a: =>x/-3=3

hay x=-9

b: =>x/9=-1/9

hay x=-1

c: =>x+1/5=-1/3

hay x=-8/15

d: =>-7/x=-7/9

hay x=9

a, \(\dfrac{x}{-3}=3\Leftrightarrow x=-9\)

b, \(\dfrac{x}{9}=-\dfrac{1}{9}\Rightarrow x=-1\)

c, \(\dfrac{x+3}{15}=-\dfrac{6}{15}\Rightarrow x=-9\)

d, \(\dfrac{42}{-54}=-\dfrac{42}{6x}\Rightarrow6x=54\Leftrightarrow x=9\)

a: =>x+7/4=6:2/3=9

=>x=29/4

b: =>x:5/3=7/5

=>x=7/5*5/3=7/3

c:=>x+1/6=5/3

=>x=10/6-1/6=3/2

d: =>x+4/5=4/5+3/7+3/5

=>x=3/7+3/5=36/35

e: =>x/35=4/5-5/7=3/35

=>x=3

f: =>13/28+x=1/2

=>x=1/28

g: =>1/3-x=1/9

=>x=2/9

b: \(\dfrac{5}{7}-\dfrac{2}{3}\cdot x=\dfrac{4}{5}\)

=>\(\dfrac{2}{3}x=\dfrac{5}{7}-\dfrac{4}{5}=\dfrac{25-28}{35}=\dfrac{-3}{35}\)

=>\(x=-\dfrac{3}{35}:\dfrac{2}{3}=\dfrac{-3}{35}\cdot\dfrac{3}{2}=-\dfrac{9}{70}\)
c: \(\dfrac{1}{2}x+\dfrac{3}{5}x=-\dfrac{2}{3}\)

=>\(x\left(\dfrac{1}{2}+\dfrac{3}{5}\right)=-\dfrac{2}{3}\)

=>\(x\cdot\dfrac{5+6}{10}=\dfrac{-2}{3}\)

=>\(x\cdot\dfrac{11}{10}=-\dfrac{2}{3}\)

=>\(x=-\dfrac{2}{3}:\dfrac{11}{10}=-\dfrac{2}{3}\cdot\dfrac{10}{11}=\dfrac{-20}{33}\)

d: \(\dfrac{4}{7}\cdot x-x=-\dfrac{9}{14}\)

=>\(\dfrac{-3}{7}\cdot x=\dfrac{-9}{14}\)

=>\(\dfrac{3}{7}\cdot x=\dfrac{9}{14}\)

=>\(x=\dfrac{9}{14}:\dfrac{3}{7}=\dfrac{9}{14}\cdot\dfrac{7}{3}=\dfrac{3}{2}\)

a) x : 1/4 = 7/5
    x         = 7/5 x 1/4
    x         = 7/20
b) 9/2 - x = 3/5
            x = 9/2 - 3/5
            x = 39/10
c) 12/5 : x = 7/2
              x = 12/5 : 7/2
              x = 24/35

a) \(x\div\dfrac{1}{4}=\dfrac{7}{5}\)

    \(x=\dfrac{7}{5}\times\dfrac{1}{4}\)

    \(x=\dfrac{7}{20}\)

b) \(\dfrac{9}{2}-x=\dfrac{3}{5}\)

            \(x=\dfrac{9}{2}-\dfrac{3}{5}\)

            \(x=\dfrac{39}{10}\)

c) \(\dfrac{12}{5}\div x=\dfrac{7}{2}\)

             \(x=\dfrac{12}{5}\div\dfrac{7}{2}\)

             \(x=\dfrac{12}{5}\times\dfrac{2}{7}\)

             \(x=\dfrac{24}{35}\)

a)\(x=\dfrac{1}{4}\)x\(\dfrac{7}{5}=\dfrac{7}{20}\)

b)\(x=\dfrac{9}{2}-\dfrac{3}{5}=\dfrac{39}{10}\)

c)\(x=\dfrac{12}{5}:\dfrac{7}{2}=\dfrac{24}{35}\)

a: \(x-\dfrac{10}{3}=\dfrac{7}{15}\cdot\dfrac{3}{5}\)

=>\(x-\dfrac{10}{3}=\dfrac{21}{75}=\dfrac{7}{25}\)

