tinh nhanh
0,18 x 1250 + 9 x 45 x 2 + 3 x 425 x 0,6
giai ho mik voi dang can gap
Cho phep tinh : x/36 = 3/4 . khi do x = ?
A x=3 B x=4 C x=36 D x=27
giup minh voi minh dang can gap
tim gtnn , gtln của /x-can2/+/y-1/ voi /x/+/y/=5...ho mk voi,mk dang can gap
a) 92/9 + 13/5 - 56/9
b) 58/7 - (31/9 + 30/7)
c) 2/3 + 1/3 x 9/4 - 13/12
d) 41/8 - 7/4 : 11/5
e) 478/19 : 5/4 - 668/19 : 5/4
f) 32/21 x 49/45 : 16/22 x 15/33
g) 2020x2018+9 / 2019x2020-2011.
Giup minh voi minh dang can gap!!!
58/7 - (31/9 + 30/7)
= 58/7 - 31/9 - 30/7
= (58/7 - 30/7) - 31/9
= 28/7- 31/9
= 4 - 31/9 = 36/9 - 31/9
= 5/9
478/19÷(-5/4)-668/19÷(-5/4)
=(478/19-668/19):(-5/4)
=-10 . (-4/5)
=8
Tim x :
x/2 + x/6 + x/12+ ................................................ + x/90 = 9
giuy minh voi minh dang can gap
ta có: x/1.2+x/2.3+x/3.4+.....+x/9.10=9
x-x/2+x/2-x/3+x/3-......+x/9-x/10=9
x-x/10=9
=>x=10
4(x-3)-8x(x-3)=0
5x(x-7)-10(7-x)=0
2x-8=3x(x-4)
3x(x-5)=10-2x
6x(x-3)-3(3-x)=0
x^2(x+4)+9(-x-4)=0
giup voi dang can gap a
\(4\left(x-3\right)-8x\left(x-3\right)=0\\ \Leftrightarrow\left(x-3\right)\left(4-8x\right)=0\\ \Leftrightarrow2\left(1-2x\right)\left(x-3\right)=0\Leftrightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{1}{2}\end{matrix}\right.\\ 5x\left(x-7\right)-10\left(7-x\right)=0\\ \Leftrightarrow\left(x-7\right)\left(5x+10\right)=0\\ \Leftrightarrow5\left(x+2\right)\left(x-7\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=7\end{matrix}\right.\\ 2x-8=3x\left(x-4\right)\\ \Leftrightarrow2\left(x-4\right)-3x\left(x-4\right)=0\\ \Leftrightarrow\left(x-4\right)\left(2-3x\right)=0\Leftrightarrow\left[{}\begin{matrix}x=4\\x=\dfrac{2}{3}\end{matrix}\right.\\ 3x\left(x-5\right)=10-2x\\ \Leftrightarrow3x\left(x-5\right)+2\left(x-5\right)=0\\ \Leftrightarrow\left(3x+2\right)\left(x-5\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{2}{3}\\x=5\end{matrix}\right.\\ 6x\left(x-3\right)-3\left(3-x\right)=0\\ \Leftrightarrow\left(6x+3\right)\left(x-3\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=3\end{matrix}\right.\)
\(x^2\left(x+4\right)+9\left(-x-4\right)=0\\ \Leftrightarrow\left(x^2-9\right)\left(x+4\right)=0\\ \Leftrightarrow\left(x-3\right)\left(x+3\right)\left(x+4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\\x=-4\end{matrix}\right.\)
\(\left(4-8x\right)\left(x-3\right)=0\)
\(\left[{}\begin{matrix}4-8x=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\3\end{matrix}\right.\)
\(2\left(x-4\right)-3x\left(x-4\right)=0\)
\(\left(2-3x\right)\left(x-4\right)=0\)
\(\left[{}\begin{matrix}2-3x=0\\x-4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=4\end{matrix}\right.\)
tìm x,y thuộc z biết x^2.(y^+1)+y^2+24=12xy
giúp mik voi ,mik tick cho ,dang can gap
2.3^x=40.3^12 + 8 : 7^4
giup mik voi mik dang can gap
Cho 2 da thuc: P(x)=-3x^2+2x+1
Q(x)=-3x^2+x-2
a, Tinh Q(1/2)
b, x=1 co phai la nghiem cua P(x) ko?
c, Tim da thuc H(x)=P(x)-Q(x)
d, Tim tat ca cac gia tri cua x sao cho P(x)=Q(x)
GIUP MIK VOI MIK DANG CAN GAP
THANK YOU
\(a,Q\left(\dfrac{1}{2}\right)=-3.\left(\dfrac{1}{2}\right)^2+\dfrac{1}{2}-2\)
\(Q\left(\dfrac{1}{2}\right)=-3.\dfrac{1}{4}+\dfrac{1}{2}-2\)
\(Q\left(\dfrac{1}{2}\right)=-\dfrac{3}{4}+\left(-\dfrac{3}{2}\right)\)
\(Q\left(\dfrac{1}{2}\right)=-\dfrac{9}{4}\)
\(b,P\left(1\right)=-3.1^2+2.1+1\)
\(P\left(1\right)=-3.1+2+1\)
\(P\left(1\right)=-3+2+1\)
\(P\left(1\right)=0\)
Vậy x = 1 là nghiệm của đa thức P(x)
\(c,H\left(x\right)=\left(-3x^2+2x+1\right)-\left(-3x^2+x-2\right)\)
Câu c thì dễ rồi bn tự làm đi nha còn câu d thì mik chịu
tinh nhanh
( 1 + 3 + 5 + 7 + .... + 2003 + 2005) x ( 1212 x 27 - 2727 x 12)giup minh voi minh dang can gap lam
nhanh len nha
cam on truoc
( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x ( 1212 x 27 - 2727 x 12 )
= ( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x ( 32724 -32724 )
= ( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x 0
= 0
vu cao minh sai roi
de keu la tinh nhanh ma
Thì thế gọi là tính nhanh còn gì