d)5( x+4)=135-35

       x+4=100:5

       x    =20-4

      x     =16

d) 135 - 5 (x+4) = 35

5 (x+4) = 135 - 35

5 (x+4) = 100

(x+4) = 100 : 5

x + 4 = 20

x = 20 - 4

x = 16

e) 25 + 3 ( x - 8 ) = 106 

3  ( x - 8 ) = 106 - 25 

3  ( x - 8 ) = 81 

x - 8 = 81 : 3 

x - 8 = 27 

x = 27 + 8 

x = 35 

f) 2x – 49 = 5. 32

2x - 49 = 160

2x = 160 + 49

2x = 209

x = 209 : 2

x = 104,5

d)\(135-5\left(x+4\right)=35\)

⇔\(5\left(x+4\right)=100\)

⇔\(x+4=20\)

⇔\(x=16\)

e)\(25+3\left(x-8\right)=106\)

⇔\(3\left(x-8\right)=81\)

⇔\(x-8=27\)

⇔\(x=35\)

f)\(2x-49=5.32\)

⇔\(2x-49=160\)

⇔\(2x=209\)

⇔\(x=\dfrac{209}{2}\)

6: \(\Leftrightarrow x-8=20\)

hay x=28

a, 2.x + 7 = 15

   2x         = 8

   x           = 4

b, 25 – 3.(6 – x) = 22

            3.(6-x)    = 3

               6-x      = 1

                  x      = 5

c, [(2x – 11) : 3 + 1].5 = 20

      (2x-11) : 3+1         = 4

       (2x-11):3              = 3

        2x-11                  = 1

        2x                       = 12

        x                         = 6

  e, 2 . 3x = 10 . 312 + 8 . 274

      6x      = 3120 + 2192

      6x      = 5312

        x      = 5312/6

g, x – 12 = (–8) + (–17)

    x  - 12 = -25

    x         = -13

Lần sau tách nhỏ nội dung câu hỏi ra nha em, chứ trả lời thế này biếng lắm '^^ Chị làm chỉ mang tính tham khảo kết quả thôi, còn cụ thể thì em tách từng bước một ra he :>

a, \(2\cdot x+7=15\)

\(\Leftrightarrow2\cdot x=8\)

\(\Leftrightarrow x=4\)

Vậy x = 4.

b, \(25-3\cdot\left(6-x\right)=22\)

\(\Leftrightarrow3\cdot\left(6-x\right)=3\)

\(\Leftrightarrow6-x=1\)

\(\Leftrightarrow x=5\)

Vậy x = 5.

c, \(\left[\left(2x-11\right):3+1\right]\cdot5=20\)

\(\Leftrightarrow\left(2x-11\right):3+1=4\)

\(\Leftrightarrow\left(2x-11\right):3=3\)

\(\Leftrightarrow2x-11=9\)

\(\Leftrightarrow2x=20\)

\(\Leftrightarrow x=10\)

Vậy x = 10.

d, \(\left(25-2x\right)\cdot3:5-32=42\)

\(\Leftrightarrow\)\(\frac{3\cdot\left(25-2x\right)}{5}=74\)

\(\Leftrightarrow3\cdot\left(25-2x\right)=370\)

\(\Leftrightarrow25-2x=\frac{370}{3}\)

\(\Leftrightarrow2x=-\frac{295}{3}\)

\(\Leftrightarrow x\approx49\)

Vậy \(x\approx49\) .

e, \(2\cdot3x=10\cdot312+8\cdot274\)

\(\Leftrightarrow6x=5312\)

\(\Leftrightarrow x=5312:6\approx885\)

Vậy \(x\approx885\) .

g, \(x-12=\left(-8\right)+\left(-17\right)\)

\(\Leftrightarrow x-12=-25\)

\(\Leftrightarrow x=-25+12=-13\)

Vậy x = -13.

h, \(7-2x=18-3x\)

\(\Leftrightarrow-2x+3x=18-7\)

\(\Leftrightarrow x=11\)

Vậy \(x=11\) .

i, \(3\cdot\left(x+5\right)-x-11=24\)

\(\Leftrightarrow3x+15-x-11=24\)

\(\Leftrightarrow2x=24+11-15\)

\(\Leftrightarrow2x=20\)

\(\Leftrightarrow x=10\)

Vậy \(x=10\) .

Thanks mn ^v^

8: =>2x=210

hay x=105

a, 51

b, 60 

c, 245

a)x=37

b)x=-28

c)x=-48

d)x=15

tách ra

\(1\)) \(5-\left(10-x\right)=7\)
\(10-x=5-7\)
\(10-x=-2\)
\(x=10-\left(-2\right)\)
\(x=12\)

\(2\)) \(-32-\left(x-5\right)=0\)
\(x-5=-32-0\)
\(x-5=-32\)
\(x=-32+5\)
\(x=-27\)

1)10-x=5-7

x=10-(-2)

x=12

2)x+5=0+32

x=32-5

x=27

3) -12+2x-9+x=0

-12+(2x+x-9)=0

3x-9=0+12

3x=12+9

x=21:3

x=7

4) 15-x=1-11

x=15-(-10)

x=25

5) 4-(27+3)=x-9

4-30=x-9

-26+9=x

x=-17

a) Sai đề nên sửa luôn\(\left(2x-5\right)\left(4x^2+10x+25\right)-2x\left(2x+1\right)^2+8x^2+23x+125\)

=\(8x^3-125-2x\left(4x^2+4x+1\right)+8x^2+23x+125\)

= \(8x^3-125-8x^3-8x^2-2x+8x^2+23x+125\)

= \(21x\)

b) \(\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)-2^{32}\)

= \(\left(2-1\right)\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)-2^{32}\)

= \(\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)-2^{32}\)

= \(\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)-2^{32}\)

= \(\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)-2^{32}\)

= \(\left(2^{16}-1\right)\left(2^{16}+1\right)-2^{32}\)

= \(2^{32}-1-2^{32}=-1\)