a) 89 + 10 x 2 = 89 + 20

                   = 109

b) 25 x 2 + 78 = 50 + 78

                   = 128

c) 46 + 77 x 2 = 46 + 14

                   = 60

d) 35 x 2 + 90 = 70 + 90

                   = 160

B

C

A

Hai góc 15⁰ và 75⁰ phụ nhau nên sin 75⁰ = cos 15⁰

Hai góc 20⁰ và 110⁰ hơn kém nhau 90⁰ nên cos 110⁰ = - sin 20⁰

Do đó,  S = sin 2 15 ° + cos 2 20 ° + sin 2 75 ° + cos 2 110 °

= ​ sin 2 15 ° + cos 2 20 + cos 2 15 ° + − sin 20 ° 2 ​​ = ​ sin 2 15 ° + cos 2 15 ° + sin 2 20 ° + cos 2 20 ° ​ = 2

ĐÁP ÁN C

a,23+45+67+89                             

=68+67+89      

=135+89

=224

b,345-123+700+8

=222+700+8

=922+8

=930

c,7x8x9x10+345678:0,5

=5040+691356

=696396

a: 

b: \(B=3-sin^290^0+2\cdot cos^260^0-3\cdot tan^245^0\)

\(=3-1+2\cdot\left(\dfrac{1}{2}\right)^2-3\cdot1^2\)

\(=2-3+2\cdot\dfrac{1}{4}=-1+\dfrac{1}{2}=-\dfrac{1}{2}\)

c: \(C=sin^245^0-2\cdot sin^250^0+3\cdot cos^245^0-2\cdot sin^240^0+4\cdot tan55\cdot tan35\)

\(=\left(\dfrac{\sqrt{2}}{2}\right)^2+3\cdot\left(\dfrac{\sqrt{2}}{2}\right)^2-2\cdot\left(sin^250^0+sin^240^0\right)+4\)

\(=\dfrac{1}{2}+3\cdot\dfrac{1}{2}-2+4\)

\(=2-2+4=4\)

tách ra thành mấy dòng ik

khó nhìn quá

Câu 3: C

Câu 4: B

\(A=\left(1-\frac{1}{2}\right)+\left(1-\frac{1}{6}\right)+\left(1-\frac{1}{12}\right)+....+\left(1-\frac{1}{90}\right)+\left(1-\frac{1}{110}\right)+\frac{10}{11}\)

\(=10-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{10.11}\right)+\frac{10}{11}=10-\left(1-\frac{1}{11}\right)+\frac{10}{11}=10\)

a: Ta có: \(-\left(x+5\right)^2\le0\forall x\)

\(\Leftrightarrow-\left(x+5\right)^2+2021\le2021\forall x\)

Dấu '=' xảy ra khi x=-5