2 phan x = 1 phan 3
cau1:1 pha n5.(-3 phan 5 - 10)+ 5x =x -2 phan 3
cau2:-3 phan 2(5 - 1 phan 6) +4 (x-1 phan 2)=1
Bai 1 Tim x
A) x nhan 4 phan 5 = 1 phan 2 nhan 1 phan 3
B ) x : 2 phan 5 = 2phan 3 + 1 phan 2
A
x. 3 phan 4 - 1 = 2 phan 75
B 3 - x : 2 phan 3 = 75
\(a,x.\frac{3}{4}-1=\frac{2}{75}\)
\(x.\frac{3}{4}=\frac{77}{75}\)
\(x=\frac{77}{75}:\frac{3}{4}=\frac{308}{225}\)
\(b,3-x:\frac{2}{3}=75\)
\(x:\frac{2}{3}=-72\)
\(x=-72.\frac{2}{3}=-48\)
X-1 phan x+2=x-2 phan x+3
tim z,y,z thoa
can x cong can tat ca y tru 1 cong can tat ca z tru 2 bang 1 phan 2 ( x cong y cong z)
tim GTN cua B bang 1 phan x tru can x cong 1
tim x thuoc z de can x cong 1 phan can 3 tru 3 la so nguyen
tinh tong T bang 1 phan can 1 cong can 2 cong 1 phan can 2 cong can 3 cong ... cong den 1 phan can 99 cong can 100
viet tap hop cac so nguyen x
1) 9 < x <= -2
2) -35 phan 7 < x < -1
3) -21 phan 3 <= x <= 0 phan 7
1 phan 4 :(x phan 4 + (-2) phan 7 + 2 phan 8)=(-1) phan 14
\(\frac{1}{4}:\left(\frac{x}{4}+\frac{\left(-2\right)}{7}+\frac{2}{8}\right)=\frac{\left(-1\right)}{14}\)
\(\frac{1}{4}:\left(\frac{x}{4}+\frac{\left(-1\right)}{28}\right)=\frac{\left(-1\right)}{14}\)
\(\frac{x}{4}+\frac{\left(-1\right)}{28}=\frac{1}{4}:\frac{\left(-1\right)}{14}\)
\(\frac{x}{4}+\frac{\left(-1\right)}{28}=\frac{-7}{2}\)
\(\frac{x}{4}=\frac{-7}{2}-\frac{\left(-1\right)}{28}\)
\(\frac{x}{4}=\frac{-97}{28}\)
\(\frac{7x}{28}=\frac{-97}{28}\)
\(\Rightarrow7x=-97\)
\(\Rightarrow x=-97:7\)
\(\Rightarrow x=\frac{-97}{7}\)
Váy \(x=\frac{-97}{7}\)
Nhớ k cho mk nha Le Ha Trang
1 phan 5 nhan 8 cong 1 phan 8 nhan 11 cong 1 phan 11 nhan 14 +..........+1 phan x nhan (x+3)=101 phan 1540
1 phan 5 nhan 8 cong 1 phan 8 nhan 11 cong 1 phan 11 nhan 14 +..........+1 phan x nhan (x+3)=101 phan 1540
\(\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{x.\left(x+3\right)}=\frac{101}{1540}\)
\(\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{x.\left(x+3\right)}=\frac{303}{1540}\)
\(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{x}-\frac{1}{x+3}=\frac{303}{1540}\)
\(\frac{1}{5}-\frac{1}{x+3}=\frac{303}{1540}\)
\(\frac{1}{x+3}=\frac{1}{308}\)
\(\Rightarrow x+3=308\)
\(x=305\)
Tim so tu nhien x biet:
1 phan 2+1 phan 6+1 phan 12+...+1 phan x(x+1)=2008 phan 2009
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+....+\frac{1}{x\left(x+1\right)}=\frac{2008}{2009}\)
\(=>\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{x\left(x+1\right)}=\frac{2008}{2009}\)
\(=>\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{2008}{2009}\)
\(=>1-\frac{1}{x+1}=\frac{2008}{2009}=>\frac{1}{x+1}=1-\frac{2008}{2009}=\frac{1}{2009}\)
=>x+1=2009
=>x=2008
Vậy x=2008
1/2+1/6+1/12+...+1/x*(x+1)=2008/2009
1/1*2+1/2*3+1/3*4+...+1/x*(x+1)=2008/2009
1-1/2+1/2-1/3+1/3-1/4+...+1/x-1/(x+1)=2008/2009
1-1/x+1)=2008/2009
1/x+1=1-2008/2009
1/x+1=1/2009
nên x+1=2009
x=2009-1
x=2008 (tick nha)