Tính bằng cách thuận tiện nhất
a) 360 : 3 + 126 : 3 + 123 : 3
b) 436 : 4 + 164 : 4 - 200 : 4
c) 525 : 5 + 120 : 5 - 145 : 5
Tính = cách thuận tiện nhất
a) 8/13+ 4/9+ 1/3 + 5/13+ 3
b)8/5x 4/7 + 47 x 2/5 - 1
\(\dfrac{8}{13}+\dfrac{4}{9}+\dfrac{1}{3}+\dfrac{5}{13}+3\)
\(=1+\dfrac{7}{9}+3\)
\(=4+\dfrac{7}{9}=\dfrac{43}{9}\)
Tính bằng cách thuận tiện nhất
A) 39/16 : 5/8 - 7/16 : 5/8
b) 4/3 X 9/8 - 4/3 X 3/8
`39/16 : 5/8 - 7/16 : 5/8`
`=39/16 xx 8/5- 7/16 xx 8/5`
`=8/5 xx (39/16 - 7/16)`
`= 8/5 xx2`
`= 16/5`
__
` 4/3 xx 9/8 - 4/3 xx 3/8`
`=4/3 -(9/8 - 3/8)`
`= 4/3 xx 3/4`
`=1`
\(a,\\ \dfrac{39}{16}:\dfrac{5}{8}-\dfrac{7}{16}:\dfrac{5}{8}\\ =\dfrac{39}{16}\cdot\dfrac{8}{5}-\dfrac{7}{16}\cdot\dfrac{8}{5}\\ =\dfrac{8}{5}\cdot\left(\dfrac{39}{16}-\dfrac{7}{16}\right)=\dfrac{8}{5}\cdot2=\dfrac{16}{5}\\ b,\\ \dfrac{4}{3}\cdot\dfrac{9}{8}-\dfrac{4}{3}\cdot\dfrac{3}{8}=\dfrac{3}{2}-\dfrac{1}{2}=1\)
a)
`39/16:5/8-7/16:5/8`
`=(39/16-7/16):5/8`
`=32/16xx8/5`
`=2xx8/5`
`=16/5`
b)
`4/3xx9/8-4/3xx3/8`
`=4/3xx(9/8-3/8)`
`=4/3xx6/8`
`=4/3xx3/4`
`=1`
Tính bằng cách thuận tiện nhất
a)3/5x17/21+17/21x2/5
b)15/8:5/20-7/8:1/4
a) \(\dfrac{3}{5}\times\dfrac{17}{21}+\dfrac{17}{21}\times\dfrac{2}{5}\)
\(=\dfrac{17}{21}\times\left(\dfrac{3}{5}+\dfrac{2}{5}\right)\)
\(=\dfrac{17}{21}\times1\)
\(=\dfrac{17}{21}\)
b) \(\dfrac{15}{8}:\dfrac{5}{20}-\dfrac{7}{8}:\dfrac{1}{4}\)
\(=\dfrac{15}{8}\times\dfrac{20}{5}-\dfrac{7}{8}\times4\)
\(=\dfrac{15}{8}\times4-\dfrac{7}{8}\times4\)
\(=4\times\left(\dfrac{15}{8}-\dfrac{7}{8}\right)\)
\(=4\times1\)
\(=4\)
a) \(\dfrac{3}{5}\) x \(\dfrac{17}{21}+\dfrac{17}{21}\) x \(\dfrac{2}{5}\)
\(=\left(\dfrac{3}{5}+\dfrac{2}{5}\right)\) x \(\dfrac{17}{21}\)
\(=\dfrac{5}{5}\) x \(\dfrac{17}{21}\)
\(=1\) x \(\dfrac{17}{21}\)
\(=\dfrac{17}{21}\)
b) \(\dfrac{15}{8}:\dfrac{5}{20}-\dfrac{7}{8}:\dfrac{1}{4}\)
\(=\dfrac{15}{8}:\dfrac{1}{4}-\dfrac{7}{8}:\dfrac{1}{4}\)
\(=\left(\dfrac{15}{8}-\dfrac{7}{8}\right):\dfrac{1}{4}\)
\(=\dfrac{8}{8}:\dfrac{1}{4}\)
\(=1:\dfrac{1}{4}\)
\(=\dfrac{1}{1}:\dfrac{1}{4}\)
\(=\dfrac{1}{1}\) x \(\dfrac{4}{1}\)
\(=\dfrac{4}{1}\)
\(=4\)
Bài 2: Tính bằng cách thuận tiện nhất
a. 1255 +436 +145
b. 142 x 12 +142 x 18
c. 4 x 18 x 25
.............................................................................................................................. .............................................................................................................................. ..............................................................................................................................
