Bày đặt sad mặt tâm trạng đồ😂

Bài 1.

a. $=a^2+2.a.12+12^2=a^2+24a+144$

b. $=(3a)^2+2.3a.\frac{1}{3}+(\frac{1}{3})^2=9a^2+2a+\frac{1}{9}$

c. $=(5a^2)^2+2.5a^2.6+6^2=25a^4+60a^2+36$

d. $=\frac{1}{4}+2.\frac{1}{2}.4b+(4b)^2$

$=\frac{1}{4}+4b+16b^2$

e.

$=(a^m)^2+2.a^m.b^n+(b^n)^2$

$=a^{2m}+2a^mb^n+b^{2n}$

Bài 2.

$(x-0,3)^2=x^2-0,6x+0,09$

$(6x-3y)^2=36x^2-36xy+9y^2$

$(5-2xy)^2=25-20xy+4x^2y^2$
$(x^4-1)^2=x^8-2x^4+1$

$(x^5-y^3)^2=x^{10}-2x^5y^3+y^6$

Bài 3.

a. $(x+10)^2+(x-10)^2=x^2+20x+100+(x^2-20x+100)$

$=2x^2+200$

b. $(x-12)^2+(x+12)^2=x^2-24x+144+(x^2+24x+144)$

$=2x^2+288$

c. $(x+7)^2-(x-7)^2=[(x+7)+(x-7)][(x+7)-(x-7)]$

$=2x.14=28x$

Câu 5:

Áp dụng định lí cos: \(bc\cdot\cos A=bc\cdot\dfrac{b^2+c^2-a^2}{2bc}=\dfrac{b^2+c^2-a^2}{2}\)

Tương tự \(\Leftrightarrow ac\cdot\cos B=\dfrac{c^2+a^2-b^2}{2};ab\cdot\cos C=\dfrac{a^2+b^2-c^2}{2}\)

\(\Leftrightarrow P=\dfrac{a^2+b^2-c^2+b^2+c^2-a^2+c^2+a^2-b^2}{2}=\dfrac{a^2+b^2+c^2}{2}=\dfrac{4032}{2}=2016\)

1 You should not wear shorts when going to the pagoda

2 At Tet, our house is more beautifully decorated than during the year

3 Sitting in front of a computer all day can cause health problems

4 Snow White is very kind to people and animals

5 Hung King Temple festival has been a public holiday in VN since 2007

III

1 Last night, we were having dinner when the telephone rang

2 Life in the countryside has changed a lot over the past ten years

3 Nam doesn't mind listening to classical music

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