b: \(\Leftrightarrow x\left(x-25\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=25\end{matrix}\right.\)

c: \(\Leftrightarrow\left(x-1\right)\left(5x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{1}{5}\end{matrix}\right.\)

\(b,\Leftrightarrow x\left(x-25\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=25\end{matrix}\right.\\ c,\Leftrightarrow\left(x-1\right)\left(5x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{1}{5}\end{matrix}\right.\)

Link : Tìm x biết 2x^2+3(x-1)(x+1)=5x(x+1)

\(2x^2-3\left(1-x\right)\left(x+1\right)=5x\left(x+1\right)\\ \Leftrightarrow2x^2+3\left(x^2-1\right)=5x^2+5x\\ \Leftrightarrow2x^2+3x^2-3=5x^2+5x\\ \Leftrightarrow x=-\dfrac{3}{5}\\ \Rightarrow S=\left\{-\dfrac{3}{5}\right\}\)

Ta có: \(2x^2-3\left(1-x\right)\left(x+1\right)=5x\left(x+1\right)\)

\(\Leftrightarrow2x^2+3x^2-3-5x^2-5x=0\)

\(\Leftrightarrow-5x=3\)

hay \(x=-\dfrac{3}{5}\)

a) 5x(x - 1) = x - 1

    5x(x - 1) - (x - 1) = 0

    (x - 1) (5x - 1) = 0

TH1: x - 1 = 0

        x       = 1

TH2: 5x - 1 = 0

         5x      = 1

          x       = 1/5

Vay x = 1 hoac x = 1/5.

b) 2(x + 5) - x² - 5x = 0

    2(x + 5) - x(x + 5) = 0

    (x + 5) (2 - x) = 0

TH1: x + 5 = 0

        x        = -5

TH2: 2 - x = 0

              x  = 2

Vay x = -5 hoac x = 2

a, x = 1

b , x = -5 hoặc x = 2

- Help Me :((

\(25\left(x+3\right)^2+\left(1-5x\right)\left(1+5x\right)=0\)

\(25\left(x^2+6x+9\right)+1-25x^2=0\)

\(25x^2+150x+225+1-25x^2=0\)

\(150x=-226\)

\(x=-\frac{113}{75}\)

25 ( x + 3 )² + ( 1 - 5x )( 1 + 5x ) = 0

25 ( x² + 6x + 9 ) + 1 + 5x - 5x - 25x² = 0

25x² + 150x + 225 + 1 + 5x - 5x - 25x² = 0

150x + 226 = 0

150x = -226

x = -226/150

`5x(x-3)=(x-2)(5x-1)-5`

`\rightarrow 5x^2-15x= [x(5x-1)-2(5x-1)-5]`

`\rightarrow 5x^2-15x=(5x^2-x-10x+2-5)`

`\rightarrow 5x^2-15x=5x^2-11x-3`

`\rightarrow 5x^2-15x-5x^2+11x+3=0`

`\rightarrow -4x+3=0`

`\rightarrow 4x=3`

`\rightarrow x=`\(\dfrac{3}{4}\)

Vậy, `x=`\(\dfrac{3}{4}\)

Còn biến `y` thì mình k thấy bạn nhé!

Cho mk sửa lại từ dòng thứ 6 (tính cả đề)

`\rightarrow -4x+3=0`

`\rightarrow -4x=-3`

`\rightarrow x=-3/-4`

`\rightarrow x=3/4`

Vậy, `x=3/4`

a) \(5x\left(x-1\right)=x-1\)

\(\Rightarrow5x\left(x-1\right)-\left(x-1\right)=0\)

\(\Rightarrow\left(x-1\right).\left(5x-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x-1=0\\5x-1=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=1\\x=\frac{1}{5}\end{cases}}\)

Vậy \(x=1\) hoặc \(x=\frac{1}{5}\)

b) \(2\left(x+5\right)-x^2-5x\)

\(\Rightarrow2\left(x+5\right)-x\left(x+5\right)\)

\(\Rightarrow\left(x+5\right).\left(2-x\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+5=0\\2-x=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-5\\x=2\end{cases}}\)

Vậy \(x=-5\)hoặc \(x=2\)

a, \(-4x+5+2x-1=3\Leftrightarrow-2x=-1\Leftrightarrow x=\dfrac{1}{2}\)

b, \(-2x+2=2\Leftrightarrow x=0\)

c, \(-2x-6=-8\Leftrightarrow x=1\)

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