.............................................................................................................................. .............................................................................................................................. .............................................................................................................................. Bài 3: > < =
41m2 19dm2 … 409dm2 30m2 6dm2 … 3060dm2 5dm2 9cm2 … 509cm2 300m2 6dm2 … 3006dm2 giúp vs ạ | 90 000cm2 … 90m2 8012cm2 … 8dm2 12cm2 3940dm2 … 39m2 40dm2 2009cm2 … 21dm2 |
Bài 2: Tính bằng cách thuận tiện nhất
\(\text{a. 1255 + 436 + 145}\)
\(=\left(1255+145\right)+436\)
\(=1400+436\)
\(=1836\)
\(\text{b. 142 x 12 + 142 x 18}\)
\(=142\times\left(12+18\right)\)
\(=142\times30\)
\(=4260\)
\(\text{c. 4 x 18 x 25}\)
\(=\left(25\times4\right)\times18\)
\(=100\times18\)
\(=1800\)
Bài 2:
a: \(=1400+436=1836\)
b: =142(12+18)
=142*30
=4260
c: \(=100\cdot18=1800\)
Bài 3:
a: \(41m^219dm^2>409dm^2\)
b: \(90000cm^2< 90m^2\)
c: \(30m^26dm^2< 3060dm^2\)
d: \(8012cm^2>8dm^212cm^2\)
e: \(5dm^29cm^2=509cm^2\)
f: \(3940dm^2=39m^240dm^2\)
g: \(300m^26dm^2>3006dm^2\)
h: \(2009cm^2< 21dm^2\)
Bài 5: Tính bằng cách thuận tiện nhất
a.1999 – 2000 + 1
b. 450 : 5 + 550 : 5
c. 188 x 7 + 188 x 4 - 188
\(a,1999-2000+1=\left(1999+1\right)-2000=2000-2000=0\\ b,450:5+550:5=\left(450+550\right):5=1000:5=200\\ c,188\times7+188\times4-188=188\times\left(7+4-1\right)=188\times10=1880\)
a,1999−2000+1=(1999+1)−2000=2000−2000=0b,450:5+550:5=(450+550):5=1000:5=200c,188×7+188×4−188=188×(7+4−1)=188×10=1880
a) 1999 - 2000 + 1
= ( 1999 + 1 ) - 2000
= 2000 - 2000
= 0
b) 450 : 5 + 550 : 5
= ( 450 + 550 ) : 5
= 1000 : 5
= 200
c) 188 x 7 + 188 x 4 - 188
= ( 7 + 4 - 1 ) x 188
= 10 x 188
= 1880
Tính bằng cách thuận tiện:
a) 2/3 x 4/9 + 2/3 x 5/9
b, 7/5 x 3/4 - 1/2 x 3/4
c, ( 5/6 + 5/8 ) x 2/3
a.\(\dfrac{2}{3}\times\dfrac{4}{9}+\dfrac{2}{3}\times\dfrac{5}{9}=\dfrac{2}{3}\times\left(\dfrac{4}{9}+\dfrac{5}{9}\right)=\dfrac{2}{3}\times1=\dfrac{2}{3}\)
b.\(\dfrac{7}{5}\times\dfrac{3}{4}-\dfrac{1}{2}\times\dfrac{3}{4}=\dfrac{3}{4}\times\left(\dfrac{7}{5}-\dfrac{1}{2}\right)=\dfrac{3}{4}\times\dfrac{9}{10}=\dfrac{27}{40}\)
c.\(\left(\dfrac{5}{6}+\dfrac{5}{8}\right)\times\dfrac{2}{3}=\dfrac{35}{24}\times\dfrac{2}{3}=\dfrac{35}{36}\)
a) 2/3 x 4/9 + 2/3 x 5/9
=2/3 x ( 4/9 + 5/9)
