chung minh rang

\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{199}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{200}\)

giup minh minh like cho nho giai chi tiet mot chut nhe

Chứng minh:\(\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{149}+\frac{1}{150}>\frac{1}{3}\)

tinh:

\(3+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^{100}}\)

\(\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)...\left(1+\frac{1}{2014.2016}\right)\)

trinh bay cach lam nua nhe

CHÚNG TỎ RẰNG :

\(\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+..........+\frac{1}{149}+\frac{1}{150}>\frac{1}{3}\)

Tinh:

\(B=\frac{\frac{1}{7}+\frac{1}{23}-\frac{1}{1009}}{\frac{1}{7}+\frac{1}{23}-\frac{1}{1009}+\frac{1}{7}.\frac{1}{23}.\frac{1}{1009}}\)

Trinh bay cach lam nua nhe

Co gi ko hieu thi vao phan doc them

Chứng tỏ rằng: ​​\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{199}+\frac{1}{200}\)

Help me

C = \(\frac{1+\frac{1}{3}+\frac{1}{3^2}+....+\frac{1}{3^{100}}}{1+\frac{1}{3}+......+\frac{1}{3^{101}}}\)

D = \(\frac{1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^{101}}}{1+\frac{1}{3}+........+\frac{1}{3^{102}}}\)

ai lam ho minh voi  so sanh nha

Chứng minh rằng:

\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{199}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{200}\) 

Help me!!!!!!!

Tinh gia tri cua bieu thuc \(D=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{200}\)

Nho giai va tring bay cach lam cho minh luon nha ^_^