`a)1<3`

`=>1/5<3/5`

`b)21>9`

`=>8/21<8/9`

`c)3/5<5/5=1`

`d)7/5>5/5=1`

a)3/5>1/5 b)8/21<8/9 c)3/5<1 d)7/5>1

a 1/5<3/5

b 8/21<8/9

c 3/5<1

d 7/5>1

a) \(\dfrac{2}{5}=\dfrac{4}{10}\)

\(\dfrac{4}{10}>\dfrac{3}{10}\)

b) \(\dfrac{5}{6}=\dfrac{10}{12}\)

\(\dfrac{7}{12}< \dfrac{10}{12}\)

c) \(\dfrac{1}{2}=\dfrac{2}{4}\)

\(\dfrac{3}{4}< \dfrac{2}{4}\)

d) \(\dfrac{8}{3}=\dfrac{56}{21}\)

\(\dfrac{56}{21}>\dfrac{11}{21}\)

a) \(< \)

b) \(>\)

c) \(< \)

d) \(>\)

e) \(< \)

g) \(>\)

h) \(>\)

k) \(>\)

a) \(\dfrac{2}{3}=\dfrac{2.8}{3.8}=\dfrac{16}{24}\)

\(\dfrac{5}{8}=\dfrac{5.3}{8.3}=\dfrac{15}{24}\)

b) \(\dfrac{1}{4}=\dfrac{1.3}{4.3}=\dfrac{3}{12}\)

\(\dfrac{7}{12}=\dfrac{7.1}{12.1}=\dfrac{7}{12}\)

c) \(\dfrac{5}{6}=\dfrac{5.4}{6.4}=\dfrac{20}{24}\)

\(\dfrac{3}{8}=\dfrac{3.3}{8.3}=\dfrac{9}{24}\)

a) 58=5.38.3=152458=5.38.3=1524

b) 712=7.112.1=712712=7.112.1=712

c) 38=3.38.3=924

a) 58=5.38.3=152458=5.38.3=1524

b) 712=7.112.1=712712=7.112.1=712

c) 38=3.38.3=924

a)\(\dfrac{3}{7}=\dfrac{3.8}{7.8}=\dfrac{24}{56};\dfrac{5}{8}=\dfrac{5.7}{8.7}=\dfrac{35}{56}\)

b)\(\dfrac{7}{10}=\dfrac{7.2}{10.2}=\dfrac{14}{20};\dfrac{3}{20}\)

c)\(\dfrac{9}{20}=\dfrac{9.9}{20.9}=\dfrac{81}{180};\dfrac{2}{9}=\dfrac{2.20}{9.20}=\dfrac{40}{180}\)

ultr hôm nay học mà bn ko nhớ cách lm hẻ :))

Lời giải:

a.

$32^{47}=(2^5)^{47}=2^{5.47}=2^{235}$

$64^{33}=(2^6)^{33}=2^{6.33}=2^{198}$

Vì $2^{235}> 2^{198}$ nên $32^{47}> 64^{33}$

b.

$(\frac{1}{2})^{30}=\frac{1}{2^{30}}=\frac{1}{8^{10}}$

$(\frac{1}{3})^{20}=\frac{1}{3^{20}}=\frac{1}{9^{10}}$

Hiển nhiên $8^{10}< 9^{10}\Rightarrow \frac{1}{8^{10}}> \frac{1}{9^{10}}$

$\Rightarrow (\frac{1}{2})^{30}> (\frac{1}{3})^{20}$

>

<

>

a 

2/5> 2/7

5/9<5/6

11/2>11/3

cách so sánh :

 sét mẫu số của phân số này bé hơn mẫu số của phân số kia thì phân số này lớn hơn

 mẫu số của phân số này lớn hơn mẫu số của phân số kia thì phân số này bé  hơn 

><>

a: \(\dfrac{-7}{6}=\dfrac{-7\cdot3}{6\cdot3}=\dfrac{-21}{18}\)

\(\dfrac{-11}{9}=\dfrac{-11\cdot2}{9\cdot2}=\dfrac{-22}{18}\)

mà -21>-22

nên \(-\dfrac{7}{6}>-\dfrac{11}{9}\)

b: \(\dfrac{5}{-7}=\dfrac{-5}{7}=\dfrac{-5\cdot5}{7\cdot5}=\dfrac{-25}{35}\)

\(\dfrac{-4}{5}=\dfrac{-4\cdot7}{5\cdot7}=\dfrac{-28}{35}\)

mà -25>-28

nên \(\dfrac{5}{-7}>\dfrac{-4}{5}\)

c: \(\dfrac{-8}{7}< -1\)

\(-1< -\dfrac{2}{5}\)

Do đó: \(-\dfrac{8}{7}< -\dfrac{2}{5}\)

d: \(-\dfrac{2}{5}< 0\)

\(0< \dfrac{1}{3}\)

Do đó: \(-\dfrac{2}{5}< \dfrac{1}{3}\)

a) \(\dfrac{3}{4}=\dfrac{3\cdot5}{4\cdot5}=\dfrac{15}{20}\\ \dfrac{2}{5}=\dfrac{2\cdot4}{5\cdot4}=\dfrac{8}{20}\)

b) \(\dfrac{5}{12}=\dfrac{5\cdot3}{12\cdot3}=\dfrac{15}{36}\\ \dfrac{11}{36}=\dfrac{11}{36}\)

c) \(\dfrac{2}{3}=\dfrac{2\cdot4\cdot5}{3\cdot4\cdot5}=\dfrac{40}{60}\\ \dfrac{3}{4}=\dfrac{3\cdot3\cdot5}{4\cdot3\cdot5}=\dfrac{45}{60}\\ \dfrac{4}{5}=\dfrac{4\cdot3\cdot4}{5\cdot3\cdot4}=\dfrac{48}{60}\)

a) \(\dfrac{3}{4}\) và \(\dfrac{2}{5}\)

Mẫu số chung: 20

\(\dfrac{3}{4}=\dfrac{3.5}{4.5}=\dfrac{15}{20}\)

\(\dfrac{2}{5}=\dfrac{2.4}{5.4}=\dfrac{8}{20}\)

b) \(\dfrac{5}{12}\) và \(\dfrac{11}{36}\)

Mẫu số chung: 36

\(\dfrac{5}{12}=\dfrac{5.3}{12.3}=\dfrac{15}{36}\)

c) \(\dfrac{2}{3};\dfrac{3}{4}\) và \(\dfrac{4}{5}\)

Mẫu số chung: 60

\(\dfrac{2}{3}=\dfrac{2.20}{3.20}=\dfrac{40}{60}\\ \dfrac{3}{4}=\dfrac{3.15}{4.15}=\dfrac{45}{60}\\ \dfrac{4}{5}=\dfrac{4.12}{5.12}=\dfrac{48}{60}\)

a) MTC=20

 \(\dfrac{3}{4}=\dfrac{15}{20}\)

\(\dfrac{2}{5}=\dfrac{8}{20}\)

b) MTC=36 

\(\dfrac{5}{12}=\dfrac{15}{36}\)

\(\dfrac{11}{36}=\dfrac{11}{36}\)

c) MTC=60

\(\dfrac{2}{3}=\dfrac{40}{60}\)

\(\dfrac{3}{4}=\dfrac{45}{60}\)

\(\dfrac{4}{5}=\dfrac{48}{60}\)