1.2 +2.3 +3.4 +...+100.101
1.2+2.3+3.4+.....+100.101
Ta có:
A-B =1.2+2.3+3.4+...+100.101-
(1^2+2^2+3^2+4^2+...+100^2)
= 1.2+2.3+3.4+...+100.101-
Đặt B = 1.2+2.3 +.......+99.100+100.101
3B= 1.2.3+2.3.4+3.4.3 +......+ 99.100.3 + 100.101.3
3B= 1.2. (3 - 0) + 2.3.(4 - 1) +3.4. (5 - 2)....... . 99.100. (101 - 98) . 100.101.(102 - 99)
3B = (1.2.3 + 2.3.4 + 3.4.5 +...... + 99.100.101 + 100.101.102) - (0.1.2 + 1.2.3 + 2.3.4 +.......+ 98.99.100.99.100.101)
3B = 100.101.102 - 0.1.2
3B = 1030200 - 0
3B= 1030200
B = 1030200 : 3
B = 343400
đặt A = 1.2+2.3+3.4+.....+100.101
=> 3A = 1.2.3+2.3.3+.......+100.101.3
=> 3A = 1.2.3+2.3.(4-1)+......+100.101.(102-99)
=> 3A = 1.2.3 + 2.3.4-1.2.3 + ........+ 100.101.102 - 99.100.101
=> 3A = 100.101.102
=> A = 100.101.102 : 3
=> A = 343400
1.Tính
A= (1-1/22).(1-1/32)...(1-1/1002)
B= -1/1.2-1/2.3-1/3.4-...-1/100.101
C= 1.2+2.3+3.4+...+100.101
Lời giải :
Đặt S=1.2+2.3+3.4+4.5+…+99.100+100.101
3S=1.2.3+2.3.3+3.4.3+4.5.3+…+99.100.3+100.101.3
=1.2(3−0)+2.3(4−1)+3.4(5−2)+4.5(6−3)+…+99.100(101−98)+100.101(102−99)
=0.1.2-1.2.3+1.2.3-2.3.4+...+99.100.101-100.101.102
=100.101.102
S=100.101.34=343400
1.Tính
a) Ta có:
A=(1-1/22).(1-1/32)...(1-1/1002)
=>A=3/22.8/32.....9999/1002
=>A=(1.3/2.2).(2.4/3.3).....(99.101/100.100)
=>A=(1.2.3.....99/2.3.4.....100).(3.4.5.....101/2.3.4.....100)
=>A=1/100.101/2
=>A=101/200
b) Ta có:
B=-1/1.2-1/2.3-1/3.4-...-1/100.101
=>B=-(1/1.2+1/2.3+1/3.4+...+1/100.101)
=>B=-(1-1/2+1/2-1/3+1/3-1/4+...+1/100-1/101)
=>B=-(1-1/101)
=>B=-100/101
c) Ta có:
C=1.2+2.3+3.4+...+100.101
=>3C=1.2.3+2.3.3+3.4.3+...+100.101.3
=>3C=1.2.3+2.3.(4-1)+3.4.(5-2)+...+100.101.(102-99)
=>3C=1.2.3-1.2.3+2.3.4-2.3.4+3.4.5-3.4.5+...+100.101.102
=>3C=100.101.102
=>3C=1030200
=>C=343400
Chúc bạn hok tốt nhé >:)!!!!!
Tính: 1.2+2.3+3.4+......................100.101 = ?
Đặt S= 1.2 + 2.3 + 3.4 + ...+ 99.100
3S = 1.2.3+2.3.3+3.4.3+...+98.99.3+99.100.3
3S= 1.2.3+2.3(4-1)+3.4(5-2)+...+98.99(100-97)+99.100(101-98)
3S= 1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...-97.98.99+99.100.101-98.99.100
3S = 99.100.101 3S = 3.33.100.101
S=33.100.101= 333300
Nhớ **** cho mjk với nhak!!!!!
