= 25 x 64 - 140 : 70 - \(17^{6+9-13}\)

= 1600 - 2 - 289 = 1309

\(703-140:\left(42+28\right)-17^6.17^9:17^{13}\)

\(=703-140:70-17^2\)

\(=701-17^2\)

\(=412\)

f: =703-2-289=703-291=412

\(703-140:\left(42+28\right)-17^{15}:17^{13}\)
\(=730-140:70-17^2\)
\(=730-2-289\)
\(=439\)

\(703-140:\left(42+28\right)-17^6.17^9:17^{13}\)

\(=703-140:70-17^{15}:17^{13}\)

\(=703-2-17^2\)

\(=412\)

\(a,-215-358+215+\left(-42\right)\\ =\left(-215+215\right)+\left(-358-42\right)\\ =0-400\\ =-400\\ b,13\cdot\left(23+22\right)-3\cdot\left(17+28\right)\\ =13\cdot45-3\cdot45\\ =45\cdot\left(13-3\right)\\ =45\cdot10\\ =450\)

AI GIÚP EM VỚI Ạ

\(#N\)

\(-\dfrac{11}{7}+\dfrac{13}{-2}+-\dfrac{6}{17}=-\dfrac{113}{14}+-\dfrac{6}{17}=-\dfrac{2005}{238}\)

\(\dfrac{13}{-8}+-\dfrac{7}{20}+\dfrac{3}{-8}=\left(-\dfrac{13}{8}+-\dfrac{3}{8}\right)+-\dfrac{7}{20}=-2+-\dfrac{7}{20}=-\dfrac{47}{20}\)

\(-\dfrac{4}{7}+\dfrac{11}{5}+\dfrac{1}{5}+-\dfrac{7}{3}=-\dfrac{4}{7}+\left(\dfrac{11}{5}+\dfrac{1}{5}\right)+-\dfrac{7}{3}=-\dfrac{4}{7}+\dfrac{12}{5}+-\dfrac{7}{3}=-\dfrac{53}{105}\)

Bài 3.21:

b: =28+19-28-32+57

=76-32

=44

A = (-135). 29 - 13. 135 + 42. (-65)

A = 135. (-29) - 13. 135 + 42. (-65)

A = 135. [(-29) - 13] + 42. (-65)

A = 135. (-42) + 42. (-65)

A = 135. (-42) + (-42). 65

A = (-42). (135 + 65)

A = (-42). 200

A = -8400

42 - 92 + 97 + (-42) - 97 

= (42 - 42) + (97 - 97) - 92 

= 0 + 0 - 92 

= -92