(2x - 5) +17=8
Tìm x
15-(x-4)=8
14-(25-8)=x-(19-7)
5x-(-17)=2
(2x-5)+17=6
|x+5|=12
|2x-1|-5=8
\(15-\left(x-4\right)=8\)
\(x-4=15-8\)
\(x-4=7\)
\(x=7+4\)
\(x=11\)
x=11
x=9
x=-3
x=-3
x=7 hoặc x=-17
x=7 hoặc x=-6
\(14-\left(25-8\right)=x-\left(19-7\right)\)
\(14-17=x-12\)
\(x-12=-3\)
\(x=-3+12\)
\(x=9\)
(2,5-3x):5/3=(8/5+2x):(-8/17)
Giải phương trình
1) 2x ( x – 3 ) + 5 ( x – 3 ) = 0
2) ( x2 – 4 ) – ( x – 2 ) ( 3 – 2x ) = 0
3) ( 2x – 1 )2 – ( 2x + 5 )2 = 11
4) ( 2x + 1 )2 ( 3x – 5 ) = 4x2 – 1
5) 3x2 – 5x – 8 = 0
6) ( 2x + 1 )2 ( 3x – 5 ) = 4x2 – 1
7) 3x2 – 5x – 8 = 0
8) \(\left|x-5\right|=3\)
9) \(\left|2x-5\right|=3-x\)
10) \(\left|2x+1\right|=\left|x-1\right|\)
11) \(\dfrac{5x+2}{6}-\dfrac{8x-1}{3}=\dfrac{4x+2}{5}-5\)
12) \(\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=2x+\dfrac{5}{3}\)
1) Ta có: \(2x\left(x-3\right)+5\left(x-3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(2x+5\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{5}{2}\end{matrix}\right.\)
2) Ta có: \(\left(x^2-4\right)-\left(x-2\right)\left(3-2x\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(x+2\right)+\left(x-2\right)\left(2x-3\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(3x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{1}{3}\end{matrix}\right.\)
3) Ta có: \(\left(2x-1\right)^2-\left(2x+5\right)^2=11\)
\(\Leftrightarrow4x^2-4x-1-4x^2-20x-25=11\)
\(\Leftrightarrow-24x=11+1+25=37\)
hay \(x=-\dfrac{37}{24}\)
5) Ta có: \(3x^2-5x-8=0\)
\(\Leftrightarrow3x^2+3x-8x-8=0\)
\(\Leftrightarrow3x\left(x+1\right)-8\left(x+1\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(3x-8\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=\dfrac{8}{3}\end{matrix}\right.\)
8) Ta có: \(\left|x-5\right|=3\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)
10) Ta có: \(\left|2x+1\right|=\left|x-1\right|\)
\(\Leftrightarrow\left[{}\begin{matrix}2x+1=x-1\\2x+1=1-x\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x-x=-1-1\\2x+x=1-1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=0\end{matrix}\right.\)
tim x biết ( 2,5 -3x ) : 5/3=( 8/5+2x ) : -8/17
2x-8+17=5+x
\(2x-8+17=5+x\Rightarrow2x+9=5+x\Rightarrow2x-x=5-9\Rightarrow x=-4\)
tìm x
a,3 4/5 : 8/5 = 0,25 :x
b, 2x+3/24 = 3x-1/32
c, 13x-2/2x+5=76/17
a) \(3\dfrac{4}{5}:\dfrac{8}{5}=0,25:x\)
\(\Rightarrow\dfrac{19}{5}.\dfrac{5}{8}=\dfrac{x}{4}\)
\(\Rightarrow\dfrac{x}{4}=2\Rightarrow x=8\)
b) \(2x+\dfrac{3}{24}=3x-\dfrac{1}{32}\)
\(\Rightarrow x=\dfrac{1}{8}+\dfrac{1}{32}=\dfrac{5}{32}\)
c) \(\dfrac{13x-2}{2x+5}=\dfrac{76}{17}\)
\(\Rightarrow221x-34=152x+380\)
\(\Rightarrow69x=414\Rightarrow x=6\)
(2,5-3x) : 1 và 2/3 = (8/5+2x) : (-8/17)
3\5 .(1-5x) -5\4 .(2x-8)=5x +17\2
x= 1/5 là 0.2 mình trả lời trc k cho mình vs
tìm 2 số nguyên x và y sao cho ( 2x - 1 ) . ( y - 8 ) = 17
tìm 2 số nguyên x va y sao cho (2x - 5 ) . ( y -6 ) = 17
a) 2x - 1 = 1 và y - 8 =17 hoặc 2x - 1 = 17 và y - 8 =1
=> x = 1 và y = 25 hoặc x = 9 và y = 9
b) 2x - 5 = 1 và y - 6 =17 hoặc 2x - 5 = 17 và y - 6 =1
=> x = 3 và y = 23 hoặc x = 11 và y = 7
nên 2x-1 thuôc Ư ( 17)
y-8 thuộc Ư (17)
liệt kê Ư(17) = 17 , 1 ,-1,-17
rồi tìm x, y
ý kia tương tự