5x(x – 1) = x – 1
⇔ 5x(x – 1) – (x – 1) = 0
⇔ (5x – 1)(x – 1) = 0
⇔ 5x – 1 = 0 hoặc x – 1 = 0
• x – 1 = 0 ⇔ x = 1
• 5x – 1 = 0 ⇔ x = 1/5
Vậy x = 1 hoặc x = 1/5.
Tìm x , biết
a) x (5x - 2y) + 2x ( x - 1) = 15
b) x^2 - 25x = 0
c) 5x (x - 1) = x - 1
Câu 3: Tìm x, biết:
a) 5x( x-1)= x-1
b) 2(x+5)- x²- 5x= 0
tìm x biết 25(x+3)^2+(1-5x)(1+5x)=0
Tìm x biết:
a) 5x(x-1)=x-1
b) 2(x+5)-x2-5x=0
tìm x biết
a) (5x-1)2-(5x-4)(5x+4)=7
b)5x2+4xy+4y2+4x+1=0
c)(x+2)3-x(x-1)(x+1)=6x2+21
tìm x ,biết
a, x^2 -4x =12
b, ( 5x+1)^2 - (5x -3)(5x+3)=30
c, (x-1) ( x^2 +x +1 ) + x(x +2) (2-x)=5
d, 5x(x-3)^2 -5 (x-1)^3 +15 (x+4) (x-4) =5
Tìm x biết:
a) 5x(x-1) = x-1.
b) 2(5+x) - x2 - 5x=0
Tìm x , biết
5x(x-1)=x-1
2(x+5)-x^2-5x=0
(x-3)^2 -(x+5)^2
tìm x biết
(5x+1)^2 - (5x+3).(5x-3)=30
(x+3).(x^2-3x+9)-x.(x-2).(x+2)=15
