\(a,f\left(-2\right)=\dfrac{3}{4}\left(-2\right)=-\dfrac{3}{2}\\ f\left(0\right)=\dfrac{3}{4}\cdot0=0\\ f\left(1\right)=\dfrac{3}{4}\cdot1=\dfrac{3}{4}\\ b,g\left(-2\right)=\dfrac{3}{4}\left(-2\right)+3=-\dfrac{3}{2}+3=\dfrac{3}{2}\\ g\left(0\right)=\dfrac{3}{4}\cdot0+3=3\\ g\left(1\right)=\dfrac{3}{4}\cdot1+3=\dfrac{15}{4}\)

Ta có: \(y=f\left(x\right)=4x-3\)

\(f\left(1\right)=4.1-3=1\)

\(f\left(2\right)=4.2-3=8-3=5\)

\(\text{f(1)=4.1-3=4-3=1}\)

\(\text{f(2)=4.2-3=8-3=5}\)

\(f\left(1\right)=4\cdot1-5=-1\)

\(f\left(3\right)=4\cdot3-5=7\)

Nếu : f(x)=f(2) => f(2)=4.(2)+2=8+2=10

Nếu : f(-3)=f9-3)=>f(-3)=4.(-3)+2=-12+2=-10

f(2)= 4.2+2= 10

f(-3)= 4.(-3)+2= -10

tick nha 

tui trả lời trước đó cao nguyễn uyên :))

\(f\left(3\right)=4.3^2-5=31\)

\(f\left(\frac{-1}{2}\right)=4.\left(\frac{-1}{2}\right)^2-5=-4\)

a: f(2)=9

f(-1/4)=0

\(a,f\left(2\right)=8+1=9\\ f\left(-\dfrac{1}{4}\right)=4\left(-\dfrac{1}{4}\right)+1=-1+1=0\\ b,f\left(x\right)=13\Leftrightarrow4x+1=13\Leftrightarrow x=3\)

ta có f(x)=4x+1

--> f(2)=4*2+1=9

--> f(-4)=4*(-4)+1=-15

tick nha bạn

Ta có hàm số : y = f(x) = 4x + 1

=> f(2) = 4*2 + 1 = 8 + 1 = 9

     f(-4) = 4 * (-4) + 1 = 0 + 1 = 1

giúp em với ạ :<