= 2/3 x 1
= 2/3
b, 7/5 x 3/4 - 1/2 x 3/4
= ( 7/5 - 1/2 ) x 3/4
= 9/10 x 3/4
= 21/40
c, ( 5/6 + 5/8 ) x 2/3
= 35/24 x 2/3
= 35/36
a) \(\dfrac{2}{3}\times\dfrac{4}{9}+\dfrac{2}{3}\times\dfrac{5}{9}=\dfrac{2}{3}\times\left(\dfrac{4}{9}+\dfrac{5}{9}\right)=\dfrac{2}{3}\times1=\dfrac{2}{3}\)
b) \(\dfrac{7}{5}\times\dfrac{3}{4}-\dfrac{1}{2}\times\dfrac{3}{4}=\left(\dfrac{7}{5}-\dfrac{1}{2}\right)\times\dfrac{3}{4}=\dfrac{9}{10}\times\dfrac{3}{4}=\dfrac{27}{40}\)
c) \(\left(\dfrac{5}{6}+\dfrac{5}{8}\right)\times\dfrac{2}{3}=\left(\dfrac{20}{24}+\dfrac{15}{24}\right)\times\dfrac{2}{3}=\dfrac{35}{24}\times\dfrac{2}{3}=\dfrac{35}{36}\)
Tính bằng cách thuận tiện nhất:
a) 145 + 86 + 14 + 55
b) 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9
a) 145 + 86 + 14 + 55 = ( 145 + 55 ) + (86 + 14 )
= 200 + 100
= 300
b) 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = ( 1+9 +2 + 8) + ( 3 + 7 + 4 + 6 ) + 5
= 20 + 20 + 5
= 45
tính bằng 2 cách:
a.4 nhân 5 nhân 3
b.3 nhân 5 nhân 6
tính bằng cách thuận tiện nhất:
a.13 nhân 5 nhân 2
b.5 nhân 2 nhân 34
a)
C1: 4✖5✖3 C2:4✖5✖3
=20✖3 =12✖5
=60 =60
b)
C1: 3✖5✖6 C2:3✖5✖6
=15✖6 =18✖5
=90 =90
Tính thuận tiện
a)13✖5✖2 b)5✖2✖34
=13✖10 =10✖34
=130 =340
tính bằng 2 cách:
a.4 nhân 5 nhân 3
C1 : 4 x 5 x 3
= 20 x 3
= 60
C2 : 4 x 5 x 3
= ( 4 x 5 ) x 3
= 20 x 3
= 60
b.3 nhân 5 nhân 6
C1 : 3 x 5 x 6
= 15 x 6
= 90
C2 : 3 x 5 x 6
= 3 x ( 5 x 6 )
= 3 x 30
= 90
tính bằng cách thuận tiện nhất:
a.13 nhân 5 nhân 2
13 x 5 x 2
= 13 x ( 5 x 2 )
= 13 x 10
= 130
b.5 nhân 2 nhân 34
5 x 2 x 34
= ( 5 x 2 ) x 34
= 10 x 34
= 340
Câu 8 : hình thoi ABCD có đọ dài đường chéo AC là 4 3/4 dm; độ dài đường chéo BD ngắn hơn AC là 7/12 dm. Tính diện tích hình thoi đó
Câu 9 : tính bằng cách thuận tiện nhất
a. 2/9 + 1/5 + 7/9 + 4/5 = .............................................................................................
b. 1/12 + 3/16 + 5/12 =...................................................................................................
Câu 1:
Câu 2:
b) 1/12 + 3/16 + 5/12 + 5/16
=(1/12 + 5/12) + (3/16 + 5/16)
=1/2 + 1/2
=2/2
=1
a) 1/2 + 3/16 + 5/12 + 5/16
=5/12 + (1/2 + 3/16 + 5/16)
= 5/12 + 1
= 15/12
(Đúng tick, sai bảo)
Bổ sung câu a:>
a) 2/9 + 1/5 + 7/9 + 4/5
= (2/9 + 7/9) + (1/5 + 4/5)
= 9/9 + 5/5
= 1 + 1
=2
a (2/9+7/9)+(1/5 +1/5)=9/9+5/5=1+1=2
b( 1/12+5/12) +3/16= 1/2+3/16=8/16+3/16=11/16
Đúng tisk nhé