Đặt S= 1.2 + 2.3 + 3.4 + ...+ 99.100
3S = 1.2.3+2.3.3+3.4.3+...+98.99.3+99.100.3
3S= 1.2.3+2.3(4-1)+3.4(5-2)+...+98.99(100-97)+99.100(101-98)
3S= 1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...-97.98.99+99.100.101-98.99.100
3S = 99.100.101 3S = 3.33.100.101
S=33.100.101= 333300
Nhớ **** cko mjk nhak!!
Tính A=1.2+2.3+3.4+.....+100.101
A = 1.2 + 2.3 + 3.4 + ...... + 100.101
3A = 1.2.3 + 2.3.3 + 3.4.3 + ...... + 100.101.3
3A = 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ..... + 100.101.(102 - 99)
3A = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ...... + 100.101.102 - 99.100.101
3A = 100.101.102
A = 100.101.34
A = 343400
Tính nhanh: 1.2+2.3+3.4+...+100.101
Tính A=1.2+2.3+3.4+.....+100.101
Ta có: \(A=1.2+2.3+3.4+...+100.101\)
\(\Rightarrow3A=1.2.3+2.3.3+3.4.3+...+100.101.3\)
\(\Rightarrow3A=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+100.101\left(102-99\right)\)
\(\Rightarrow3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+100.101.102-99.100.101\)
\(\Rightarrow3A=\left(1.2.3-1.2.3\right)+...+\left(99.100.101-99.100.101\right)+100.101.102\)
\(\Rightarrow3A=\) \(100.101.102\)
\(\Rightarrow A=\dfrac{100.101.102}{3}=343400\)
Vậy \(A=343400.\)
A = 1.2+2.3+3.4+.....+100.101
3A = 1.2.3+2.3.4+3.4.3+...........+99.100.3
3A= 1.2.(3-0)+ 2.3.(4-1)+ 3.4.(5-2)....... . 99.100.(101-98)
3A=(1.2.3+2.3.4+3.4.5+......+99.100.101)-(0.1.2 + 1.2.3 + 2.3.4 +........+98.99.100)
3A = 99.100.101 - 0.1.2
3A = 999900 - 0
3A = 999900
=> A = 999900 : 3
=> A = 333300
câu này trên gg có r` bn!! bn lên tra nhé! mk k lm lại nx! Tiến Đạt
ps: gg là google
A=1.2+2.3+3.4+4.5+5.6+.......+99.100+100.101
A = 1.2 + 2.3 + 3.4 + 4.5 + ... + 99.100 + 100.101
3.A = 1.2.3 + 2.3.3 +3.4.3 + ... + 100.101.3
3A= 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 100.101.(102 - 99)
3A = 1.2.3 + 2.3.4 - 1.2.3 + 2.3.4 -3.4.5 + ... +99.100.101 -100.101.102
3A = 99.100.101
A = 99.100.101 : 3
A = 33.100.101
Vậy A = 33. 100 .101 (Tự tính)
1/1.2+1/2.3+1/3.4+...1/100.101
Áp dụng \(\frac{1}{a.\left(a+1\right)}=\frac{1}{a}-\frac{1}{a+1}\)
Ta có \(\frac{1}{1.2}+\frac{1}{2.3}+....+\frac{1}{100.101}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{100}-\frac{1}{101}\)
\(=1-\frac{1}{101}\)
\(=\frac{100}{101}\)
1/1.2+1/2.3+1/3.4+.....+1/100/101
=1-1/2+1/2-1/3+1/3-1/4+.....+1/100-1/101
=1-1/101
=100/101
tìm A biết A=1.2+2.3+3.4+4.5+...+99.100+100.101
A = 1.2 + 2.3 + 3.4 + ... + 99.100 + 100.101
⇒ 3A = 1.2.3 + 2.3.3 + 3.4.3 + ... + 99.100.3 + 100.101.3
= 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 99.100.(101 - 98) + 100.101.(102 - 99)
= 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + 3.4.5 + ... - 98.99.100 + 99.100.101 - 99.100.101 + 100.101.102
= 100.101.102
= 1030200
⇒ A = 1030200 : 3
= 343400