x+20-56=0\)

\(7x^2-66x-36=0\)

bạn tự làm tiếp nha

(3x-5)/(2x+7)=(4x+8)/(5x-4)

<=>(3x-5)(5x-4)=(4x+8)(2x+7)

<=>15x-20=8x+56

<=>15x-8x=56+20

<=>7x=76

<=>x=76:7=76/7

\(\frac{3x-5}{2x+7}=\frac{4x+8}{5x-4}\)

\(\left(3x-5\right)\left(5x-4\right)=\left(4x+8\right)\left(2x+7\right)\)

\(3x.5x-4.3x-5.5x+5.4=4x.2x+7.4x+8.2x+8.7\)

\(15x^2-12x-10x+20=8x^2+28x+16x+56\)

\(15x^2-22x+20=8x^2+44x+56\)

\(15x^2-22x+20-8x^2-44x-56=0\)

\(7x^2-66x-36=0\)

a) \(\left(3-x\right)\left(5x+10\right)=0\)

\(\left(3-x\right).5.\left(x+2\right)=0\)

\(\Rightarrow\orbr{\begin{cases}3-x=0\\x+2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=-2\end{cases}}\)

vậy...

b) \(\left|5x+2\right|-4x=7\)

\(\left|5x+2\right|=7+4x\)

\(\Rightarrow\orbr{\begin{cases}5x+2=7+4x\\5x+2=-7-4x\end{cases}}\Rightarrow\orbr{\begin{cases}5x-4x=7-2\\5x+4x=-7-2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=5\\9x=-9\end{cases}}\Rightarrow\orbr{\begin{cases}x=5\\x=-1\end{cases}}\)

vậy.... 

k nha 

a, \(\left(3-x\right)\left(5x+10\right)=0\)

\(\Rightarrow3-x=0\)   hoặc     \(5x+10=0\)

\(\Rightarrow x=3\)         hoặc          \(x=-2\)

\(\left|5x+2\right|-4x=7\)

\(\Rightarrow\left|5x+2\right|=7+4x\)

\(\Rightarrow\orbr{\begin{cases}5x+2=7+4x\\5x+2=-\left(7+4x\right)\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}5x-4x=7-2\\5x+2=-7-4x\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=5\\5x+4x=-7-2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=5\\9x=-9\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=5\\x=-1\end{cases}}\)

A

A

C

C

D

C

D

A

A

C

Quãng đường tuần lễ thứ ba làm chiếm:

1/2x1/5=1/10(quãng đường)

Quãng đường AB dài:

3,5:1/10=35(km)