chung minh rang x,y thuoc Z va (5x-2y)x(2x-5y) chia het cho 7 thi tich (5x-2y)x(2x-5y) co nhieu hon 2 uoc chinh phuong
chung minh rang x,y thuoc Z va (5x-2y)x(2x-5y) chia het cho 7 thi tich (5x-2y)x(2x-5y) co nhieu hon 2 uoc chinh phuong
1. Chung minh rang: neu x, y thuoc N thi x+2y chia het cho 5 <=> 3x-4y chia het cho 5.
2. Chung minh: 2x+3y chia het cho 17 <=> 9x+5y chia het cho 17.
chung minh rang 9x+5y chia het cho 11<=>2x+3y chia het cho 11 voi x va y thuoc N
cho so nguyen to p va cac so duong x,y thoa man 4x^2-3xy-y^2-p(3x+2y)=2p^2 CHUNG MINH RANG 5x-1 la so chinh phuong
Có: \(4x^2-3xy-y^2-p\left(3x+2y\right)=2p^2\Leftrightarrow\left(4x+y\right)\left(x-y\right)-p\left(3x+2y\right)=2p^2\)\(\Leftrightarrow\left[\left(3x+2y\right)+\left(x-y\right)\right]\left(x-y\right)-p\left(3x+2y\right)=2p^2\)\(\Leftrightarrow\left(3x+2y\right)\left(x-y\right)-p\left(3x+2y\right)+\left(x-y\right)^2-p^2=p^2\)\(\Leftrightarrow\left(3x+2y\right)\left(x-y-p\right)+\left(x-y-p\right)\left(x-y+p\right)=p^2\)\(\Leftrightarrow\left(x-y-p\right)\left(4x+y+p\right)=p^2=1.p^2\)
Do \(4x+y+p>x-y-p\)nên \(\hept{\begin{cases}x-y-p=1\left(1\right)\\4x+y+p=p^2\left(2\right)\end{cases}}\)(Do p là số nguyên tố)
Lấy (1) + (2), ta được: \(5x=p^2+1\Rightarrow5x-1=p^2\)(là số chính phương, đpcm)
PP nhóm hạng tử chung
1)2x+2y-x(x+y)
2)5x^2-5xy-10x+10y
3)4x^2+8xy-3x-6y
4)2x^2+2y^2-x^2z+z-y^2z-2
5)x^2+xy-5x-5y
6)x(2x-7)-4x+14
7)x^2-3x+xy-3y
1) 2x + 2y - x(x+y)
= 2(x + y) - x(x + y)
= (2 - x)(x + y)
2/ 5x2 - 5xy -10x + 10y
= 5x(x - y) - 10(x - y)
= (5x - 10(x - y)
3/ 4x2 + 8xy - 3x - 6y
= 4x(x + 2y) - 3(x + 2y)
= (4x - 3)(x + 2y)
1) 2x + 2y - x(x + y)
= 2(x + y) - x(x + y)
= (2 - x)(x + y)
2) 5x2 - 5xy - 10x + 10y
= 5x(x - y) - 10(x - y)
= (5x - 10)(x - y)
= 5(x - 2)(x - y)
3) 4x2 + 8xy - 3x - 6y
= 4x(x + 2y) - 3(x + 2y)
= (4x - 3)(x + 2y)
4) 2x2 + 2y2 - x2z + z - y2z - 2
= 2(x2 + y2 - z(x2 + y2) - (2 - z)
= (2 - z)(x2 + y2) - (2 - z)
= (2 - z)(x2 + y2)
5) x2 + xy - 5x - 5y
= x(x + y) - 5(x + y)
= (x - 5)(x + y)
6) x(2x - 7) - 4x + 14
= x(2x - 7) - 2(2x - 7)
= (x - 2)(2x - 7)
7)x2 - 3x + xy - 3y
= x(x + y) - 3(x + y)
= (x - 3)(x + y)
5/ x2 + xy - 5x - 5y
= x(x + y) - 5(x + y)
= (x - 5)(x + y)
6/ x(2x - 7) - 4x + 14
= 2x2 - 7x - 4x + 14
= (2x2 - 4x) - (7x - 14)
= 2x(x - 2) -7(x - 2)
= (2x - 7)(x - 2)
7/ x2 - 3x + xy - 3y
= x(x - 3) + y(x - 3)
= (x + y)(x - 3)
1------- cho x,y thuoc Z .Cm rang 5x+ 47y la Boi cua 17 khi va chi khi x+6y la boi cua 17
2------- chung minh rang voi moi a thuoc Z ta co
a- (a -1)(a-2)+12 ko chia het cho 9
b- (a+2)(a+9)+21 ko chia het cho 49
Chung minh rang neu x,y thuocZ: 2x +3y va 9x+5y deu chia het cho 17
vì tổng của chúng chia hết cho 17
9x+5y = 17x - 8x + 17y - 12y = 17(x+y) - 4(2x+3y)
chia hết cho 17 khi và chỉ khi 2x+3y chia hết cho 17
=>Nếu 2x+3y chia hết cho 17 thì 9x+5y cũng chia hết cho 17
Cho x+y+z=0. Chung minh rằng (2011x/xy+2011x+2011) +(y/yz+y+2011) +(z/xz+z+1) =1 b, cho x, y thỏa mãn đẳng thức 5x^2+5y^2+8xy-2x+2y+2=0 Tính giá trị của M=(x+y) ^2015+(x-2)^2016+(y+1) ^2017
b: 5x^2+5y^2+8xy-2x+2y+2=0
=>4x^2+8xy+4y^2+x^2-2x+1+y^2+2y+1=0
=>(x-1)^2+(y+1)^2+(2x+2y)^2=0
=>x=1 và y=-1
M=(1-1)^2015+(1-2)^2016+(-1+1)^2017=1
Chung minh phuong chinh 2x^2-5y^2=7 khong co nguyen nguyen
ai lam duoc em tich cho luon