=x(x^3+7x^2+14x+14+4)

=x(x^3+7x^2+14x+18)

   x⁴+7x³+14x²+14x+4

=x⁴+7x³+4x²+10x²+14x+4

=(x⁴+4x²+4)+(7x³+14x)+10x²

=(x²+2)²+7x(x²+2)+10x²

=(x²+2)²+2x(x²+2)+5x(x²+2)+10x²

=(x²+2)(x²+2+2x)+5x(x²+2+2x)

=(x²+2+2x)(x²+2+5x)

\(x^4+7x^3+14x^2+14x+4\)

\(=x^4+x^3+6x^3+6x^2+8x^2+8x+4x+4\)

\(=x^3\left(x+1\right)+6x^2\left(x+1\right)+8x\left(x+1\right)+4\left(x+1\right)\)

\(=\left(x+1\right)\left(x^3+6x^2+8x+4\right)\)

a, \(x^4+6x^3+7x^2-6x+1\)

\(=x^4-2x^2+1+6x^3+9x^2+6x\)

\(=\left(x^2-1\right)^2+6x\left(x^2-1\right)+9x^2\)

\(=\left(x^2-1+3x\right)^2\)

b, \(x^4-7x^3+14x^2-7x+1\)

\(=x^4+2x^2+1+7x^3+12x^2-7x\)

\(=\left(x^2+1\right)^2-7x\left(x^2+1\right)+12^2\)

\(=\left(x^2-1+3x\right)^2\)

c, \(12x^2-11x-36\)

\(=12x^2-27x+16x-36\)

\(=3x\left(4x-9\right)+4\left(4x-9\right)\)

\(=\left(4x-9\right)\left(3x+4\right)\)

\(a,=7xy\left(x^2-2xy+y^2\right)=7xy\left(x-y\right)^2\\ b,=3x\left(x-y\right)-5\left(x-y\right)=\left(3x-5\right)\left(x-y\right)\\ c,=x^2+3x+4x+12=\left(x+3\right)\left(x+4\right)\)

\(=x^2+8x-x-8=x\left(x+8\right)-\left(x+8\right)=\left(x+8\right)\left(x-1\right)\)

\(x^2+8x-x-8=8\left(x-1\right)+x\left(x-1\right)=\left(8+x\right)\left(x-1\right)\)

   x²+7x-8
= x²-x+8x-8
= (x²-x)+(8x-8)
= x(x-1)+8(x-1)
= (x-1)(x+8)

b) 3x⁴-3x³+9x³-9x²-24x²+24x-48x+48

=3x³(x-1)+9x²(x-1)-24x(x-1)-48(x-1)

=(x-1)(3x³+9x²-24x-48)

=3(x-1)(x³+3x²-8x-16)

Vô đây xem: bài 1:phân tích đa thức thành nhân tửa)7x^3y-14x^2y+7xy^3b)3x^2-3xy-5x+5yc)x^2+7x+12giúp mình với  - Hoc24