=>\(x=\dfrac{7}{25}+\dfrac{10}{3}=\dfrac{21+250}{75}=\dfrac{271}{75}\)

b: \(x+\dfrac{3}{22}=\dfrac{27}{121}\cdot\dfrac{9}{11}\)

=>\(x+\dfrac{3}{22}=\dfrac{243}{1331}\)

=>\(x=\dfrac{243}{1331}-\dfrac{3}{22}=\dfrac{123}{2662}\)

c: \(\dfrac{8}{23}\cdot\dfrac{46}{24}-x=\dfrac{1}{3}\)

=>\(\dfrac{8}{24}\cdot\dfrac{46}{23}-x=\dfrac{1}{3}\)

=>\(\dfrac{2}{3}-x=\dfrac{1}{3}\)

=>\(x=\dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}\)

d: \(1-x=\dfrac{49}{65}\cdot\dfrac{5}{7}\)

=>\(1-x=\dfrac{49}{7}\cdot\dfrac{5}{65}=\dfrac{7}{13}\)

=>\(x=1-\dfrac{7}{13}=\dfrac{6}{13}\)

a, 11 - ( 15 + 11 ) = x - ( 25 - 9 )

11-15-11=x-25+9

-15=x-16

x=1

b, 2 - x = 17 - ( - 5 )

2-x=22

x=-20

c, x - 12 = ( - 9 ) - 15

x-12=-24

x=-12

d, 9 - 25 = ( 7 - x ) - ( 25 + 7 )

(7-x)-32=-16

7-x=16

x=-9

#H

(x-14)-20=5

=> x-14 = 25

=> x = 39

Các dạng toán như này lớp 6 ai cũng làm được cả * lười vừa thôi*

( x - 14 ) - 20 = 5

 x - 14 = 5 + 20

 x - 14 = 25

 x = 25 + 14

 x = 39

128 + ( 202 - x ) = 330

           [ 202 - x ] = 330 - 128

             202 - x = 202

                      x = 202 - 202

                      x = 0

( x - 120 ) x 9 = 450

[ x - 120 ] = 450 : 9

 x - 120 = 50

 x = 50 + 120

 x = 170

x - 320 : 32 = 25 x 16

x - 320 : 32 = 400

x - 320 = 400 x 32

x - 320 = 12800

x = 12800 + 320

x = 13120

25 - ( 2x +10 ) = 5

        [ 2x + 10] = 25 - 5

          2x + 10 = 20

          2x = 20 - 10

          2x = 10

            x = 10 : 2

            x = 5

315 - ( 135 - x ) = 215

          [ 135 - x ] = 315 - 215

          [ 135 - x ] = 100

                      x = 135 - 100

                      x = 35

x : 2 + 21 : 3 = 37

x : 2 + 21 = 37 x 3

x : 2 + 21 = 111

x : 2 = 111 - 21

x : 2 = 90

x = 90 x 2

x = 180

4 x ( x + 100 ) = 800

      [ x + 100 ] = 800 : 4

      [ x + 100 ] = 200

       x = 200 - 100

       x = 100

504 : ( 16 - 5x ) = 72

          [ 16 - 5x ] = 504 : 72

           [ 16 - 5x ] = 7

                     5x = 16 - 7

                     5x = 9

                       x = \(\dfrac{9}{5}\)

( x - 5 ) : 7 + 3 = 20

[ x - 5 ] : 7 = 20 - 3

[ x - 5 ] : 7 = 17

[ x - 5 ] = 17 x 7

 x - 5 = 119

 x = 119 + 5

 x = 124

a,11-(15+21)=x-(25-9)

      11-15-21=x-25+9

               -x=-25+9-11+15+21

               -x=9

                x=-9

b,9-25=(7-x)-(25+7)

    -16=7-x-32

      x=7-32+16

     x=-9

 Câu 5. Tìm các số x thỏa mãn cả hai bất phương trình sau x>3 và x<8

A. x<8  

b. 3<x<8

c. 3>x>8

d. x>3

câu 6: tìm các số x thỏa mãn cả 2 bất phương trình sau x>5 và x>3

A. x<5

B. 3<x<5

C. x>3

D. c>5