\(M=\sqrt{\dfrac{2^{30}-2^{20}}{2^{22}-2^{12}}}=\sqrt{\dfrac{2^{20}\left(2^{10}-1\right)}{2^{12}\left(2^{10}-1\right)}}=\sqrt{2^8}=\sqrt{16^2}=16\)

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{ \left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=\frac{2^{20}}{2^{12}}=2^8=256\)

Chúc học tốt :)

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)

\(M=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}\)

\(M=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)

\(M=\frac{2^{20}.\left(2^{10}+1\right)}{2^{12}.\left(1+2^{10}\right)}\)

\(M=\frac{2^{20}}{2^{12}}\)

\(M=2^8=256\)

\(M=\frac{8^{10}+4^{10}=1.074.790.400}{8^4+4^{11}=4.198.400}\)

Vậy 

\(\Rightarrow M=\frac{1.074.790.400}{4.198.400}\)

P/s; Ko chắc đâu nhé

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{12}.2^8\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=2^8\)

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=\frac{2^{20}}{2^{12}}=2^8\)

tách 8 thành 2 mũ 3, 4 thành 2 mũ 2 là sẽ ra nhé 

đáp án là 2 mũ 8 

\(M=\sqrt{\frac{8^{10}-4^{10}}{4^{11}-8^4}}\)

\(=\sqrt{\frac{2^{30}-2^{20}}{2^{22}-2^{12}}}\)

\(=\sqrt{\frac{2^{20}\left(2^{10}-1\right)}{2^{12}\left(2^{10}-1\right)}}\)

\(=\sqrt{\frac{2^{20}}{2^{12}}}\)

\(=\sqrt{2^8}\)

\(=2^4\)

\(=16\)

=.= hok tốt!!

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)

\(M=\frac{8^4+4^{10}.8^6}{8^4+4^{10}.4}\)

\(M=1\frac{8^6}{8^4+4^{10}.4}\)

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)

\(M=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)

\(M=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(2^{10}+1\right)}\)

\(M=2^8\)

\(M=256\)

\(m=\dfrac{8^{10}+4^{10}}{8^4+4^{11}}=\dfrac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}=\dfrac{2^{30}+2^{20}}{2^{12}+2^{22}}=\dfrac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=\dfrac{2^{20}}{2^{12}}=2^8=256\)Vậy \(m=256\)