tính [(-703+73]:1+3+5+7+9+...+2008
Tính tổng:E=1-3+5-7+...+2013-2015
F=1+2-3-4+5+6-7-8+9+10-....+2006-2007-2008+2009
E = 1 - 3 + 5 - 7 + ... + 2013 - 2015 (1008 số hạng)
= (1 - 3) + (5 - 7) + ... + (2013 - 2015) (504 cặp)
= -2 + (-2) + ... + (-2) (504 số hạng - 2)
= 504.(-2) = -1008
F = 1 + 2 - 3 - 4 + .... + 2006 - 2007 - 2008 + 2009 (2009 SỐ HẠNG)
= 1 + (2 - 3) + (-4 + 5) + .... + (2006 - 2007) + (-2008 + 2009) (1004 cặp số)
= 1 + [(-1) + 1 + .... + (-1) + 1] (1005 số hạng)
= 1
E = 1 - 3 + 5 - 7 + .. + 2013 - 2015
E= ( 1 - 3 ) + ( 5 - 7 ) + ... + ( 2013 - 2015 )
E = - 2 + ( -2 ) + ... + (-2 )
E = -2 x 504
E= -1008
F = 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + 10 - ... + 2006 -2007 - 2008 + 2009
F = ( 1 - 3 ) + ( 2 - 4 ) + ( 5 - 7 ) + ( 6 - 8 ) + ... + (2005 - 2007 ) + ( 2006 - 2008 ) + 2009
F = -2 + ( -2 ) + ( - 2 ) + ( - 2 ) + ... + ( - 2 ) + ( - 2 ) +2009
F = ( - 2 ) x 1004 + 2009
F = -2008 + 2009
F = 1
Tính toorng :1+2-3-4+5+6-7-8+9+...+2006-2007-2008+2009+2010
=1+(2-3-4+5)+(6-7-8+9)+...+(2006-2007-2008+2009)+2010
=1+0+0+...+0+2010
=2011
Ta thấy tổng của 4 số bắt đầu từ 2 thì đều =0 (2-3-4+5=0,6-7-8+9=0)Ta đặt A=\(1+2-3-4+5+6-7-8+9+...+2006-2007-2008+2009+2010\)
= \(1+\left(2-3-4+5\right)+\left(6-7-8+9\right)+...+\left(2006-2007-2008+2009\right)+2010=1+0+0+...+0+2010=2011\)
Tính tổng sau:
C= 1-2+3+4-5-6+7+8-9-...+2007+2008-2009-2010
tính: 1+2-3-4+5+6-7-8+9+10-...+2006-2007-2008+2009
= 1+(2-3-4+5)+(6-7-8+9)+ ... +(2006-2007-2008+2009)
=1+0+0+ ... +0
=1
Tính hợp lí:
S=1-2+3+4-5-6+7+8-9-...-2006+2007+2008-2009
S = 1 - 2 + 3 + 4 - 5 - 6 + 7 + 8 - 9 + ... - 2006 + 2007 + 2008 - 2009
= 1 + (-2 + 3 + 4 - 5) + (-6 + 7 + 8 - 9) + ... + (-2006 + 2007 + 2008 - 2009)
= 1 + 0 + 0 + ... + 0
= 1
Tính:
1, 7/36- 8/-9 + -2/3
2, -1/2 + 3/7 - 1/9 + -7/18 + 4/7
3, -10/3 + 13/10 - 1/6 + 1/10
4, 10/17- 5/13 - (-7/17) - 8/13 + 11/25
\(1.\) \(\dfrac{7}{36}-\dfrac{8}{-9}+\dfrac{-2}{3}=\dfrac{7}{36}+\dfrac{8}{9}-\dfrac{2}{3}=\dfrac{7+32-24}{36}=\dfrac{5}{12}.\)
\(2.\) \(\dfrac{-1}{2}+\dfrac{3}{7}-\dfrac{1}{9}+\dfrac{-7}{18}+\dfrac{4}{7}=\dfrac{-9-2-7}{18}+\dfrac{4+3}{7}=\dfrac{-18}{18}+\dfrac{7}{7}=-1+1=0.\)
\(3.\) \(-\dfrac{10}{3}+\dfrac{13}{10}-\dfrac{1}{6}+\dfrac{1}{10}=\dfrac{13+1}{10}+\dfrac{-20-1}{6}=\dfrac{14}{10}+\dfrac{-21}{6}=\dfrac{7}{5}-\dfrac{7}{2}=-\dfrac{21}{10}.\)
\(4.\) \(\dfrac{10}{17}-\dfrac{5}{13}-\left(-\dfrac{7}{17}\right)-\dfrac{8}{13}+\dfrac{11}{25}=\dfrac{10+7}{17}+\dfrac{-5-8}{13}+\dfrac{11}{25}=\dfrac{17}{17}-\dfrac{13}{13}+\dfrac{11}{25}=\dfrac{11}{25}.\)
Tính:
1, 7/36- 8/-9 + -2/3
2, -1/2 + 3/7 - 1/9 + -7/18 + 4/7
3, -10/3 + 13/10 - 1/6 + 1/10
4, 10/17- 5/13 - (-7/17) - 8/13 + 11/25
1: \(=\dfrac{7}{36}+\dfrac{32}{36}+\dfrac{-24}{36}=\dfrac{15}{36}=\dfrac{5}{12}\)
2: \(=\left(-\dfrac{1}{2}-\dfrac{1}{9}-\dfrac{7}{18}\right)+\dfrac{3}{7}+\dfrac{4}{7}\)
\(=\dfrac{-9-2-7}{18}+1=-1+1=0\)
3: \(=\left(-\dfrac{10}{3}-\dfrac{1}{6}\right)+\dfrac{14}{10}\)
\(=-\dfrac{21}{6}+\dfrac{14}{10}=\dfrac{-7}{2}+\dfrac{14}{10}=\dfrac{-35+14}{10}=-\dfrac{21}{10}\)
4: \(=\left(\dfrac{10}{17}+\dfrac{7}{17}\right)-\left(\dfrac{5}{13}+\dfrac{8}{13}\right)+\dfrac{11}{25}=\dfrac{11}{25}\)
Tính
7-8+9-10+11-12+...+2009-2010.
-1-2-3-4--...-2008-2009-2010.
1-3-5+7-9-11+...+1000-1002-1004
Số số hạng của dãy:(2010-7):1+1=2004(số)
Vậy có tất cả:2004:2=1002(cặp)
A=7-8+9-10+11-12+...+2009-2010
A=(7-8)+(9-10)+(11-12)+...+(2009-2010)
A=-1+(-1)+(-1)+...+(-1)
Vậy A=(-1)*1002=-1002
Tính tổng:1+2-3-4+5+6-7-8+9+10-...+2006-2007-2008+2009.