uses crt;

var a:array[1..20]of integer;

i,n,t,dem:integer;

begin

clrscr;

for i:=1 to 20 do 

  begin

repeat

write('A[',i,']='); readln(a[i]);

until a[i]>0;

end;

t:=0;

for i:=1 to 20 do 

  t:=t+a[i];

writeln('Tong cac so trong mang la: ',t);

dem:=0;

for i:=1 to 20 do 

  if a[i] mod 2=0 then inc(dem);

writeln('Trong mang co ',dem,' so chan');

readln;

end.

uses crt;

var a:array[1..100]of integer;

i,n,min,dem:integer;

begin

clrscr;

write('Nhap n='); readln(n);

for i:=1 to n do

begin

write('A[',i,']='); readln(a[i]);

end;

min:=a[1];

for i:=1 to n do 

  if min>a[i] then min:=a[i];

dem:=0;

for i:=1 to n do 

  if min=a[i] then inc(dem);

writeln('So phan tu co gia tri nho nhat la: ',dem);

readln;

end.

Mn giúp e vơi e đang cần gấp!!!!!

Câu 1: 

uses crt;

var a:array[1..500]of integer;

i,n,t:integer;

begin

clrscr;

write('Nhap n='); readln(n);

for i:=1 to n do 

  begin

       write('A[',i,']='); readln(a[i]);

  end;

t:=0;

for i:=1 to n do 

  if (a[i]<0) and (a[i] mod 7=0) then t:=t+a[i];

writeln('Tong cac so am chia het cho 7 la: ',t);

readln;

end.

Câu 2: 

uses crt;

var c,a:array[1..10]of integer;

i,kt,j,dem:integer;

begin

clrscr;

for i:=1 to 10 do 

  begin

write('C[',i,']='); readln(c[i]);

end;

dem:=0;

for i:=1 to 10 do 

  if c[i]>1 then 

begin

kt:=0;

for j:=2 to c[i]-1 do 

  if c[i] mod j=0 then kt:=1;

if kt=0 then 

begin

inc(dem);

a[dem]:=c[i];

end;

end;

if dem=0 then writeln('Trong day khong co so nguyen to')

else begin

writeln('Cac so nguyen to trong day la: ');

for i:=1 to dem do

write(a[i]:4);

end;

readln;

end.

Câu 3: 

uses crt;

var d:array[1..200]of integer;

i,k,dem:integer;

begin

clrscr;

write('Nhap k='); readln(k);

for i:=1 to k do 

  begin

write('D[',i,']='); readln(d[i]);

end;

dem:=0;

for i:=1 to k do 

  if (a[i] mod 2=0) and (a[i]>=10) then inc(dem);

writeln('So phan tu chan co 2 chu so la: ',dem);

readln;

end.

1.

Program Tim_Max; 
Var A:Array[1..255] of Integer; 
i, n, Max: Integer; 
Begin 
Write('Nhap n: '); Readln(n); 
For i := 1 to n do 
Begin 
Write('Nhap phan tu A[',i,'] = '); Readln(A[i]); 
End; 
Max := A[1]; 
For i := 2 to n do if A[i]>Max then Max := A[i]; 
Write('Phan tu lon nhat la :',Max); 
Readln 
End.

2.

Uses Crt;
Type Mang = ARRAY[1..50] Of Integer;
Var A:Mang;
N,i,j,Tam:Integer;
Begin
{Nhập mảng}
Write('Nhap N='); Readln(N);
For i:=1 To N Do
Begin
Write('A[',i,']='); Readln(A[i]);
End;
{Sắp xếp}
For i:=1 To N-1 Do
For j:=i+1 To N Do
If A[i]>A[j] Then
Begin
Tam:=A[i]; A[i]:=A[j]; A[j]:=Tam;
End;
{In kết quả ra màn hình}
Writeln('Ket qua sau khi sap xep:');
For i:=1 To N Do Write(A[i]:5);
Readln;
End.

3.

Uses Crt;
Type Mang = ARRAY[1..50] Of Integer;
Var A:Mang;
N,i,x:Integer;

Function TimKiem(x, N: Integer; A:Mang):Integer;
Var i:Integer;
Begin
I:=1;
While (I <= N) and (X<>A[I]) do I:=I+1; {{{{tại sao lại phải làm như bước này, tại sao lại lấy i đi so sánh với N}}}}
If I <= N Then Timkiem:=I Else Timkiem:=0;
End;

Begin
{Nhập mảng}
Write(‘Nhap N=’); Readln(N);
For i:=1 To N Do
Begin
Write(‘A[‘,i,’]=’); Readln(A[i]);
End;
Write(‘Nhap X=’); Readln(x);
{Kết quả tìm kiếm}
If TimKiem(X,N,A)<>0 Then 
Writeln(‘Vi tri cua X trong mang la:’, TimKiem(X,N,A))
Else Writeln(‘X khong co trong mang.’);
Readln;
End.

câu 1 tham khảo cái này nhé

Uses Crt;

Type Mang = ARRAY[1..50] Of Integer;

Var A:Mang;

    N,i,Max:Integer;

Begin

    Write('Nhap N='); Readln(N);

    For i:=1 To N Do

        Begin

            Write('A[',i,']='); Readln(A[i]);

        End;

    Max:=A[1];

    For i:=2 To N Do

    If Max<A[i] Then Max:=A[i];

    Writeln('Phan tu lon nhat cua mang:', Max);

    Readln;

End.

Var a:array[1..20] of integer;

i,n,d:integer;

Begin

For i:=1 to 20 do

Begin

Write('Nhap phan tu thu ',i);readln(a[i]);

if a[i] = 3 then d:=d+1;

End;

Write('Co ',d,' chu so 3');

Readln

End.

uses crt;

var a:array[1..1000]of integer;

i,n,dem,t:integer;

begin

clrscr;

repeat

write('Nhap n='); readln(n);

until (0<n) and (n<=1000);

for i:=1 to n do 

begin

repeat

write('A[',i,']='); readln(a[i]);

until abs(a[i])<=1000;

end;

for i:=1 to n do 

  write(a[i]:4);

writeln;

dem:=0;

for i:=1 to n do 

  if a[i]=0 then inc(dem);

writeln('So phan tu bang 0 la: ',dem);

t:=0;

for i:=1 to n do 

  if a[i] mod 2=0 then t:=t+a[i];

writeln('Tong cac phan tu chan la: ',t);

readln;

end. 

uses crt;

var a:array[1..100]of integer;

i,n,kt,dem,j:integer;

begin

clrscr;

write('Nhap n='); readln(n);

for i:=1 to n do

begin

write('A[',i,']='); readln(a[i]);

end;

dem:=0;

for i:=1 to n do 

  if a[i]>1 then 

begin

kt:=0;

for j:=2 to trunc(sqrt(a[i])) do 

  if a[i] mod j=0 then 

begin

kt:=1;

break;

end;

if kt=0 then inc(dem);

end;

writeln('So phan tu la so nguyen to la: ',dem);

readln;

end.