(-17) . (-125) -17. 25
x³ =125
4⁵:4³=
8¹² . 8³ : 8¹⁵=
7¹⁵ : 7¹³=
17¹⁵. 17¹⁰: 17²²=
5¹⁰ . 25 : 5¹¹=
15¹⁰ .225 : 15¹¹=
`@` `\text {Ans}`
`\downarrow`
`x^3 = 125`
`=> x^3 = 5^3`
`=> x = 5`
Vậy, `x = 5`
_____
`4^5 \div 4^3`
`=`\(4^{5-3}\)
`= 4^2`
______
\(8^{12}\cdot8^3\div8^{15}\)
`=`\(8^{12+3-15}\)
`=`\(8^0=1\)
______
\(7^{15}\div7^{13}\)
`=`\(7^{15-13}\)
`=`\(7^2\)
_______
\(17^{15}\cdot17^{10}\div17^{22}\)
`=`\(17^{15+10-22}\)
`= 17^3`
_______
\(5^{10}\cdot25\div5^{11}\)
`=`\(5^{10}\cdot5^2\div5^{11}\)
`=`\(5^{10+2-11}\)
`= 5`
_______
\(15^{10}\cdot225\div15^{11}\)
`=`\(15^{10}\cdot15^2\div15^{11}\)
`=`\(15^{12}\div15^{11}\)
`= 15`
`@` `\text {Kaizuu lv uuu}`
\(x^3=125\)
\(\Rightarrow x^3=5^3\)
\(\Rightarrow x=3\)
___________________
\(4^5:4^3\)
\(=4^{5-3}\)
\(=4^2=16\)
___________________
\(8^{12}.8^3:8^{15}\)
\(=8^{15}:8^{15}\)
\(=1\)
___________________
\(7^{15}:7^{13}\)
\(=7^{15-13}\)
\(=7^2=49\)
___________________
\(17^{15}.17^{10}:17^{22}\)
\(=17^{25}:17^{22}\)
\(=17^3=4913\)
___________________
\(5^{10}.25:5^{11}\)
\(=5^{10}.5^2:5^{11}\)
\(=5^{12}:5^{11}\)
\(=5^1=5\)
___________________
\(15^{10}.225:15^{11}\)
\(=15^{10}.15^2:15^{11}\)
\(=15^{12}:15^{11}\)
\(=15^1=15\)
__________________
* an . am = an+m
an : am = an-m
Chúc bạn học tốt
8. Bỏ dấu ngoặc rồi tính:
a) ( 17 – 229) + ( 17 - 25 + 229) ; b) ( 125 – 679 + 145) – ( 125 – 679 )
9. Tìm x biết: a) 15 – ( 4 – x) = 6 ; b) - 30 + ( 25 – x) = - 1 ;
c) x – ( 12 – 25) = -8 ; d) ( x – 29 ) – ( 17 – 38 ) = - 9
10. Tìm số nguyên x biết: a) x – 5 = - 1 ; b) x + 30 = - 4; c) x – ( - 24) = 3 ; d) 22 – ( - x ) = 12; e) ( x + 5 ) + ( x – 9 ) = x + 2 ; f) ( 27 – x ) + ( 15 + x ) = x – 24 .
Bỏ dấu ngoặc rồi tính
a) ( 17 – 229) + ( 17 – 25 + 229) ;
b) ( 125 – 679 + 145) – ( 125 – 679 )
a) ( 17 - 229 ) + ( 17 - 25 + 229 )
= 17 - 229 + 17 - 25 + 229
= 34 - 25
= 9
b) ( 125 - 679 + 145 ) - ( 125 - 679 )
= 125 - 679 + 145 - 125 - 679
= ( 125 - 125 ) - ( 679 - 679 ) + 145
= 0 + 145
= 145
a)( 17-229)+(17-25+229)
=17-229+17-25+229
=34-25
=9
b)(125-679+145)-(125-679)
=125-679+145-125+679
=145
Leo1eo_ Bạn làm ngắn gọn ghê zứa?
Bỏ dấu ngoăc rồi tính:
a)(17-229)+(17-25+229)
b)(125-679+145)-(125-679)
a) \(\left(17-229\right)+\left(17-25+229\right)\)
\(=17-229+17-25+229=9\)
b) \(\left(125-679+145\right)-\left(125-679\right)\)
\(=125-679+145-125+679=145\)
a.17-229+17-25+229
=(17+17)+(-229+229)+(-25)
=34+0+(-25)
=9
b.125-679+145-125+679
=(125-125)+(-679+679)+145
=0+0+145
=145
a) 8.25.(-125).4.12.(-2005)^0 .(-3)
b) -128.[(-25)+89]+128.(89-125)
c) 15.(17 - 111) - 17 .(222 +15)
a)8.25.(-125).4.12.(-2005)^0.(-3)
=8.25.(-125).4.12.(-1).(-3)
=(-125.8).(25.4).(-1.-3).12
=-1000.100.3.12
=-100000.3.12
=-3600000
b)-128.((-25)+89)+128.(89-125)
=-128.64+128.(-36)
=128.(-64)+128.(-36)
=128.(-64+-36)
=128.(-100)
=-12800
c)15.(17-111)-17.(222+15)
=15.(-94)-17.237
=-1410-4029
=-5439
bỏ dấu ngoặc rồi tính:
a (17-229)+(17-25+229)
b (125-679+145)-(125-679)
giúp mik với
a) \(\left(17-229\right)+\left(17-25+229\right)\)
\(=17-229+17-25+229\)
\(=34-25=9\)
b) \(\left(125-679+145\right)-\left(125-679\right)\)
\(=125-679+145-125+679\)
\(=145\)
a) 8.25.(-125).4.12.(-2005)^0 .(-3)
b) -128.[(-25)+89]+128.(89-125)
c) 15.(17 - 111) - 17 .(222 +15)
tính hợp lí
giải chi tiết xong mới tik .
bỏ ngặc đi rồi tính
(17-229) + (17-25+229)
b) (125-679 + 145 ) - ( 125 - 679 )
Mọi người giúp e với ạ
a)
17-229+17-25+229
=34-25+0
=9
b)
125-679+145-125+679
= 0 + 145 + 0
=145
a)17-229+17-25+229 b)125-679+145-125-629
=(17-17)+(229-229)+25 =(125-125)+(679-679)+145
=0+0+25 = 0+0+145
25 =145
Tính :
a)-17+5+8+17
b)(-17).(+125)-(-25).17
c)777-(-111)-(-222)+20
d)(-8).(+7).(-125)
Các bạn làm nhanh giúp mình nhé !
a,-17+5+8+17=13
b)(-17).(+125)-(-25).17
=17.(-125)-(-25).17
=17.[(-125)-(-25)]
=17.(-100)
= -1700
c)777-(-111)-(-222)+20=1103
d)(-8).(+7).(-125)
=[(-8).(-125)].7
= (-1000).7
= -7000